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Combustion reactions of fossil fuels provide most of the energy needs of the world. Why are combustion reactions of fossil fuels so exothermic?

Short Answer

Expert verified
The combustion reactions of fossil fuels are exothermic because the energy released during the formation of new CO2 and H2O bonds is greater than the energy required to break the original carbon, hydrogen, and oxygen bonds. This excess energy is released as heat, making the reaction exothermic. The energy released in the form of heat during combustion reactions drives various processes such as generating electricity in power plants and providing heat for our homes and vehicles.

Step by step solution

01

Understand fossil fuels

Fossil fuels are hydrocarbon compounds that have formed over millions of years from the remains of plants and animals. They include coal, oil, and natural gas and contain a high amount of chemical energy stored in their bonds.
02

Understand exothermic reactions

An exothermic reaction is a chemical reaction that releases energy (mostly in the form of heat) into the surrounding environment. These reactions occur when the energy stored in the bonds of the reactants is greater than the energy stored in the bonds of the products.
03

Combustion reactions

Combustion is a type of chemical reaction that occurs between a fuel (usually a hydrocarbon) and an oxidizing agent (usually oxygen from the air), releasing heat and producing products such as carbon dioxide and water.
04

Energy changes during combustion

In the combustion of fossil fuels, the carbon and hydrogen atoms present in the fuel combine with oxygen from the air to form carbon dioxide (CO2) and water (H2O). This process involves breaking the chemical bonds between carbon, hydrogen, and oxygen and forming new bonds in the CO2 and H2O molecules.
05

Explain why combustion reactions are exothermic

The combustion reactions of fossil fuels are exothermic because the energy released during the formation of new CO2 and H2O bonds is greater than the energy required to break the original carbon, hydrogen, and oxygen bonds. This excess energy is released as heat, making the reaction exothermic. The energy released in the form of heat during combustion reactions drives various processes such as generating electricity in power plants and providing heat for our homes and vehicles. In conclusion, combustion reactions of fossil fuels are exothermic because the formation of new chemical bonds in the products (CO2 and H2O) releases more energy than the energy required to break the initial bonds in the reactants (carbon and hydrogen in the fuel and oxygen in the air).

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Most popular questions from this chapter

The most common type of exception to the octet rule are compounds or ions with central atoms having more than eight electrons around them. PF_. \(\mathrm{PF}_{5}, \mathrm{SF}_{4}, \mathrm{ClF}_{3}\) and \(\mathrm{Br}_{3}^{-}\) are examples of this type of exception. Draw the Lewis structure for these compounds or ions. Which elements, when they have to, can have more than eight electrons around them? How is this rationalized?

Borazine \(\left(\mathrm{B}_{3} \mathrm{N}_{3} \mathrm{H}_{6}\right)\) has often been called "inorganic" benzene. Write Lewis structures for borazine. Borazine contains a six-membered ring of alternating boron and nitrogen atoms with one hydrogen bonded to each boron and nitrogen.

For each of the following groups, place the atoms and/or ions in order of decreasing size. a. \(\mathrm{V}, \mathrm{V}^{2+}, \mathrm{V}^{3+}, \mathrm{V}^{5+}\) b. \(\mathrm{Na}^{+}, \mathrm{K}^{+}, \mathrm{Rb}^{+}, \mathrm{Cs}^{+}\) c. \(\mathrm{Te}^{2-}, \mathrm{I}^{-}, \mathrm{Cs}^{+}, \mathrm{Ba}^{2+}\) d. \(\mathrm{P}, \mathrm{P}^{-}, \mathrm{P}^{2-}, \mathrm{P}^{3-}\) e. \(\mathrm{O}^{2-}, \mathrm{S}^{2-}, \mathrm{Se}^{2-}, \mathrm{Te}^{2-}\)

Use bond energies to estimate \(\Delta H\) for the combustion of one mole of acetylene: $$\mathrm{C}_{2} \mathrm{H}_{2}(g)+\frac{5}{2} \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)$$

Hydrogen has an electronegativity value between boron and carbon and identical to phosphorus. With this in mind, rank the following bonds in order of decreasing polarity: \(\mathrm{P}-\mathrm{H}\) , \(\mathrm{O}-\mathrm{H}, \mathrm{N}-\mathrm{H}, \mathrm{F}-\mathrm{H}, \mathrm{C}-\mathrm{H} .\)

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