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Mars is roughly 60 million km from Earth. How long does it take for a radio signal originating from Earth to reach Mars?

Short Answer

Expert verified
It takes 200 seconds for a radio signal originating from Earth to reach Mars, based on the given distance of 60 million km and the speed of light \( (3 \times 10^5\) km/s).

Step by step solution

01

Given Information

First, let's write down the information given in the problem: Distance from Earth to Mars = 60 million km Speed of radio signals (speed of light, c) = 300,000 km/s We need to find the time taken for a radio signal to cover this distance at the said speed.
02

Set up the equation

The formula for calculating the time taken to travel a certain distance is: time = distance / speed In this case, we need to find the time taken to travel the distance between Earth and Mars, which is 60 million km, at the speed of light, which is approximately 300,000 km/s. So the equation becomes: time = (60 million km) / (300,000 km/s)
03

Solve the equation

Now, let's solve the equation by plugging in the given values: time = (60 x 10^6 km) / (300,000 km/s) time = 200 s So, it takes 200 seconds for a radio signal originating from Earth to reach Mars.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Speed of Light
The speed of light is one of the fundamental constants in physics and is critically important in various calculations involving space and time. Light travels at an incredible speed of approximately 300,000 kilometers per second (km/s) in a vacuum. This speed is denoted by the letter "c" and is universally acknowledged for its magnitude and unchanging nature.
  • Light can travel around the Earth approximately 7.5 times in one second due to this remarkable speed.
  • This constant speed applies to all electromagnetic waves, including radio waves.
Knowing the speed of light enables us to perform precise calculations in physics, such as determining time lags for signals sent across vast distances. The concept of the speed of light allows scientists to better understand distances in space and the time it takes for information to travel.
Radio Signal Transmission
Radio signal transmission is a key method of communication across vast distances, such as between Earth and Mars. When a signal is transmitted from an antenna on Earth, it travels as an electromagnetic wave at the speed of light.
  • Radio waves are a type of electromagnetic radiation, similar to visible light but with longer wavelengths.
  • The transmission speed of these signals is also determined by the speed of light.
The ability to transmit signals at the speed of light means that the delay in receiving a message from Mars depends purely on the distance between the two planets. This understanding helps in planning communication tasks, such as sending commands to rovers or receiving data from space missions.
Distance Calculation
Calculating the distance between two points, such as Earth and Mars, is essential for understanding the time it takes signals to travel. Distance is often measured in kilometers when discussing astronomical distances. In this exercise, we know:
  • The distance from Earth to Mars is approximately 60 million kilometers.
Distance is a straightforward yet crucial variable in solving problems where time and speed are involved. Accurate distance measurements are essential in ensuring precise calculations for signal transmission timing and other space-related computations.
The relationship between distance, speed, and time is widely used in physics to determine any of these variables when the other two are known.
Time Calculation
Time calculation in this scenario involves determining how long it takes a radio signal to travel from Earth to Mars. By using the formula \( \text{time} = \frac{\text{distance}}{\text{speed}} \), we can solve for the time variable easily when distance and speed are known.
  • Substitute the known values: distance = 60 million km, speed = 300,000 km/s.
  • Perform the division: \( \text{time} = \frac{60 \times 10^6 \text{ km}}{300,000 \text{ km/s}} \).
  • The result is 200 seconds.
By understanding time calculation with this formula, students can apply this knowledge to similar physics problems involving movement across distances at constant speeds. Recognizing the role of speed and distance in determining travel time enhances problem-solving skills and provides a solid foundation for more advanced physics topics.

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Most popular questions from this chapter

When the excited electron in a hydrogen atom falls from \(n=5\) to \(n=2,\) a photon of blue light is emitted. If an excited electron in He \(^{+}\) falls from \(n=4,\) to which energy level must it fall so that a similar blue light (as with the hydrogen) is emitted? Prove it. (See Exercise \(174 . )\)

How many unpaired electrons are present in each of the following in the ground state: \(\mathrm{O}, \mathrm{O}^{+}, \mathrm{O}^{-}, \mathrm{Os}, \mathrm{Zr}, \mathrm{S}, \mathrm{F}, \mathrm{Ar}\) ?

An electron is excited from the \(n=1\) ground state to the \(n=\) 3 state in a hydrogen atom. Which of the following statements are true? Correct the false statements to make them true. a. It takes more energy to ionize (completely remove) the electron from \(n=3\) than from the ground state. b. The electron is farther from the nucleus on average in the \(n=3\) state than in the \(n=1\) state. c. The wavelength of light emitted if the electron drops from \(n=3\) to \(n=2\) will be shorter than the wavelength of light emitted if the electron falls from \(n=3\) to \(n=1 .\) d. The wavelength of light emitted when the electron returns to the ground state from \(n=3\) will be the same as the wavelength of light absorbed to go from \(n=1\) to \(n=3\) e. For \(n=3,\) the electron is in the first excited state.

Although no currently known elements contain electrons in g orbitals in the ground state, it is possible that these elements will be found or that electrons in excited states of known elements could be in \(g\) orbitals. For \(g\) orbitals, the value of \(\ell\) is \(4 .\) What is the lowest value of \(n\) for which \(g\) orbitals could exist? What are the possible values of \(m_{\ell} ?\) How many electrons could a set of \(g\) orbitals hold?

It takes 208.4 kJ of energy to remove 1 mole of electrons from an atom on the surface of rubidium metal. How much energy does it take to remove a single electron from an atom on the surface of solid rubidium? What is the maximum wavelength of light capable of doing this?

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