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What is the central idea of the VSEPR model?

Short Answer

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The central idea of the VSEPR model is to predict the three-dimensional structure of molecules based on the repulsion between electron pairs surrounding the central atom. The model emphasizes that electron pairs in an atom's valence shell repel each other and arrange themselves to minimize repulsion, influencing the resulting molecular geometry.

Step by step solution

01

VSEPR Model Definition

The Valence Shell Electron Pair Repulsion (VSEPR) model is a method used to predict the three-dimensional structure of molecules based on the repulsion between electron pairs around the central atom. The basic idea is that electron pairs in the valence shell of an atom repel each other and arrange themselves to minimize this repulsion.
02

Electron Pair Repulsion

In the VSEPR model, there is an emphasis on the repulsion between electron pairs. This repulsion arises due to the negative charges of the electron pairs, causing them to push each other away. The force of repulsion decreases with the increasing distance between the electron pairs. This concept helps understand the effects of lone pairs and bonding pairs in determining molecular shape.
03

VSEPR Notations

The VSEPR model uses the AXE notation to describe the arrangement of atoms and electron pairs. A represents the central atom, X represents the number of atoms directly bonded to the central atom (also known as bonding pairs), and E represents the number of lone pairs (nonbonding pairs).
04

Molecular Geometry Prediction

To predict the molecular geometry using the VSEPR model, perform the following steps: 1) Determine the Lewis structure of the molecule. 2) Identify the AXE notation for the molecule. 3) Based on the AXE notation, identify the predicted molecular geometry. Some common geometries include linear, bent, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral. By understanding the central idea of the VSEPR model – electron pair repulsion – and applying these steps, you can predict the molecular geometry of various compounds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Geometry
Molecular geometry describes the three-dimensional arrangement of atoms within a molecule. It influences many properties of a molecule such as its reactivity, color, phase of matter, and biological activity. Understanding molecular geometry is essential to grasping how molecules interact and behave in different environments.

The shape of a molecule is primarily determined by the valence shell electron pair repulsion model (VSEPR model), which predicts the spatial arrangement based on minimizing repulsion between electron pairs around the central atom.
  • Linear geometry: Seen in molecules with two bonding pairs and no lone pairs, like CO2.
  • Bent or angular geometry: Occurs in molecules with lone pairs, like H2O.
  • Trigonal planar: Found in molecules like BF3, with three bonding pairs and no lone pairs.
  • Tetrahedral geometry: Seen in CH4, with four bonding pairs.
  • Trigonal bipyramidal and octahedral geometries, for more complex molecules, involve more atoms and electron pairs.
Using the VSEPR model, you can accurately predict these geometries by exploring the arrangement of atoms and electron pairs in the molecule.
Electron Pair Repulsion
At the heart of the VSEPR model is the concept of electron pair repulsion. Electron pairs are negative and repel one another, much like how magnets with the same poles repel each other. This repulsion affects both bonding pairs, which connect different atoms, and lone pairs, which exist solely on the central atom.

Lone pairs exert a greater repulsive force than bonding pairs because they are closer to the central atom. This increased repulsion can influence the molecular geometry by pushing bonding pairs further apart.
  • Bonding pairs: These are shared electrons between atoms, creating a bond.
  • Lone pairs: Electrons not involved in bonding but affect the overall shape.
For instance, in a molecule like NH3, the lone pair on nitrogen pushes the three hydrogen atoms into a trigonal pyramidal shape rather than a flat trigonal planar one.

To minimize repulsion, molecules rearrange themselves into the most stable shape possible, leading to the diverse geometries that we see.
AXE Notation
AXE notation is a concise way to describe the composition and arrangement of atoms and electron pairs in a molecule, which is crucial for predicting its geometry. The notation consists of three parts:
  • A: Represents the central atom in the molecule.
  • X: Indicates the number of surrounding atoms that are directly bonded to the central atom. These are referred to as bonding pairs.
  • E: Denotes the number of lone pairs of electrons on the central atom.
AXE notation serves as the foundation for predicting molecular geometry. For example, consider water (H2O) with AXE notation written as AX2E2:
  • The central atom A is oxygen.
  • There are two hydrogen atoms bonded to oxygen, giving X=2.
  • The molecule also has two lone pairs on the oxygen, leading to E=2.
This specific AXE arrangement results in a bent molecular geometry. By using the AXE method, learners can systematically determine the structure of a molecule from its bonded atoms and electron pairs.

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Most popular questions from this chapter

When comparing the size of different ions, the general radii trend discussed in Chapter 7 is usually not very useful. What do you concentrate on when comparing sizes of ions to each other or when comparing the size of an ion to its neutral atom?

Predict the molecular structure (including bond angles) for each of the following. a. \(\mathrm{PCl}_{3}\) b. \(\mathrm{SCl}_{2}\) c. \(\mathrm{SiF}_{4}\)

An alternative definition of electronegativity is $$\text { Electronegativity } = \text { constant } (\mathrm{I.E.}-\mathrm{E.A.})$$ where I.E. is the ionization energy and E.A. is the electron affinity using the sign conventions of this book. Use data in Chapter 7 to calculate the \((\mathrm{I} . \mathrm{E} .-\mathrm{E} \cdot \mathrm{A} .)\) term for \(\mathrm{F}, \mathrm{Cl}, \mathrm{Br}\) and \(\mathrm{I}\). Do these values show the same trend as the electronegativity values given in this chapter? The first ionization energies of the halogens are 1678, 1255, 1138, and 1007 kJ/mol, respectively. (Hint: Choose a constant so that the electronegativity of fluorine equals 4.0. Using this constant, calculate relative electronegativities for the other halogens and compare to values given in the text.)

Write Lewis structures that obey the octet rule for the following species. Assign the formal charge for each central atom. a. \(\mathrm{POCl}_{3} \quad\) c. \(\mathrm{ClO}_{4}^{-} \quad\) \(\mathrm{e} \cdot \mathrm{SO}_{2} \mathrm{Cl}_{2} \quad\) g. \(\mathrm{ClO}_{3}^{-}\) b. \(\mathrm{SO}_{4}^{2-} \quad\) d. \(\mathrm{PO}_{4}^{3-} \quad\) f. \(\mathrm{XeO}_{4} \quad\) h. \(\mathrm{NO}_{4}^{3-}\)

Use the following data to estimate \(\Delta H_{\mathrm{f}}^{\circ}\) for magnesium fluoride. $$\mathrm{Mg}(s)+\mathrm{F}_{2}(g) \longrightarrow \mathrm{MgF}_{2}(s)$$ \(\begin{array}{l}{\text { Lattice energy }} & {-22913 . \mathrm{kJ} / \mathrm{mol}} \\ {\text { First ionization energy of } \mathrm{Mg}} & \quad{735 \mathrm{kJ} / \mathrm{mol}} \\ {\text {Second ionization energy of } \mathrm{Mg}} & \quad {1445 \mathrm{kJ} / \mathrm{mol}}\\\\{\text { Electron affinity of } \mathrm{F}} & {-328 \mathrm{kJ} / \mathrm{mol}} \\ {\text { Bond energy of } \mathrm{F}_{2}} & \quad {154 \mathrm{kJ} / \mathrm{mol}} \\\ {\text { Enthalpy of sublimation for } \mathrm{Mg}} & \quad {150 . \mathrm{kJ} / \mathrm{mol}} \end{array}\)

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