Chapter 1: Problem 40
A student pours \(44.3 \mathrm{~g}\) of water at \(10^{\circ} \mathrm{C}\) into a beaker containing \(115.2 \mathrm{~g}\) of water at \(10^{\circ} \mathrm{C}\). What are the final mass, temperature, and density of the combined water? The density of water at \(10^{\circ} \mathrm{C}\) is \(1.00 \mathrm{~g} / \mathrm{mL}\).
Short Answer
Step by step solution
Calculate the Final Mass
Determine the Final Temperature
Calculate the Density
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mass
The mass of a substance is straightforward and doesn't depend on its shape or location, such as inside a beaker.
When we added the mass of the first water sample, which is 44.3 g, to the mass of the second sample, 115.2 g, the final mass became 159.5 g.
- The formula to calculate the total mass is:
\( ext{Final Mass} = ext{Mass}_1 + ext{Mass}_2\)
Using this approach ensures you account for all the matter in both water samples.
Remember, to always carry units through the calculation to avoid errors.
Temperature
In this exercise, both water samples are initially at 10°C.
- Since no external heat is being added or removed, the final temperature of the combined water remains 10°C.
Therefore, if two samples are mixed and are both at the same initial temperature, the final temperature is the same unless a chemical reaction occurs or heat is transferred in some way.
Water Properties
This value means that for every milliliter of water, the mass is 1 gram. This relationship is fundamental, as it allows us to understand and calculate other related concepts, like volume or mass, when one is unknown.
- Even when water is combined, as in this exercise, the density remains constant at this specific temperature unless there is a temperature change or another substance is mixed in.
Understanding how density works with temperature is crucial in many scientific and environmental studies where water is being evaluated.