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The density of ammonia gas under certain conditions is \(0.625 \mathrm{~g} / \mathrm{L} .\) Calculate its density in \(\mathrm{g} / \mathrm{cm}^{3}\).

Short Answer

Expert verified
0.000625 g/cm³

Step by step solution

01

Understand the Conversion

We need to convert the density from grams per liter to grams per cubic centimeter. Remember that 1 liter (L) is equivalent to 1000 cubic centimeters (cm³).
02

Set Up the Conversion Equation

To convert density from grams per liter to grams per cubic centimeter, divide the density in grams per liter by the number of cubic centimeters in a liter. Using the provided density: \(0.625 \text{ g/L} \) divided by \(1000 \text{ cm}^3/\text{L}\).
03

Perform the Calculation

Calculate the new density: \(\frac{0.625 \text{ g/L}}{1000 \text{ cm}^3/\text{L}} = 0.000625 \text{ g/cm}^3\).
04

Interpret the Result

The density of ammonia gas in grams per cubic centimeter (\(\text{g/cm}^3\)) is 0.000625. This is a typical conversion for gases measured in larger units to smaller units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Understanding unit conversion is key when dealing with measurements in different units. Unit conversion involves changing a measurement from one unit to another, which can make interpreting and comparing values easier.
In our example, we need to convert density units from grams per liter (g/L) to grams per cubic centimeter (g/cm³). This is important because different scientific contexts may require specific units.
To convert from g/L to g/cm³, we must understand the relationship between liters and cubic centimeters. There are always 1000 cubic centimeters in one liter. Therefore, when converting, we divide the density in g/L by 1000 to get the density in g/cm³.
This straightforward division gives us the same mass spread over a different volume measurement, effectively changing the unit without altering the actual density value in terms of mass per unit volume.
  • 1 L = 1000 cm³
  • Conversion factor = 1/1000
Density Calculation
To better understand how density calculations work, it’s beneficial to recap what density is. Density is the measure of how much mass is contained within a certain volume.
In the world of chemistry and physics, density provides insights into the concentration of mass in a given space.To calculate the density of a substance, you use the formula:
\[\text{Density} = \frac{\text{Mass}}{\text{Volume}}\]For gases such as ammonia, we often express the density in grams per liter (g/L) because this unit balances the larger volumes typical in gaseous states.
However, sometimes we need to express density in smaller units, like grams per cubic centimeter (g/cm³), as seen in our exercise. To perform this density calculation:
  • First, note the provided density, which is 0.625 g/L.
  • Ensure you have the conversion factor ready, which in our case is dividing by 1000.
  • Perform the calculation: \[\frac{0.625}{1000} = 0.000625\] g/cm³.
Once you've converted to the appropriate unit, you've completed the density calculation!
Ammonia Gas Density
The density of ammonia gas, particularly in scientific experiments, is a crucial property that helps in understanding how ammonia behaves under certain conditions.
Ammonia, a compound of nitrogen and hydrogen (NH₃), is often used in fertilizers and industrial applications. Its gaseous form has an established density that can vary depending on temperature and pressure. When calculating ammonia gas density, it’s essential to account for its physical state. Gases spread out to fill the container they are in, so density is a way to define how much mass is within that specified volume. In the exercise, we found the ammonia gas density initially in g/L, and converted it to g/cm³. This conversion can help in scenarios where precise volume measurement is crucial, such as in small-container reactions or when it's necessary to consider smaller, more controlled environments.
  • Ammonia chemical formula: NH₃
  • Standard conditions may require density doubles checks
  • Calculated density: 0.000625 g/cm³
Understanding these dynamics will aid greatly in any scientific study involving ammonia.

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Most popular questions from this chapter

A chemist mixes two liquids \(\mathrm{A}\) and \(\mathrm{B}\) to form a homogeneous mixture. The densities of the liquids are \(2.0514 \mathrm{~g} / \mathrm{mL}\) for \(\mathrm{A}\) and \(2.6678 \mathrm{~g} / \mathrm{mL}\) for \(\mathrm{B}\). When she drops a small object into the mixture, she finds that the object becomes suspended in the liquid; that is, it neither sinks nor floats. If the mixture is made of 41.37 percent \(\mathrm{A}\) and 58.63 percent \(\mathrm{B}\) by volume, what is the density of the object? Can this procedure be used in general to determine the densities of solids? What assumptions must be made in applying this method?

Convert the following temperatures to degrees Celsius: (a) \(77 \mathrm{~K},\) the boiling point of liquid nitrogen, (b) \(4.22 \mathrm{~K}\) the boiling point of liquid helium, (c) \(600.61 \mathrm{~K},\) the melting point of lead.

Chlorine is used to disinfect swimming pools. The accepted concentration for this purpose is \(1 \mathrm{ppm}\) chlorine, or \(1 \mathrm{~g}\) of chlorine per million grams of water. Calculate the volume of a chlorine solution (in milliliters) a homeowner should add to her swimming pool if the solution contains 6.0 percent chlorine by mass and there are \(2.0 \times 10^{4}\) gallons (gal) of water in the pool (1 gal \(=3.79 \mathrm{~L} ;\) density of liquids \(=1.0 \mathrm{~g} / \mathrm{mL}\) ).

The average speed of helium at \(25^{\circ} \mathrm{C}\) is \(1255 \mathrm{~m} / \mathrm{s}\). Convert this speed to miles per hour (mph).

Express the answers to the following calculations in scientific notation: (a) \(145.75+\left(2.3 \times 10^{-1}\right)\) (b) \(79,500 \div\left(2.5 \times 10^{2}\right)\) (c) \(\left(7.0 \times 10^{-3}\right)-\left(8.0 \times 10^{-4}\right)\) (d) \(\left(1.0 \times 10^{4}\right) \times\left(9.9 \times 10^{6}\right)\)

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