Chapter 10: Problem 16
Calculate the height of a column of ethylene glycol \(\left[\mathrm{CH}_{2}(\mathrm{OH}) \mathrm{CH}_{2}(\mathrm{OH})\right]\) that would be supported by atmospheric pressure ( 1 atm). The density of ethylene glycol is \(1.12 \mathrm{~g} / \mathrm{cm}^{3}\)
Short Answer
Expert verified
The height of the ethylene glycol column is approximately 9.22 meters.
Step by step solution
01
Understand the Problem
We need to determine the height of an ethylene glycol column that corresponds to atmospheric pressure, which is 1 atm. We have been given the density of ethylene glycol as \(1.12 \text{ g/cm}^3\). Atmospheric pressure can also be expressed as \(101,325 \text{ Pa}\).
02
Convert Given Quantities to Compatible Units
Since we are working with pressure in pascals, we convert the density to \(\text{ kg/m}^3\):\[1.12 \text{ g/cm}^3 = 1.12 \times 1000 \text{ kg/m}^3 = 1120 \text{ kg/m}^3\]
03
Use the Pressure-Height Equation
The height \(h\) of the liquid column can be calculated using the equation:\[P = \rho g h\]where \(P\) is the pressure (\(101,325 \text{ Pa}\)), \(\rho\) is the density (\(1120 \text{ kg/m}^3\)), and \(g\) is the acceleration due to gravity (\(9.81 \text{ m/s}^2\)).
04
Solve for Height
Rearrange the formula to find \(h\):\[h = \frac{P}{\rho g}\]Substitute the values:\[h = \frac{101,325}{1120 \times 9.81} \approx \frac{101,325}{10,987.2} \approx 9.22 \text{ m}\]
05
Conclusion
The height of the ethylene glycol column supported by atmospheric pressure is approximately \(9.22 \text{ meters}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Ethylene Glycol
Ethylene glycol is a common organic compound widely used in antifreeze and deicing solutions. Its chemical formula is \( ext{CH}_2( ext{OH}) ext{CH}_2( ext{OH})\). Because of its chemical structure, ethylene glycol is hydrophilic, meaning it mixes well with water. This property is important for its applications in environments where liquid-based heat transfer is needed. In calculations related to physics or engineering, knowing the density of the substance plays a crucial role. For ethylene glycol, its density is given as \(1.12 ext{ g/cm}^3\). Knowing this helps us connect the intrinsic properties of ethylene glycol with external factors like pressure.
The Process of Density Conversion
In order to perform calculations that involve units from different measurement systems, such as the metric and SI systems, it's essential to convert quantities into compatible units. Density is usually given in \( ext{g/cm}^3\), especially in chemistry, but for physics calculations involving pressure and height, the SI unit \( ext{kg/m}^3\) is more suitable.
- To convert \(1.12 ext{ g/cm}^3\) to \( ext{kg/m}^3\), multiply by 1000.
- This is because there are 1000 grams in a kilogram and each side of a meter cube has 100 centimeters.
- Thus, the conversion leads to \(1120 ext{ kg/m}^3\).
Applying the Pressure-Height Equation
The pressure-height equation is fundamental in fluid dynamics and can help determine various properties of liquids in a column. The general equation is \[ P = \rho g h \]where:
- \(P\) is pressure, measured in pascals \(\text{Pa}\).
- \(\rho\) is the density of the fluid, in \(\text{kg/m}^3\).
- \(g\) is the acceleration due to gravity, approximately \(9.81 \text{ m/s}^2\).
- \(h\) is the height of the liquid column, in meters.
Understanding Atmospheric Pressure
Atmospheric pressure is the force exerted onto a surface by the weight of the air above it. At sea level, it is commonly measured as 1 atmosphere (atm). For scientific calculations, it is often converted into pascals (\(101,325\) Pa). Understanding atmospheric pressure is vital because it acts as a baseline pressure that counterbalances the pressure exerted by columns of liquid or other fluids.
- It affects everything from weather patterns to boiling points of liquids.
- In the context of the given problem, atmospheric pressure is what 'holds up' the column of ethylene glycol.
- Knowing this baseline helps us calculate the specific column height a certain pressure could support.