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Carry out the following conversions: (a) \(22.6 \mathrm{~m}\) to decimeters, (b) \(25.4 \mathrm{mg}\) to kilograms, (c) \(556 \mathrm{~mL}\) to liters, (d) \(10.6 \mathrm{~kg} / \mathrm{m}^{3}\) to \(\mathrm{g} / \mathrm{cm}^{3}\).

Short Answer

Expert verified
a) 226 dm, b) 0.0000254 kg, c) 0.556 L, d) 0.0106 g/cm³.

Step by step solution

01

Converting Meters to Decimeters

To convert from meters to decimeters, we need to know that 1 meter is equal to 10 decimeters. Therefore, we multiply the given value in meters by 10 to get the value in decimeters.Given: \(22.6 \text{ meters}\)Calculation: \[ 22.6 \text{ m} \times 10 = 226 \text{ dm} \]
02

Converting Milligrams to Kilograms

To convert from milligrams to kilograms, we note that there are 1,000,000 milligrams in a kilogram. Thus, we divide the value in milligrams by 1,000,000.Given: \(25.4 \text{ mg}\)Calculation: \[ \frac{25.4 \text{ mg}}{1,000,000} = 0.0000254 \text{ kg} \]
03

Converting Milliliters to Liters

To convert from milliliters to liters, we use the fact that 1 liter is 1,000 milliliters. Therefore, we divide the milliliter value by 1,000.Given: \(556 \text{ mL}\)Calculation: \[ \frac{556 \text{ mL}}{1,000} = 0.556 \text{ L} \]
04

Converting Kilograms per Cubic Meter to Grams per Cubic Centimeter

To convert from kg/m³ to g/cm³, we use the conversion that 1 kg/m³ equals 0.001 g/cm³.Given: \(10.6 \text{ kg/m}^3\)Calculation: \[ 10.6 \text{ kg/m}^3 \times 0.001 = 0.0106 \text{ g/cm}^3 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Metric System
The metric system is a universal decimal measurement system used worldwide. It is simple, easy to apply, and based on multiples of ten. The base units include the meter for length, the kilogram for mass, and the liter for volume. These units make calculations straightforward:
  • Length is measured in meters, which can be converted into kilometers, centimeters, and millimeters.
  • Mass is measured in kilograms, easily convertible into grams, milligrams, or metric tons.
  • Volume is generally measured in liters, convertible into milliliters and cubic meters.

By knowing these base units, students can perform unit conversions smoothly in the metric system.
Measurement Conversion
Measurement conversion involves changing one unit to another within the same system. In the original exercise, we see conversions between units like meters to decimeters and milligrams to kilograms. Understanding the relationship is key:
  • Meters to Decimeters: Since 1 meter equals 10 decimeters, multiply meters by 10 to get decimeters.
  • Milligrams to Kilograms: Recognize that 1 kilogram equals 1,000,000 milligrams. Hence, divide milligrams by 1,000,000.
  • Milliliters to Liters: 1 liter equals 1,000 milliliters, so divide milliliters by 1,000.
  • Kilograms/Meters³ to Grams/Centimeters³: Use the conversion factor 1 kg/m³ equals 0.001 g/cm³, multiplying the original value appropriately.
These conversion rules are consistent across various measurements, simplifying complex calculations.
Dimensional Analysis
Dimensional analysis is a technique used to ensure that calculations yield the correct units. It involves the systematic conversion between units using conversion factors. In solving measurement conversion problems, dimensional analysis helps confirm the correctness of unit transformations. To employ dimensional analysis, follow these steps:
  • Identify the units you have and the units you want to obtain.
  • Determine the conversion factor(s) needed to link the two units.
  • Apply the conversion factor by multiplying or dividing, according to the relationship.
  • Ensure units cancel appropriately, leaving only the desired units.
By consistently applying dimensional analysis, students reduce errors and deepen their understanding of unit conversions.

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Most popular questions from this chapter

Using examples, explain the difference between a physical property and a chemical property.

Suppose that a new temperature scale has been devised on which the melting point of ethanol \(\left(-117.3^{\circ} \mathrm{C}\right)\) and the boiling point of ethanol \(\left(78.3^{\circ} \mathrm{C}\right)\) are taken as \(0^{\circ} \mathrm{S}\) and \(100^{\circ} \mathrm{S},\) respectively, where \(\mathrm{S}\) is the symbol for the new temperature scale. Derive an equation relating a reading on this scale to a reading on the Celsius scale. What would this thermometer read at \(25^{\circ} \mathrm{C} ?\)

Convert the following temperatures to degrees Celsius: (a) \(77 \mathrm{~K},\) the boiling point of liquid nitrogen, (b) \(4.22 \mathrm{~K}\) the boiling point of liquid helium, (c) \(600.61 \mathrm{~K},\) the melting point of lead.

Express the following numbers as decimals: (a) \(1.52 \times 10^{-2}\) (b) \(7.78 \times 10^{-8}\) (c) \(1 \times 10^{-6}\) (d) \(1.6001 \times 10^{3}\).

A student is given a crucible and asked to prove whether it is made of pure platinum. She first weighs the crucible in air and then weighs it suspended in water (density = \(0.9986 \mathrm{~g} / \mathrm{mL}\) ). The readings are \(860.2 \mathrm{~g}\) and \(820.2 \mathrm{~g}\), respectively. Based on these measurements and given that the density of platinum is \(21.45 \mathrm{~g} / \mathrm{cm}^{3},\) what should her conclusion be? (Hint: An object suspended in a fluid is buoyed up by the mass of the fluid displaced by the object. Neglect the buoyancy of air.)

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