Chapter 8: Problem 78
Consider the following reaction: $$A_{2}+B_{2} \longrightarrow 2 A B \quad \Delta H=-285 \mathrm{kJ}$$ The bond energy for \(\mathrm{A}_{2}\) is one-half the amount of the AB bond energy. The bond energy of \(\mathrm{B}_{2}=432 \mathrm{kJ} / \mathrm{mol}\) . What is the bond energy of \(\mathrm{A}_{2}\) ?
Short Answer
Step by step solution
Write the equation for the enthalpy change of the reaction
Find bond energy of A₂ using the given relationship
Solve for the bond energy of A₂
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