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Many over-the-counter antacid tablets are now formulated using calcium carbonate as the active ingredient, which enables such tablets to also be used as dietary calcium supplements. As an antacid for gastric hyperacidity, calcium carbonate reacts by combining with hydrochloric acid found in the stomach, producing a solution of calcium chloride, converting the stomach acid to water, and releasing carbon dioxide gas (which the person suffering from stomach problems may feel as a “burp”). Write the balanced chemical equation for this process.

Short Answer

Expert verified
The balanced chemical equation for the reaction between calcium carbonate and hydrochloric acid is: \( CaCO_3 + 2HCl \rightarrow CaCl_2 + 2H_2O + CO_2 \)

Step by step solution

01

Identify the Chemical Formulas of the Reactants and Products.

We have the following reactants and products: 1. Calcium carbonate (CaCO3): Reactant 2. Hydrochloric acid (HCl): Reactant 3. Calcium chloride (CaCl2): Product 4. Water (H2O): Product 5. Carbon dioxide (CO2): Product
02

Write the Unbalanced Chemical Equation.

Now that we have the chemical formulas for the reactants and products, we can write the unbalanced chemical equation: CaCO3 + HCl -> CaCl2 + H2O + CO2
03

Balance the Chemical Equation.

To balance the chemical equation, we need to equalize the number of atoms of each element on both sides of the equation. Currently, the equation is unbalanced as there are two chlorine atoms on the product side, while only one chlorine atom is on the reactant side. Similarly, there are two hydrogen atoms on the reactant side, while only one hydrogen atom is on the product side. To balance the equation, we need to multiply the number of molecules of hydrochloric acid (HCl) by 2 and the number of molecules of water (H2O) by 2: CaCO3 + 2HCl -> CaCl2 + 2H2O + CO2 Now the equation is balanced as there are equal numbers of atoms of each element on both sides: 1 calcium atom: 1 (reactants) = 1 (products) 1 carbon atom: 1 (reactants) = 1 (products) 3 oxygen atoms: 3 (reactants) = 3 (products) 2 hydrogen atoms: 2 (reactants) = 2 (products) 2 chlorine atoms: 2 (reactants) = 2 (products)
04

Write the Balanced Chemical Equation.

The balanced chemical equation for the reaction between calcium carbonate and hydrochloric acid is: CaCO3 + 2HCl -> CaCl2 + 2H2O + CO2

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balancing Chemical Equations
Balancing chemical equations is a fundamental skill in chemistry. It's how you ensure that the number of atoms for each element remains the same on both sides of a chemical equation. Imagine it like a seesaw, where you want everything perfectly balanced!

When we're talking about balancing equations, what we're doing is making sure that the mass and the charge are conserved—nothing gets lost in the process of a chemical reaction.
  • First, identify all the reactants and products involved in the reaction.
  • Write down their chemical formulas before adding coefficients to balance the equation.
  • Always balance one element at a time, often starting with metals or the most complex molecule.
In our example of calcium carbonate reacting with hydrochloric acid, the initial unbalanced equation was:\[ \text{CaCO}_3 + \text{HCl} \rightarrow \text{CaCl}_2 + \text{H}_2\text{O} + \text{CO}_2 \]

By using coefficients to balance the number of each atom on both sides, we achieved:\[ \text{CaCO}_3 + 2\text{HCl} \rightarrow \text{CaCl}_2 + 2\text{H}_2\text{O} + \text{CO}_2 \]

Now, each element has the same number of atoms on both sides! This means the chemical reaction can be accurately represented and understood.
Acid-Base Reactions
Acid-base reactions are a class of chemical reactions that occur between an acid and a base. These reactions are important because they often result in the formation of water and a salt. Think of it as a neutralization reaction where the sting of an acid is neutralized by the soothing nature of a base.

In our example, hydrochloric acid \((\text{HCl})\) is the acid, and calcium carbonate \((\text{CaCO}_3)\) acts as the base. When these two react, they neutralize each other:
  • The hydrogen from \(\text{HCl}\) combines with the carbonate \((\text{CO}_3^{2-})\) from \(\text{CaCO}_3\) to form water \((\text{H}_2\text{O})\).
  • Calcium ions \((\text{Ca}^{2+})\) combine with chloride ions \((\text{Cl}^-)\) to form calcium chloride \((\text{CaCl}_2)\).
This process also releases carbon dioxide gas \((\text{CO}_2)\), which is why these reactions can cause fizzy sensations or burps in the context of taking an antacid.

This type of reaction not only helps with indigestion but also exemplifies the fascinating interactions between acids and bases.
Calcium Carbonate
Calcium carbonate is a common chemical compound with the formula \(\text{CaCO}_3\). It's a versatile substance found naturally in rocks like limestone, marble, and chalk, as well as in the shells of marine organisms, eggs, and snails.

In the world of chemistry and everyday life, calcium carbonate holds numerous roles:
  • Used as a dietary calcium supplement: It contributes to bone health and the function of cells.
  • As an antacid: Neutralizes stomach acidity, providing relief from indigestion and heartburn.
  • In industry: It's utilized in the manufacture of cement and the purification of iron in blast furnaces.
Calcium carbonate's reaction with acids like hydrochloric acid is well-noted in educational syllabi due to its straightforward yet illustrative chemical reactions. This makes \(\text{CaCO}_3\) a perfect exemplar to reflect upon when learning about both chemical reactions and their balanced equations. Its ability to react and transform products efficiently highlights the practical importance of chemistry in everyday scenarios.

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Most popular questions from this chapter

Chlorisondamine chloride \(\left(\mathrm{C}_{14} \mathrm{H}_{20} \mathrm{Cl}_{6} \mathrm{N}_{2}\right)\) is a drug used in the treatment of hypertension. A 1.28-g sample of a medication containing the drug was treated to destroy the organic material and to release all the chlorine as chloride ion. When the filtered solution containing chloride ion was treated with an excess of silver nitrate, 0.104 g silver chloride was recovered. Calculate the mass percent of chlorisondamine chloride in the medication, assuming the drug is the only source of chloride.

When hydrochloric acid reacts with magnesium metal, hydrogen gas and aqueous magnesium chloride are produced. What volume of 5.0 M HCl is required to react completely with 3.00 g of magnesium?

What mass of \(\mathrm{Na}_{2} \mathrm{CrO}_{4}\) is required to precipitate all of the silver ions from 75.0 mL of a 0.100-M solution of \(\mathrm{AgNO}_{3} ?\)

A 100.0-mL aliquot of 0.200 M aqueous potassium hydroxide is mixed with 100.0 mL of 0.200 M aqueous magnesium nitrate. a. Write a balanced chemical equation for any reaction that occurs. b. What precipitate forms? c. What mass of precipitate is produced? d. Calculate the concentration of each ion remaining in solution after precipitation is complete.

The blood alcohol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) level can be determined by tirrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of \(\mathrm{Cr}^{3+}(a q)\) and carbon dioxide. The reaction can be monitored because the dichromate ion \(\left(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\right)\) is orange in solution, and the \(\mathrm{Cr}^{3+}\) ion is green. The unbalanced redox equation is $$\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q)+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(a q) \rightarrow \mathrm{Cr}^{3+}(a q)+\mathrm{CO}_{2}(g)$$ If 31.05 \(\mathrm{mL}\) of 0.0600\(M\) potassium dichromate solution is required to titrate 30.0 \(\mathrm{g}\) of blood plasma, determine the mass percent of alcohol in the blood.

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