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Which of the following molecules has the largest \(a\) value: \(\mathrm{CH}_{4}, \mathrm{~F}_{2}, \mathrm{C}_{6} \mathrm{H}_{6}, \mathrm{Ne}\) ?

Short Answer

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\( \mathrm{C}_6 \mathrm{H}_6 \) has the largest 'a' value.

Step by step solution

01

Understand What the 'a' Value Represents

In the context of the van der Waals equation, the 'a' value represents the measure of the attractive forces between molecules. A larger 'a' value indicates stronger intermolecular attractions.
02

Identify the Types of Intermolecular Forces Present

Analyze the molecules: - \( \mathrm{CH}_4 \) is non-polar and has weak London dispersion forces. - \( \mathrm{F}_2 \) is non-polar with London dispersion forces. - \( \mathrm{C}_6 \mathrm{H}_6 \) (benzene) is non-polar with relatively strong dispersion forces due to its larger size and delocalized electrons.- \( \mathrm{Ne} \) is a noble gas with very weak dispersion forces.
03

Determine Which Molecule Has the Largest Polarizability

Consider the size and polarizability of the molecules, as larger, more polarizable molecules generally exhibit stronger van der Waals forces resulting in a larger 'a' value. \( \mathrm{C}_6 \mathrm{H}_6 \) is the largest and has the most electrons, contributing to a higher polarizability and stronger dispersion forces compared to the others.
04

Conclusion Based on Analysis

Given that \( \mathrm{C}_6 \mathrm{H}_6 \) has the largest and most polarizable structure, it is expected to have the largest 'a' value among the provided molecules due to the strongest intermolecular attractions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intermolecular Forces
Intermolecular forces are the forces of attraction or repulsion between neighboring particles. They are essential in determining the physical properties of substances, such as boiling and melting points. In the context of the van der Waals equation, these forces are crucial in understanding how real gases behave compared to ideal gases.

There are different types of intermolecular forces, including:
  • Dipole-dipole interactions: These occur in polar molecules where the positive end of one molecule is attracted to the negative end of another.
  • Hydrogen bonding: A strong type of dipole-dipole interaction that happens when hydrogen is bonded to a highly electronegative atom like oxygen, nitrogen, or fluorine.
  • London dispersion forces: These are the weakest intermolecular forces, present in all molecules, but they are the only types that occur in non-polar compounds.
Each of these forces plays a vital role in molecular interactions, influencing how substances behave on a macroscopic level.
Polarizability
Polarizability refers to the ease with which the electron cloud of a molecule can be distorted by an external electric field. It's a crucial factor determining the strength of London dispersion forces.

Some important aspects of polarizability:
  • Larger atoms or molecules with more electrons are generally more polarizable. This is because their outer electrons are further from the nucleus and can be more easily influenced by nearby charges.
  • Molecules with high polarizability tend to exhibit stronger intermolecular forces, leading to higher van der Waals constants (notably the 'a' value in the van der Waals equation).
  • Benzene (\(\mathrm{C}_6 \mathrm{H}_6\)), for example, is more polarizable due to its larger size and larger number of delocalized electrons compared to smaller molecules like neon (\(\mathrm{Ne}\)).
  • Polarizability influences the physical properties of substances, such as viscosity and boiling points.
Understanding polarizability helps in predicting and explaining the behavior of different substances under various conditions.
London Dispersion Forces
London dispersion forces are weak intermolecular forces arising from temporary shifts in the density of electrons in electron clouds. They are named after Fritz London, who first described them.

Key aspects of London dispersion forces:
  • They occur between all atoms and molecules, regardless of whether they are polar or nonpolar.
  • They are temporary and arise when electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles.
  • The strength of London dispersion forces increases with the size and mass of the particles. Therefore, larger, more massive molecules like benzene have stronger dispersion forces compared to small molecules like fluorine (\(\mathrm{F}_2\)).
  • They are significant in interactions between non-polar substances and noble gases, explaining phenomena like the liquefication of gases such as argon (\(\mathrm{Ar}\)) and neon (\(\mathrm{Ne}\))
  • Understanding London dispersion forces provides insights into how seemingly weak interactions can still significantly affect the properties of substances.
Chemical Bonding
Chemical bonding is the force that holds atoms together in molecules and compounds. It plays a crucial role in determining the structure and properties of matter.

There are several main types of chemical bonding:
  • Ionic bonding: Occurs when electrons are transferred from one atom to another, resulting in positively and negatively charged ions that attract each other.
  • Covalent bonding: Happens when atoms share one or more pairs of electrons to attain stability, as seen in molecules like hydrogen (\(\mathrm{H}_2\)) and oxygen (\(\mathrm{O}_2\)).
  • Metallic bonding: Characteristic of metals, where electrons are shared over many nuclei, leading to properties like conductivity and malleability.
Chemical bonds determine the geometric structures of molecules, affecting everything from physical properties to chemical reactions. Each bond type has its own energy and characteristics, influencing the behavior and interaction of substances at the molecular level.

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Most popular questions from this chapter

A stockroom supervisor measured the contents of a 25.0-gal drum partially filled with acetone on a day when the temperature was \(18.0^{\circ} \mathrm{C}\) and atmospheric pressure was \(750 \mathrm{mmHg}\), and found that 15.4 gal of the solvent remained. After tightly sealing the drum, an assistant dropped the drum while carrying it upstairs to the organic laboratory. The drum was dented, and its internal volume was decreased to 20.4 gal. What is the total pressure inside the drum after the accident? The vapor pressure of acetone at \(18.0^{\circ} \mathrm{C}\) is \(400 \mathrm{mmHg}\). (Hint: At the time the drum was sealed, the pressure inside the drum, which is equal to the sum of the pressures of air and acetone, was equal to the atmospheric pressure.)

Assuming ideal behavior, which of the following gases will have the greatest volume at STP? (a) 0.82 mole of \(\mathrm{He},\) (b) \(24 \mathrm{~g}\) of \(\mathrm{N}_{2},\) or (c) \(5.0 \times 10^{23}\) molecules of \(\mathrm{Cl}_{2}\).

Methane, the principal component of natural gas, is used for heating and cooking. The combustion process is: $$ \mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l) $$ If 15.0 moles of \(\mathrm{CH}_{4}\) react with oxygen, what is the volume of \(\mathrm{CO}_{2}\) (in liters) produced at \(23.0{ }^{\circ} \mathrm{C}\) and \(0.985 \mathrm{~atm} ?\)

The temperature in the stratosphere is \(-23^{\circ} \mathrm{C}\). Calculate the root-mean-square speeds of \(\mathrm{N}_{2}, \mathrm{O}_{2},\) and \(\mathrm{O}_{3}\) molecules in this region.

Venus's atmosphere is composed of 96.5 percent \(\mathrm{CO}_{2}\), 3.5 percent \(\mathrm{N}_{2}\), and 0.015 percent \(\mathrm{SO}_{2}\) by volume. Its standard atmospheric pressure is \(9.0 \times 10^{6} \mathrm{~Pa}\). Calculate the partial pressures of the gases in pascals.

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