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Describe the bonding in the \(\mathrm{O}_{3}\) molecule and the \(\mathrm{NO}_{2}^{-}\) ion using the localized electron model. How would the molecular orbital model describe the \(\pi\) bonding in these two species?

Short Answer

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In the O3 molecule, the localized electron model describes one sigma bond and one pi bond between the central oxygen and the outer oxygens, with resonance leading to equal bond lengths. In the NO2- ion, there is one sigma bond and one pi bond between the nitrogen atom and each oxygen atom, with resonance causing equal bond lengths. Using the molecular orbital model, π bonding in both species is delocalized across all three atoms, allowing for the sharing of electrons in π bonding orbitals, which contributes to resonance properties and equal bond lengths.

Step by step solution

01

O3 Localized Electron Model

O3 is an ozone molecule composed of three oxygen atoms. Using Lewis structure, we would have one double bond between the first and second oxygen atoms, and a single bond between the second and third oxygen atoms, with an extra lone pair on the central oxygen. However, due to resonance, the two outer oxygen atoms share the double bond, and the bond lengths are equal between each oxygen pair. Thus, there is one sigma bond and one pi bond between the outer oxygens and the central oxygen.
02

NO2- Localized Electron Model

NO2- is a nitrite ion with one nitrogen atom and two oxygen atoms. To describe the bonding in this ion using the localized electron model, we can use the Lewis structure. One of the oxygen atoms is double bonded to the nitrogen atom, while the other oxygen atom is single bonded to the nitrogen atom, with a charge of -1. The nitrogen atom has a lone pair of electrons which contributes to the resonance. Similar to the O3 molecule, the bond lengths and bond strengths are equal for both N-O bonds due to resonance. There is one sigma bond and one pi bond between the nitrogen atom and each oxygen atom.
03

O3 Molecular Orbital Model

The molecular orbital model describes the distribution of electrons in π bonding differently compared to the localized electron model. In this case, the π bonding in the O3 molecule is delocalized across the three oxygen atoms. The electrons in the π bonding orbitals are shared by all three oxygen atoms in a continuous orbital, which helps explain the resonance properties and equal bond lengths.
04

NO2- Molecular Orbital Model

Similarly, the molecular orbital model in the NO2- ion describes the π bonding as delocalized across the nitrogen atom and both oxygen atoms. This leads to electron distribution in π bonding orbitals shared by all three atoms, which contributes to the resonance properties and equal bond lengths between the nitrogen and oxygen atoms. Both of these descriptions, using the Localized Electron Model and the Molecular Orbital Model, help us understand the bonding and resonance properties of these molecules and ions.

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Most popular questions from this chapter

The oxyanion of nitrogen in which it has the highest oxidation state is the nitrate ion \(\left(\mathrm{NO}_{3}^{-}\right) .\) The corresponding oxyanion of phosphorus is \(\mathrm{PO}_{4}^{3-}\) . The \(\mathrm{NO}_{4}^{3-}\) ion is known but is not very stable. The \(\mathrm{PO}_{3}-\) ion is not known. Account for these differences in terms of the bonding in the four anions.

The diatomic molecule OH exists in the gas phase. OH plays an important part in combustion reactions and is a reactive oxidizing agent in polluted air. The bond length and bond energy have been measured to be 97.06 \(\mathrm{pm}\) and 424.7 \(\mathrm{kJ} / \mathrm{mol}\) respectively. Assume that the OH molecule is analogous to the HF molecule discussed in the chapter and that the MOs result from the overlap of a \(p_{z}\) orbital from oxygen and the 1\(s\) orbital of hydrogen (the O-H bond lies along the z axis). a. Draw pictures of the sigma bonding and antibonding molecular orbitals in OH. b. Which of the two MOs has the greater hydrogen 1\(s\) character? c. Can the 2\(p_{x}\) orbital of oxygen form MOs with the 1\(s\) orbital of hydrogen? Explain. d. Knowing that only the 2\(p\) orbitals of oxygen interact significantly with the 1\(s\) orbital of hydrogen, complete the MO energy-level diagram for OH. Place the correct number of electrons in the energy levels. e. Estimate the bond order for OH. f. Predict whether the bond order of \(\mathrm{OH}^{+}\) is greater than, less than, or the same as that of OH. Explain.

A variety of chlorine oxide fluorides and related cations and anions are known. They tend to be powerful oxidizing and fluorinating agents. \(\mathrm{FClO}_{3}\) is the most stable of this group of compounds and has been studied as an oxidizing component in rocket propellants. Draw a Lewis structure for \(\mathrm{F}_{3} \mathrm{ClO}\) , \(\mathrm{F}_{2} \mathrm{ClO}_{2}^{+},\) and \(\mathrm{F}_{3} \mathrm{ClO}_{2}\) . What is the molecular structure for each species, and what is the expected hybridization of the central chlorine atom in each compound or ion?

Use the localized electron model to describe the bonding in \(\mathrm{H}_{2} \mathrm{O}\) .

Use the localized electron model to describe the bonding in \(\mathrm{CCl}_{4}\) .

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