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Calculate the average kinetic energies of \(\mathrm{CH}_{4}(g)\) and \(\mathrm{N}_{2}(g)\) molecules at 273 \(\mathrm{K}\) and 546 \(\mathrm{K} .\)

Short Answer

Expert verified
At 273K, the average kinetic energies of both CH4(g) and N2(g) are \(KE_{avg(CH_4, 273K)} = KE_{avg(N_2, 273K)} = 5.60 \times 10^{-21}\) J. At 546K, their average kinetic energies are \(KE_{avg(CH_4, 546K)} = KE_{avg(N_2, 546K)} = 1.12 \times 10^{-20}\) J.

Step by step solution

01

Identify the given information

We are given the following information: - The temperatures: 273K and 546K - The Boltzmann constant: \(1.38 \times 10^{-23}~ J/mol~K\) We will use this information to find the average kinetic energies of CH4 and N2 molecules.
02

Calculate the average kinetic energy at 273K

Using the formula for the average kinetic energy, we will find the avg. kinetic energy for both CH4 and N2 molecules at 273K: \(KE_{avg}=\dfrac{3}{2}kT\) For CH4(g) at 273K: \(KE_{avg(CH_4, 273K)}=\dfrac{3}{2}(1.38 \times 10^{-23}~ J/mol~K)(273~K) = \) For N2(g) at 273K: \(KE_{avg(N_2, 273K)}=\dfrac{3}{2}(1.38\times10^{-23}~ J/mol~K)(273~K) = \) Since both molecules are at the same temperature (273K), their average kinetic energies will be the same.
03

Calculate the average kinetic energy at 546K

Using the same formula, we will find the average kinetic energy for CH4 and N2 molecules at 546K: \(KE_{avg}=\dfrac{3}{2}kT\) For CH4(g) at 546K: \(KE_{avg(CH_4, 546K)}=\dfrac{3}{2}(1.38\times10^{-23}~ J/mol~K)(546~K) = \) For N2(g) at 546K: \(KE_{avg(N_2, 546K)}=\dfrac{3}{2}(1.38\times10^{-23}~ J/mol~K)(546~K) = \) As in step 2, since both molecules are at the same temperature (546K), their average kinetic energies will be the same.
04

Finalize the answers

We have calculated the average kinetic energies of CH4 and N2 gas molecules at given temperatures. At 273K: - CH4(g): \(KE_{avg(CH_4, 273K)} = \) J - N2(g): \(KE_{avg(N_2, 273K)} = \) J At 546K: - CH4(g): \(KE_{avg(CH_4, 546K)} = \) J - N2(g): \(KE_{avg(N_2, 546K)} = \) J

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boltzmann Constant
The Boltzmann constant is a fundamental physical constant that connects the macroscopic and microscopic physical worlds. It is denoted by the symbol \(k\) and has a value of approximately \(1.38 \times 10^{-23} \, J/K\). This constant plays a crucial role in statistical mechanics and thermodynamics.

In the context of gases, the Boltzmann constant helps in determining the average kinetic energy of particles. It's particularly useful for calculating properties of individual molecules within gases. When computing the average kinetic energy of gas molecules, we use the formula:
  • \(KE_{avg} = \dfrac{3}{2}kT\)
where \(T\) is the temperature in Kelvin.

Understanding the Boltzmann constant enables us to bridge the gap between bulk thermodynamic quantities, such as temperature, and the behavior of individual particles, giving us insight into molecular motion.
Temperature
Temperature is a measure of the average kinetic energy of the particles in a substance. It's a fundamental concept in thermodynamics that dictates how energy spreads within and between systems. Measured in Kelvin (K), it is directly proportional to the average energy per degree of freedom of the particles.

In gases, increasing the temperature increases the average kinetic energy of the gas molecules. This is why the average kinetic energy formula \(KE_{avg} = \dfrac{3}{2}kT\) includes temperature as a direct multiplier. By knowing the temperature, we can determine how much energy gas molecules have on average.

Understanding temperature helps us comprehend how changes in thermal energy affect molecular speed and, consequently, properties like pressure and volume in gases under the ideal gas law.
Gas Molecules
Gas molecules are in constant, random motion, and their behavior is essential for understanding the properties of gases. These small particles, like those of
  • Methane (\(CH_4\)), and
  • Nitrogen (\(N_2\))
obey the kinetic molecular theory. This theory asserts that gas molecules are in perpetual motion, colliding elastically with each other and the walls of their container, which creates pressure.

Given temperatures, such as 273 K and 546 K, can significantly influence gas molecule behavior. At these conditions, the average kinetic energy of gas molecules can be calculated and demonstrates how temperature affects molecular movement. With formulas involving the Boltzmann constant, we can determine how energetic these molecules are under different thermodynamic conditions.

This understanding allows us to predict the behavior and properties of gases in diverse conditions, which is vital for both scientific and practical applications.

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Most popular questions from this chapter

An organic compound contains \(\mathrm{C}, \mathrm{H}, \mathrm{N},\) and \(\mathrm{O}\) . Combustion of 0.1023 \(\mathrm{g}\) of the compound in excess oxygen yielded 0.2766 \(\mathrm{g} \mathrm{CO}_{2}\) and 0.0991 \(\mathrm{g} \mathrm{H}_{2} \mathrm{O} .\) A sample of 0.4831 \(\mathrm{g}\) of the compound was analyzed for nitrogen by the Dumas method (see Exercise 137\() .\) At STP, 27.6 \(\mathrm{mL}\) of dry \(\mathrm{N}_{2}\) was obtained. In a third experiment, the density of the compound as a gas was found to be 4.02 \(\mathrm{g} / \mathrm{L}\) at \(127^{\circ} \mathrm{C}\) and 256 torr. What are the empirical and molecular formulas of the compound?

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