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Identify the following three elements. a. The ground-state electron configuration is \([\mathrm{Kr}] 5 s^{2} 4 d^{10} 5 p^{4}\) b. The ground-state electron configuration is \([\mathrm{Ar}] 4 s^{2} 3 d^{10} 4 p^{2}\) c. An excited state of this element has the electron configuration 1\(s^{2} 2 s^{2} 2 p^{4} 3 s^{1}\)

Short Answer

Expert verified
The identified elements are: a. Tellurium (Te) - Ground state electron configuration b. Germanium (Ge) - Ground state electron configuration c. Fluorine (F) - Excited state electron configuration

Step by step solution

01

Identify element for configuration a

For configuration a, \([\mathrm{Kr}] 5 s^{2} 4 d^{10} 5 p^{4}\), we first need to determine the atomic number of Kr. Kr has an atomic number of 36. Now, we add the electrons from the additional subshells: 36 (from Kr) + 2 (from \(5s^2\)) + 10 (from \(4d^{10}\)) + 4 (from \(5p^4\)) = 52 The element with atomic number 52 is Tellurium (Te).
02

Identify element for configuration b

For configuration b, \([\mathrm{Ar}] 4 s^{2} 3 d^{10} 4 p^{2}\), we first need to determine the atomic number of Ar. Ar has an atomic number of 18. Now, we add the electrons from the additional subshells: 18 (from Ar) + 2 (from \(4s^2\)) + 10 (from \(3d^{10}\)) + 2 (from \(4p^2\)) = 32 The element with atomic number 32 is Germanium (Ge).
03

Identify element for excited state configuration c

For the excited state configuration c, \(1s^{2} 2s^{2} 2p^{4} 3s^{1}\), we sum up the number of electrons: 2 (from \(1s^2\)) + 2 (from \(2s^2\)) + 4 (from \(2p^4\)) + 1 (from \(3s^1\)) = 9 The element with atomic number 9 is Fluorine (F). We can conclude that: a. Tellurium (Te) - Ground state electron configuration b. Germanium (Ge) - Ground state electron configuration c. Fluorine (F) - Excited state electron configuration

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ground State
In chemistry, the ground state of an atom refers to the lowest energy configuration of its electrons. It is the most stable state for an atom and generally corresponds to the situation in which electrons occupy the lowest available energy levels. This arrangement is guided by the principles of quantum mechanics: the Aufbau principle, Hund's rule, and the Pauli Exclusion Principle.
For example, in the exercise provided, configurations for Tellurium and Germanium are given in their ground states. Tellurium's ground-state configuration is \(\mathrm{[Kr]}\ 5\ s^{2}\ 4\ d^{10}\ 5\ p^{4}\), while Germanium's is \(\mathrm{[Ar]}\ 4\ s^{2}\ 3\ d^{10}\ 4\ p^{2}\). These configurations indicate how electrons are distributed across the various sub-shells in their lowest energy states. The electrons fill the 1s orbital first, then the 2s, followed by 2p, 3s, and so forth, as per increasing energy levels.
Excited State
An excited state occurs when electrons in an atom have absorbed energy and moved to a higher energy level, leaving lower-energy levels partially filled. This state is generally unstable, and atoms tend to release the absorbed energy and return to their ground state.
For instance, in the exercise, an excited state is presented for Fluorine. Its electron configuration in this state is\(1s^{2} 2s^{2} 2p^{4} 3s^{1}\).Normally, all electrons would fill the 1s, 2s, and 2p orbitals before entering the next level (3s). However, one of the 2p electrons has been excited to the 3s orbital, resulting in this particular configuration.
Given that excited states are temporary, electrons will eventually release energy, often in the form of light, and 'fall' back to their ground state configuration.
Atomic Number
The atomic number is a fundamental property of a chemical element and is defined as the number of protons in the nucleus of an atom. It essentially dictates the identity of an element, as each element has a unique atomic number.
To identify the elements in the exercise, one can add up the total number of electrons provided by the electron configurations. For instance, Tellurium has an atomic number of 52, determined by adding 36 (from Krypton [Kr] core configuration) plus the electrons in the additional orbitals. Similarly, Germanium's atomic number is 32, and Fluorine's is 9. It's crucial to calculate atomic numbers correctly, since they guide us not only to an element’s chemical properties but also its placement in the periodic table.
Chemical Elements
Chemical elements are pure substances consisting of only one type of atom, each characterized by a unique number of protons in their atomic nuclei. They are the building blocks of matter and are organized systematically in the periodic table based on their atomic structures and properties.
In the exercise we examined, elements like Tellurium, Germanium, and Fluorine were identified by interpreting their electron configurations. Tellurium is a metalloid, crucial in various industrial applications such as thermoelectric devices. Germanium is another metalloid, often used in semiconductor technology. Fluorine, on the other hand, is a highly reactive, non-metallic element used widely in toothpaste and Teflon coating.
  • Understanding chemical elements involves recognizing their distinct electron configurations and atomic numbers.
  • These factors help predict chemical behavior and potential reactivity in different environments.
By grasping these concepts, you can better understand not only the nature of each element but also their diverse applications in science and industry.

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Most popular questions from this chapter

The bright yellow light emitted by a sodium vapor lamp consists of two emission lines at 589.0 and 589.6 nm. What are the frequency and the energy of a photon of light at each of these wavelengths? What are the energies in kJ/mol?

In each of the following sets, which atom or ion has the smallest ionization energy? a. \(\mathrm{Ca}, \mathrm{Sr}, \mathrm{Ba}\) b. \(\mathrm{K}, \mathrm{Mn}, \mathrm{Ga}\) c. \(\mathrm{N}, \mathrm{O}, \mathrm{F}\) d. \(\mathrm{S}^{2-}, \mathrm{S}, \mathrm{S}^{2+}\) e. \(\mathrm{Cs}, \mathrm{Ge}, \mathrm{Ar}\)

Answer the following questions based on the given electron configurations, and identify the elements. a. Arrange these atoms in order of increasing size: \([\mathrm{Kr}] 5 s^{2} 4 d^{10} 5 p^{6} ;[\mathrm{Kr}] 5 s^{2} 4 d^{10} 5 p^{1} ;[\mathrm{Kr}] 5 s^{2} 4 d^{10} 5 p^{3}\) b. Arrange these atoms in order of decreasing first ionization energy: [Ne \(3 s^{2} 3 p^{5} ;[\operatorname{Ar}] 4 s^{2} 3 d^{10} 4 p^{3} ;[\operatorname{Ar}] 4 s^{2} 3 d^{10} 4 p^{5}\)

Valence electrons are those electrons in the outermost principal quantum level (highest n level) of an atom in its ground state. Groups 1A to 8A have from 1 to 8 valence electrons. For each group of the representative elements (1A–8A), give the number of valence electrons, the general valence electron configuration, a sample element in that group, and the specific valence electron configuration for that element.

Assume that a hydrogen atom's electron has been excited to the \(n=5\) level. How many different wavelengths of light can be emitted as this excited atom loses energy?

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