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A gas sample occupying a volume of \(25.6 \mathrm{~mL}\) at a pressure of 0.970 atm is allowed to expand at constant temperature until its pressure reaches 0.541 atm. What is its final volume?

Short Answer

Expert verified
The final volume is approximately 45.9 mL.

Step by step solution

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01

Identify the Given and Required Information

We are given the initial volume \( V_1 = 25.6 \; \mathrm{mL} \), the initial pressure \( P_1 = 0.970 \; \mathrm{atm} \), and the final pressure \( P_2 = 0.541 \; \mathrm{atm} \). We need to find the final volume \( V_2 \).
02

Apply Boyle's Law

According to Boyle's Law, for a constant temperature, the product of pressure and volume is constant: \( P_1 \times V_1 = P_2 \times V_2 \). We can use this relationship to find the unknown final volume \( V_2 \).
03

Rearrange Boyle's Law to Solve for Final Volume

Solve for \( V_2 \) by rearranging the equation: \[ V_2 = \frac{P_1 \times V_1}{P_2} \].
04

Substitute the Known Values into the Equation

Insert the known values into the rearranged equation:\[ V_2 = \frac{0.970 \times 25.6}{0.541} \].
05

Calculate the Final Volume

Perform the calculation:\[ V_2 = \frac{24.832}{0.541} \approx 45.9 \; \mathrm{mL} \].

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Laws
Gas laws are fundamental principles in chemistry that relate the properties of gases, such as pressure, volume, and temperature. These laws allow us to predict and understand how gases behave under various conditions. Boyle's Law, Charles's Law, and Avogadro's Law are some of the main gas laws which help describe these relationships. For instance, Boyle's Law specifically deals with how pressure and volume of a gas interact while keeping the temperature constant. When studying gas laws, we assume gases exhibit ideal behavior, meaning they follow these laws perfectly under normal conditions.
  • Boyle's Law: Describes the pressure-volume relationship at constant temperature.
  • Charles's Law: Relates volume and temperature, holding pressure constant.
  • Avogadro's Law: Connects volume and quantity of gas molecules, assuming constant temperature and pressure.
Understanding these laws is crucial for predicting how changes in one property of a gas will affect the others. It's important to remember that while these laws are accurate under many conditions, real gases might diverge slightly due to non-ideal interactions.
Pressure-Volume Relationship
The pressure-volume relationship of gases, as outlined in Boyle’s Law, demonstrates that the pressure of a gas is inversely proportional to its volume, provided the temperature remains constant. This principle means that if you decrease the volume of a gas, its pressure increases, and vice versa.
  • Mathematically, this relationship is represented as: \( P_1 \times V_1 = P_2 \times V_2 \).
  • This means when one multiplies the initial pressure and volume, it should be equal to the product of the final pressure and volume.
In practical terms, imagine a balloon: squeezing it reduces the volume inside, which, according to Boyle's Law, increases the pressure the gas exerts internally.

It's also important to note that this relationship assumes no other factors alter the gas's behavior, such as temperature or external pressures. This direct relationship assists in many real-world applications, from understanding balloons to optimizing engines.
Ideal Gas Behavior
Ideal gas behavior is an assumption where we consider gas molecules to have perfectly elastic collisions and no volume or intermolecular forces. This simplification allows for the easy application of gas laws. In reality, ideal gases don't exist, but many gases behave almost ideally under typical conditions like standard temperature and pressure (STP).
  • Ideal gases obey all gas laws precisely, making calculations straightforward.
  • Real gases show slight deviations, especially at extremely high pressures or low temperatures due to intermolecular attractions and volumes.
In the exercise solution, we assumed ideal gas behavior to apply Boyle’s Law effectively. This is a valid approximation in most scenarios, as the small deviations typically do not significantly affect outcomes at common conditions. Maintaining this assumption simplifies solving gas-related problems, ensuring the results remain reasonably accurate.

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Most popular questions from this chapter

Acidic oxides such as carbon dioxide react with basic oxides like calcium oxide \((\mathrm{CaO})\) and barium oxide \((\mathrm{BaO})\) to form salts (metal carbonates). (a) Write equations representing these two reactions. (b) A student placed a mixture of \(\mathrm{BaO}\) and \(\mathrm{CaO}\) of combined mass \(4.88 \mathrm{~g}\) in a \(1.46-\mathrm{L}\) flask containing carbon dioxide gas at \(35^{\circ} \mathrm{C}\) and \(746 \mathrm{mmHg}\). After the reactions were complete, she found that the \(\mathrm{CO}_{2}\), pressure had dropped to \(252 \mathrm{mmHg}\). Calculate the percent composition by mass of the mixture. Assume that the volumes of the solids are negligible.

(a) What volume of air at 1.0 atm and \(22^{\circ} \mathrm{C}\) is needed to fill a \(0.98-\mathrm{L}\) bicycle tire to a pressure of \(5.0 \mathrm{~atm}\) at the same temperature? (Note that the 5.0 atm is the gauge pressure, which is the difference between the pressure in the tire and atmospheric pressure. Before filling, the pressure in the tire was \(1.0 \mathrm{~atm} .\) ) (b) What is the total pressure in the tire when the gauge pressure reads 5.0 atm? (c) The tire is pumped by filling the cylinder of a hand pump with air at 1.0 atm and then, by compressing the gas in the cylinder, adding all the air in the pump to the air in the tire. If the volume of the pump is 33 percent of the tire's volume, what is the gauge pressure in the tire after three full strokes of the pump? Assume constant temperature.

The gas laws are vitally important to scuba divers. The pressure exerted by \(33 \mathrm{ft}\) of seawater is equivalent to 1 atm pressure. (a) A diver ascends quickly to the surface of the water from a depth of \(36 \mathrm{ft}\) without exhaling gas from his lungs. By what factor will the volume of his lungs increase by the time he reaches the surface? Assume that the temperature is constant. (b) The partial pressure of oxygen in air is about \(0.20 \mathrm{~atm}\). (Air is 20 percent oxygen by volume.) In deep-sea diving, the composition of air the diver breathes must be changed to maintain this partial pressure. What must the oxygen content (in percent by volume) be when the total pressure exerted on the diver is \(4.0 \mathrm{~atm} ?\) (At constant temperature and pressure, the volume of a gas is directly proportional to the number of moles of gases.)

Nitrogen forms several gaseous oxides. One of them has a density of \(1.33 \mathrm{~g} / \mathrm{L}\) measured at \(764 \mathrm{mmHg}\) and \(150^{\circ} \mathrm{C}\). Write the formula of the compound.

Some commercial drain cleaners contain a mixture of sodium hydroxide and aluminum powder. When the mixture is poured down a clogged drain, the following reaction occurs: $$ 2 \mathrm{NaOH}(a q)+2 \mathrm{Al}(s)+6 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{NaAl}(\mathrm{OH})_{4}(a q)+3 \mathrm{H}_{2}(g) $$ The heat generated in this reaction helps melt away obstructions such as grease, and the hydrogen gas released stirs up the solids clogging the drain. Calculate the volume of \(\mathrm{H}_{2}\) formed at \(23^{\circ} \mathrm{C}\) and 1.00 atm if \(3.12 \mathrm{~g}\) of \(\mathrm{Al}\) are treated with an excess of \(\mathrm{NaOH}\)

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