Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A student pours \(44.3 \mathrm{~g}\) of water at \(10^{\circ} \mathrm{C}\) into a beaker containing \(115.2 \mathrm{~g}\) of water at \(10^{\circ} \mathrm{C}\). What are the final mass, temperature, and density of the combined water? The density of water at \(10^{\circ} \mathrm{C}\) is \(1.00 \mathrm{~g} / \mathrm{mL}\).

Short Answer

Expert verified
Final mass is 159.5 g, temperature is 10°C, density is 1.00 g/mL.

Step by step solution

01

Calculate the Final Mass

To find the final mass of the combined water, add the masses of the two samples. The first sample has a mass of \(44.3\,\text{g}\) and the second has \(115.2\,\text{g}\). Thus, the total mass is \(44.3 + 115.2 = 159.5\,\text{g}\).
02

Determine the Final Temperature

Since both samples of water are at the same temperature of \(10^{\circ}\,C\), the final temperature of the combined water remains \(10^{\circ}\,C\).
03

Calculate the Density

The density of water at \(10^{\circ}\,C\) is given as \(1.00\,\text{g/mL}\). Since the temperature does not change and the substance is composed entirely of water, the density remains \(1.00\,\text{g/mL}\) for the combined mixture.

Achieve better grades quicker with Premium

  • Textbook solutions

    Access to all textbook solutions

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Offline and ads-free access

    To over 500 million flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 22 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass
Mass is a measure of the amount of matter in an object, typically measured in grams (g) or kilograms (kg). In this exercise, we are combining two samples of water, each with a known mass. To find the final mass of the combined water, we simply add the masses of the individual samples together.
The mass of a substance is straightforward and doesn't depend on its shape or location, such as inside a beaker.
When we added the mass of the first water sample, which is 44.3 g, to the mass of the second sample, 115.2 g, the final mass became 159.5 g.
  • The formula to calculate the total mass is:
    \( ext{Final Mass} = ext{Mass}_1 + ext{Mass}_2\)
    Using this approach ensures you account for all the matter in both water samples.
    Remember, to always carry units through the calculation to avoid errors.
So, adding substances together is a nifty way to calculate the total mass, as we have done by simply summing the masses.
Temperature
Temperature is an indicator of the thermal energy in a substance, denoted in degrees Celsius (°C) in this context. It's important to understand that temperature is a property independent of the mass of the object. When dealing with the same substance, like water, and at the same temperature, the final mixture's temperature remains unchanged.
In this exercise, both water samples are initially at 10°C.
  • Since no external heat is being added or removed, the final temperature of the combined water remains 10°C.
This happens because of something called thermal equilibrium, where substances in thermal contact reach the same temperature and maintain it without gaining or losing heat.
Therefore, if two samples are mixed and are both at the same initial temperature, the final temperature is the same unless a chemical reaction occurs or heat is transferred in some way.
Water Properties
Water is a unique substance with several interesting properties. One such property is its density, which is defined as mass per unit volume. Here, the density of water at 10°C is given as 1.00 g/mL.
This value means that for every milliliter of water, the mass is 1 gram. This relationship is fundamental, as it allows us to understand and calculate other related concepts, like volume or mass, when one is unknown.
  • Even when water is combined, as in this exercise, the density remains constant at this specific temperature unless there is a temperature change or another substance is mixed in.
Water has a high specific heat capacity, meaning it requires a lot of energy to change its temperature, hence maintaining its density under stable conditions.
Understanding how density works with temperature is crucial in many scientific and environmental studies where water is being evaluated.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A \(37.2-\mathrm{g}\) sample of lead \((\mathrm{Pb})\) pellets at \(20^{\circ} \mathrm{C}\) is mixed with a 62.7 -g sample of lead pellets at the same temperature. What are the final mass, temperature, and density of the combined sample? The density of \(\mathrm{Pb}\) at \(20^{\circ} \mathrm{C}\) is \(11.35 \mathrm{~g} / \mathrm{cm}^{3}\).

Pheromones are compounds secreted by females of many insect species to attract mates. Typically, \(1.0 \times 10^{-8} \mathrm{~g}\) of a pheromone is sufficient to reach all targeted males within a radius of \(0.50 \mathrm{mi}\). Calculate the density of the pheromone (in grams per liter) in a cylindrical air space having a radius of \(0.50 \mathrm{mi}\) and a height of \(40 \mathrm{ft}\) (volume of a cylinder of radius \(r\) and height \(h\) is \(\pi r^{2} h\) ).

Determine whether each of the following describes a physical change or a chemical change: (a) The helium gas inside a balloon tends to leak out after a few hours. (b) A flashlight beam slowly gets dimmer and finally goes out. (c) Frozen orange juice is reconstituted by adding water to it. (d) The growth of plants depends on the sun's energy in a process called photosynthesis. (e) A spoonful of salt dissolves in a bowl of soup.

The thin outer layer of Earth, called the crust, contains only 0.50 percent of Earth's total mass and yet is the source of almost all the elements (the atmosphere provides elements such as oxygen, nitrogen, and a few other gases). Silicon (Si) is the second most abundant element in Earth's crust ( 27.2 percent by mass). Calculate the mass of silicon in kilograms in Earth's crust (mass of Earth \(=5.9 \times 10^{21}\) tons; 1 ton \(=2000 \mathrm{lb}\); \(1 \mathrm{lb}=453.6 \mathrm{~g})\).

A slow jogger runs a mile in 13 min. Calculate the speed in (a) in/s, (b) \(\mathrm{m} / \mathrm{min}\) (c) \(\mathrm{km} / \mathrm{h}(1 \mathrm{mi}=1609 \mathrm{~m}\) \(1 \mathrm{in}=2.54 \mathrm{~cm})\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free