Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In the equation \(w=-P \Delta V,\) why is there a negative sign?

Short Answer

Expert verified
The negative sign in the equation \(w = -P \Delta V\) holds physical significance to indicate the direction of work done and the associated transfer of energy during a gas's volume change. When the gas expands (\(\Delta V > 0\)), it performs work on its surroundings, and the system loses energy, resulting in a negative value for work. Conversely, when the gas is compressed (\(\Delta V < 0\)), work is done on the gas, transferring energy into the system, yielding a positive value for work. Without the negative sign, the relationship between work, pressure, and volume change in thermodynamics would be misrepresented.

Step by step solution

01

Concepts Involved

In thermodynamics, we study the work done by or on a gas when it undergoes a change in volume under the influence of pressure. The equation given is \(w = -P \Delta V\), where \(w\) represents the work done, \(P\) represents the pressure, and \(\Delta V\), the change in volume.
02

Significance of Negative Sign

The negative sign in the equation \(w = -P \Delta V\) has a physical significance relating to the direction of work done. Work is said to be done on a system when energy is transferred into the system, and work is said to be done by the system when energy is transferred out of the system. In the context of this equation, a positive change in volume (\(\Delta V > 0\)) represents an expansion of the gas, indicating that work is done by the gas to push its surroundings outward. In this case, the gas is doing the work, and the system loses energy. As a result, we assign a negative sign to the work done in this case. On the other hand, a negative change in volume (\(\Delta V < 0\)) represents a compression of the gas, indicating that work is done on the gas by the surroundings. In this case, energy is transferred into the system, and we assign a positive value to the work done in this case.
03

Concluding the Significance

The negative sign in the equation \(w = -P \Delta V\) is essential to indicate the direction of work done and the associated transfer of energy. A negative sign signifies that the gas is transferring energy out of the system (work done by the gas), and a positive sign signifies that the gas is receiving energy from the surroundings (work done on the gas). Without the negative sign, the equation would not correctly represent the relationship between work, pressure, and volume change in thermodynamics.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which has the greater kinetic energy, an object with a mass of 2.0 \(\mathrm{kg}\) and a velocity of 1.0 \(\mathrm{m} / \mathrm{s}\) or an object with a mass of 1.0 \(\mathrm{kg}\) and a velocity of 2.0 \(\mathrm{m} / \mathrm{s}\) ?

A piston performs work of \(210 . \mathrm{L} \cdot\) atm on the surroundings, while the cylinder in which it is placed expands from \(10 . \mathrm{L}\) to 25 \(\mathrm{L}\) . At the same time, 45 \(\mathrm{J}\) of heat is transferred from the surroundings to the system. Against what pressure was the piston working?

Quinone is an important type of molecule that is involved in photosynthesis. The transport of electrons mediated by quinone in certain enzymes allows plants to take water, carbon dioxide, and the energy of sunlight to create glucose. A 0.1964 -g sample of quinone \(\left(\mathrm{C}_{6} \mathrm{H}_{4} \mathrm{O}_{2}\right)\) is burned in a bomb calorimeter with a heat capacity of 1.56 \(\mathrm{kJ} / \mathrm{C}\) . The temperature of the calorimeter increases by \(3.2^{\circ} \mathrm{C}\) . Calculate the energy of combustion of quinone per gram and per mole.

Calculate the internal energy change for each of the following. a. One hundred \((100 .)\) joules of work is required to compress a gas. At the same time, the gas releases 23 \(\mathrm{J}\) of heat. b. A piston is compressed from a volume of 8.30 \(\mathrm{L}\) to 2.80 \(\mathrm{L}\) against a constant pressure of 1.90 \(\mathrm{atm}\) . In the process, there is a heat gain by the system of 350. J. c. A piston expands against 1.00 atm of pressure from 11.2 \(\mathrm{L}\) to 29.1 \(\mathrm{L}\) . In the process, 1037 \(\mathrm{J}\) of heat is absorbed.

The preparation of \(\mathrm{NO}_{2}(g)\) from \(\mathrm{N}_{2}(g)\) and \(\mathrm{O}_{2}(g)\) is an endothermic reaction: $$ \mathrm{N}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{NO}_{2}(g)(\text { unbalanced }) $$ The enthalpy change of reaction for the balanced equation (with lowest whole- number coefficients) is \(\Delta H=67.7 \mathrm{kJ}\) . If \(2.50 \times 10^{2} \mathrm{mL} \mathrm{N}_{2}(g)\) at \(100 .^{\circ} \mathrm{C}\) and 3.50 atm and \(4.50 \times\) \(10^{2} \mathrm{mL} \mathrm{O}_{2}(g)\) at \(100 .^{\circ} \mathrm{C}\) and 3.50 atm are mixed, what amount of heat is necessary to synthesize the maximum yield of \(\mathrm{NO}_{2}(g) ?\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free