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How many minutes are there in a solar year \((365.24\) days \() ?\)

Short Answer

Expert verified
There are 525,945.6 minutes in a solar year.

Step by step solution

01

Understand the Problem

We need to find out the number of minutes in a solar year, which is given to be 365.24 days. This involves converting days into minutes.
02

Convert Days to Hours

First, we need to convert the number of days into hours. Since there are 24 hours in a day, we multiply the total number of days by 24. \[365.24 \text{ days} \times 24 \text{ hours/day} = 8765.76 \text{ hours}\]
03

Convert Hours to Minutes

Next, we convert hours into minutes. There are 60 minutes in an hour. Multiply the total number of hours by 60 to get the number of minutes.\[8765.76 \text{ hours} \times 60 \text{ minutes/hour} = 525,945.6 \text{ minutes}\]
04

Finalize the Answer

The calculation shows that a solar year contains 525,945.6 minutes. We can round this to a more practical number but let’s keep it as it is for precision.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Time Conversion
Time conversion is a process of changing one unit of time into another. We use it to compare, calculate, and understand different lengths of time. For example, converting days into hours or minutes helps us in making practical decisions. When converting, it is important to know the basic time units:
  • 1 day = 24 hours
  • 1 hour = 60 minutes
By multiplying, you can convert larger units into smaller ones. In the case of a solar year, which is around 365.24 days, we first change days to hours, then hours to minutes. This allows us to see the total minutes in a year. It is a simple but essential skill often used in science and daily activities.
Exploring the Solar Calendar
A solar calendar is based on the solar year, the time it takes for Earth to complete one orbit around the Sun. This period is approximately 365.24 days. Solar calendars aim to keep the months aligned with the seasons. This is slightly different from a regular calendar year of 365 days because of the extra 0.24 days. To accommodate this, we use leap years, which add an extra day every four years. This adjustment ensures that the calendar stays in sync with the solar year and seasonal changes. Knowing about the solar calendar is important for understanding how years and timekeeping systems are designed globally. It affects how we plan agriculture, festivities, and daily life.
Basic Mathematical Calculations
Mathematical calculations involve basic operations like addition, subtraction, multiplication, and division. Accurately performing these calculations is crucial when dealing with time conversion, such as converting a solar year into minutes.In this exercise, we used multiplication to change from days to hours and then from hours to minutes:
  • First, multiply the total days by 24 to get hours: \[365.24 \times 24 = 8765.76 \text{ hours}\]
  • Next, convert hours to minutes by multiplying by 60: \[8765.76 \times 60 = 525,945.6 \text{ minutes}\]
This example shows how mathematical calculations help us derive exact and practical figures, like the minutes in a solar year. Understanding and practicing these operations cements your skills in problem-solving and numerical understanding.

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Most popular questions from this chapter

A human brain weighs about \(1 \mathrm{~kg}\) and contains about \(10^{11}\) cells. Assuming that each cell is completely filled with water (density \(=1 \mathrm{~g} / \mathrm{mL}\) ), calculate the length of one side of such a cell if it were a cube. If the cells are spread out into a thin layer that is a single cell thick, what is the surface area in square meters?

One gallon of gasoline in an automobile's engine produces on the average \(9.5 \mathrm{~kg}\) of carbon dioxide, which is a greenhouse gas; that is, it promotes the warming of Earth's atmosphere. Calculate the annual production of carbon dioxide in kilograms if there are 40 million cars in the United States and each car covers a distance of \(5000 \mathrm{mi}\) at a consumption rate of 20 miles per gallon.

The average time it takes for a molecule to diffuse a distance of \(x \mathrm{~cm}\) is given by $$ t=\frac{x^{2}}{2 D} $$ where \(t\) is the time in seconds and \(D\) is the diffusion coefficient. Given that the diffusion coefficient of glucose is \(5.7 \times 10^{-7} \mathrm{~cm}^{2} / \mathrm{s},\) calculate the time it would take for a glucose molecule to diffuse \(10 \mu \mathrm{m}\), which is roughly the size of a cell.

The speed of sound in air at room temperature is about \(343 \mathrm{~m} / \mathrm{s}\). Calculate this speed in miles per hour \((1 \mathrm{mi}=1609 \mathrm{~m})\).

The total volume of seawater is \(1.5 \times 10^{21} \mathrm{~L}\). Assume that seawater contains 3.1 percent sodium chloride by mass and that its density is \(1.03 \mathrm{~g} / \mathrm{mL}\). Calculate the total mass of sodium chloride in kilograms and in tons \((1\) ton \(=2000 \mathrm{lb} ; 1 \mathrm{lb}=453.6 \mathrm{~g})\).

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