Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Name all of the aldehydes and ketones that have the formula \(\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}\) .

Short Answer

Expert verified
The aldehydes and ketones with the formula \(\mathrm{C}_{4}\mathrm{H}_{8}\mathrm{O}\) are butanal, propanone, and 2-butanone.

Step by step solution

01

Understanding aldehydes and ketones structures

The aldehydes and ketones are organic molecules containing a carbonyl group (C=O) as a functional group. The main difference between them is: - In an aldehyde, the carbonyl group is situated at the end of a carbon chain. - In a ketone, the carbonyl group is situated within the carbon chain, with two carbons attached to it.
02

Generate possible structures with C4H8O

Moving on, let's start creating the possible isomers of aldehydes and ketones with the molecular formula C4H8O. For aldehydes, the carbonyl group must be at the end of the carbon chain. So, the possible structures for aldehydes are: 1. HCHOCH2CH2CH3 For ketones, the carbonyl group must be within the carbon chain. Let's find the number of possible structures for ketones: 1. CH3COCH2CH3 2. CH3CH2COCH3
03

Naming the structures

Now, we have to name these generated structures using IUPAC nomenclature rules. For the aldehyde structure: 1. HCHOCH2CH2CH3 is butanal. For the ketone structures: 1. CH3COCH2CH3 is propanone. 2. CH3CH2COCH3 is 2-butanone (Notice that we mention the position of the carbonyl group in the name since ketones can have more than one possible structure with different carbonyl positions). Final Answer: The aldehydes and ketones with the formula C4H8O are butanal, propanone, and 2-butanone.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Aldehydes
Aldehydes are a crucial group of organic compounds characterized by the presence of a carbonyl group (C=O) located at the end of the carbon chain. This specific positioning makes their chemistry unique and interesting. The general formula for an aldehyde is \( ext{RCHO}\), where R represents the rest of the hydrocarbon chain, and the carbonyl carbon is always attached to a hydrogen atom.

In the case of our exercise, we have an aldehyde with the formula \( ext{C}_4 ext{H}_8 ext{O}\). The structure that corresponds to this formula is butanal. Butanal is the simplest aldehyde containing four carbon atoms. Here, the carbonyl group is at the terminal carbon, which aligns with the typical aldehyde structure. Understanding aldehydes involves knowing their reactivity due to the polar nature of the carbonyl group. The positive partial charge on the carbon makes it an excellent site for nucleophilic attack, which is a common reaction pattern in organic chemistry.
Ketones
Ketones are another class of organic compounds that, like aldehydes, contain a carbonyl group (C=O). Unlike aldehydes, in ketones, the carbonyl group is situated within the carbon chain, meaning it is bonded to two carbon atoms. This places ketones in a slightly different reactivity category compared to aldehydes.

The general formula for a ketone is \( ext{RCOR}'\), where both R and \('R)\)' represent separate hydrocarbon chains, which could be similar or different. In terms of structure, ketones are less reactive than aldehydes because the carbonyl carbon, being sandwiched between two alkyl groups, is less accessible to nucleophiles.

In our exercise, two ketone structures were determined with the formula \( ext{C}_4 ext{H}_8 ext{O}\): propanone and 2-butanone. Propanone is the simplest ketone known as acetone, and 2-butanone is also commonly known as methyl ethyl ketone (MEK). The naming involves indicating the position of the carbonyl group, crucial for distinguishing between potential isomers.
Isomerism
Isomerism is a fascinating concept in organic chemistry that explains how molecules with the same molecular formula can have different structures. This leads to different physical and chemical properties. There are several types of isomerism, but for aldehydes and ketones, we focus on structural isomerism.

Structural isomerism occurs when molecules share the same formula but differ in the connectivity of their atoms. In our exercise with the formula \( ext{C}_4 ext{H}_8 ext{O}\), we can see that butanal, propanone, and 2-butanone are structural isomers. They all have the same number of carbon, hydrogen, and oxygen atoms but differ in how these atoms are arranged.

Recognizing isomers is crucial for understanding organic reactions since each isomer may react differently under the same conditions. It's this ability to rearrange atoms that makes organic chemistry so rich and diverse in reactions and possibilities.
Organic Chemistry
Organic chemistry is the branch of chemistry that studies carbon-containing compounds, their properties, structures, reactions, and synthesis. This broad field encompasses millions of compounds, including everything from simple molecules like methane to complex biopolymers such as proteins and DNA.

The study of organic chemistry involves understanding the behavior of different functional groups, like carbonyl groups found in both aldehydes and ketones. The unique properties of carbon, such as its ability to form four covalent bonds, its versatility in creating chains and rings, and its compatibility with many heteroatoms, make organic chemistry both challenging and rewarding.

Skills in organic chemistry include naming compounds using the IUPAC nomenclature, predicting reactivity and products, and proposing synthetic routes for complex molecules. By grasping these skills, you unlock the ability to innovate in areas such as pharmaceuticals, materials science, and biotechnology.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Draw the structural formula for each of the following. a. formaldehyde (methanal) b. 4-heptanone c. 3-chlorobutanal d. 5,5-dimethyl-2-hexanone

Give an example of a hydrocarbon that, in theory, exhibits each of the following bond angles: \(60^{\circ}, 90^{\circ}, 109.5^{\circ}, 120^{\circ},\) and \(180^{\circ} .\)

Reagents such as \(\mathrm{HCl}\) , HBr, and \(\mathrm{HOH}\left(\mathrm{H}_{2} \mathrm{O}\right)\) can add across carbon-carbon double and triple bonds, with \(\mathrm{H}\) forming a bond to one of the carbon atoms in the multiple bond and \(\mathrm{Cl}\) , Br, or OH forming a bond to the other carbon atom in the multiple bond. In some cases, two products are possible. For the major organic product, the addition occurs so that the hydrogen atom in the reagent attaches to the carbon atom in the multiple bond that already has the greater number of hydrogen atoms bonded to it. With this rule in mind, draw the structure of the major product in each of the following reactions.

Glucose can occur in three forms: two cyclic forms and one open-chain structure. In aqueous solution, only a tiny fraction of the glucose is in the open-chain form. Yet tests for the presence of glucose depend on reaction with the aldehyde group, which is found only in the open-chain form. Explain why these tests work.

Structural and optical isomers can be drawn having the formula \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{F}\) . Give examples to illustrate these types of isomerism for \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{F}\) . Why can't \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{F}\) exhibit geometrical isomerism?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free