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Explain why ΔH is obtained directly from coffee-cup calorimeters, whereas ΔE is obtained directly from bomb calorimeters.

Short Answer

Expert verified
Coffee-cup calorimeters measure heat changes at constant pressure (isobaric conditions), which is directly related to the enthalpy change (∆H) of the reaction. On the other hand, bomb calorimeters measure heat changes at constant volume (isochoric conditions), which is directly related to the internal energy change (∆E) of the reaction. Therefore, ∆H is obtained directly from coffee-cup calorimeters, whereas ∆E is obtained directly from bomb calorimeters.

Step by step solution

01

Understanding Coffee-cup Calorimeters

Coffee-cup calorimeters are simple, open-system calorimeters that are well insulated to minimize heat exchange with the surroundings. As a result, these calorimeters measure heat changes at constant pressure (isobaric conditions). Hence, the heat change measured by a coffee-cup calorimeter is directly related to the enthalpy change (∆H) of the reaction.
02

Understanding Bomb Calorimeters

Bomb calorimeters, on the other hand, are closed-system calorimeters that consist of a sealed metal container called a "bomb" in which the reaction takes place, submerged in a known amount of water. The pressure inside the bomb is allowed to increase as the reaction proceeds, but the volume is kept constant. As a result, bomb calorimeters measure heat changes at constant volume (isochoric conditions). The heat change measured at constant volume is directly related to the internal energy change (∆E) of the reaction.
03

Comparing Coffee-cup and Bomb Calorimeters

To summarize, coffee-cup calorimeters measure heat changes at constant pressure, while bomb calorimeters measure heat changes at constant volume. Since enthalpy changes (∆H) occur at constant pressure and internal energy changes (∆E) occur at constant volume, we can conclude that ∆H is obtained directly from coffee-cup calorimeters and ∆E is obtained directly from bomb calorimeters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enthalpy Change
Enthalpy change, denoted as ΔH, represents the heat absorbed or released during a chemical reaction at constant pressure. It is a crucial concept in thermodynamics because most chemical reactions in laboratories and industry occur at constant pressure.
  • When a reaction gives off heat, it is exothermic, and ΔH is negative.
  • If it absorbs heat, it is endothermic, and ΔH is positive.
In real-world applications, enthalpy is preferred because it considers not only the internal energy change but also the work done by the system as it expands or contracts against the atmospheric pressure. This makes enthalpy an essential part of understanding how much energy a reaction releases or consumes.
Internal Energy
Internal energy, symbolized as ΔE, refers to the total energy change within a system. It includes all forms of energy, like kinetic and potential energy, that contribute to the system's overall energy state.
  • In a closed system, the only changes in energy are due to heat exchange and work done.
  • Unlike enthalpy, internal energy does not account for pressure-volume work.
This makes internal energy a simpler concept, directly linked to heat in a constant volume setting, providing clarity when experiments are designed in a closed container, like a bomb calorimeter. Here, ΔE becomes crucial for understanding how energy is conserved in a reaction.
Constant Pressure
Constant pressure conditions, or isobaric conditions, are used in coffee-cup calorimeters to measure enthalpy changes. Under these conditions, pressure remains unchanged while heat is absorbed or released.
  • Common in everyday scenarios, as atmospheric pressure often remains constant.
  • Allows for the direct measurement of ΔH without needing to adjust for pressure changes.
Operating under constant pressure is practical in experimental setups because it mirrors common laboratory conditions more closely, making data easy to interpret. This makes constant pressure an essential concept when determining the heat dynamics of reactions using simpler calorimeters.
Constant Volume
In constant volume or isochoric conditions, the volume of the system does not change during a reaction. Bomb calorimeters use this setup as their heavy-duty design ensures no expansion or contraction.
  • This makes it easier to measure changes in internal energy ΔE.
  • Pressure may vary but does not affect the direct calculation of ΔE.
Constant volume conditions are ideal for reactions involving gases, where pressure changes would complicate measurements. The robust construction of bomb calorimeters makes them perfect for obtaining precise energy change readings by focusing purely on internal energy shifts.

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Most popular questions from this chapter

Calculate ΔH for the reaction: 2NH3(g)+12O2(g)N2H4(l)+H2O(l) given the following data: 2NH3(g)+3N2O(g)4N2(g)+3H2O(l) ΔH=1010.kJ N2O(g)+3H2(g)N2H4(l)+H2O(l) ΔH=317kJ N2H4(l)+O2(g)N2(g)+2H2O(l) ΔH=623kJ H2(g)+12O2(g)H2O(l) ΔH=286kJ

Consider the following reaction: 2H2(g)+O2(g)2H2O(l)ΔH=572kJ a. How much heat is evolved for the production of 1.00 mole of H2O(l)? b. How much heat is evolved when 4.03 g hydrogen are reacted with excess oxygen? c. How much heat is evolved when 186 g oxygen are reacted with excess hydrogen? d. The total volume of hydrogen gas needed to fill the Hindenburg was 2.0×108L at 1.0 atm and 25C. How much heat was evolved when the Hindenburg exploded, assuming all of the hydrogen reacted?

A coffee-cup calorimeter initially contains 125 g water at 24.2C. Potassium bromide (10.5g), also at 24.2C, is added to the water, and after the KBr dissolves, the final temperature is 21.1C . Calculate the enthalpy change for dissolving the salt in J/g and kJ/mol . Assume that the specific heat capacity of the solution is 4.18 J/Cg and that no heat is transferred to the surroundings or to the calorimeter.

The enthalpy change for the reaction CH4(g)+2O2(g)CO2(g)+2H2O(l) is 891kJ for the reaction as written. a. What quantity of heat is released for each mole of water formed? b. What quantity of heat is released for each mole of oxygen reacted?

Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 40.cm3. If the combustion of this mixture releases 950.J of energy, to what volume will the gases expand against a constant pressure of 650 . torr if all the energy of combustion is converted into work to push back the piston?

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