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Name all of the alcohols that have the formula \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\) . How many ethers have the formula \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O} ?\)

Short Answer

Expert verified
There are 4 alcohols with the formula C4H10O: 1-butanol, 2-butanol, 2-methyl-1-propanol, and 1-methyl-1-propanol. There are 3 ethers with the same formula: methyl propyl ether, propyl methyl ether, and diethyl ether.

Step by step solution

01

Analyze the structure of alcohols

Alcohols have the general formula CnH2n+1OH, where n represents the number of carbon atoms. In our case, the formula given is C4H10O. So, there are 4 carbon atoms present, and the alcohol functional group (OH) will be attached to one of these.
02

Identify and draw isomers of C4H10O alcohols

To find all structural isomers of C4H10O alcohols, we will attach the OH group to each carbon atom in the C4H9 chain one at a time. There are 4 alcohols that can be formed this way. 1. 1-butanol: OH is attached to the first carbon atom. 2. 2-butanol: OH is attached to the second carbon atom. 3. 2-methyl-1-propanol: A branching occurs, with the OH group attached to the first carbon atom and a methyl group on the second carbon atom. 4. 1-methyl-1-propanol: This isomer also has a branching, with the OH group attached to the first carbon atom and a methyl group on the second carbon atom. These are all the possible isomers for C4H10O alcohols.
03

Analyze the structure of ethers

Ethers have the general formula R-O-R', where R and R' are alkyl groups. In our case, since the formula is C4H10O, the total number of carbon atoms in R and R' should add up to 4.
04

Identify and count isomers of C4H10O ethers

Keeping the general formula of ethers (R-O-R') in mind, we will find all possible combinations of R and R' where the total number of carbons add up to 4: 1. R = methyl group (1 carbon) and R' = propyl group (3 carbons) 2. R = propyl group (3 carbons) and R' = methyl group (1 carbon) 3. R = ethyl group (2 carbons) and R' = ethyl group (2 carbons) These combinations give us 3 isomers for ethers with the formula C4H10O. Answer: There are 4 possible alcohols with the formula C4H10O: 1-butanol, 2-butanol, 2-methyl-1-propanol, and 1-methyl-1-propanol. There are 3 possible ethers with the same formula: methyl propyl ether, propyl methyl ether, and diethyl ether.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alcohol Isomers
In organic chemistry, isomers refer to compounds that have the same molecular formula but different structural arrangements. Alcohols are organic compounds that contain a hydroxyl group (-OH) attached to a carbon atom. When examining alcohol isomers of the formula \(\mathrm{C}_{4} \mathrm{H}_{10}\mathrm{O}\), there are multiple ways of structuring these atoms based on the position of the hydroxyl group.

Key considerations for alcohol isomers include:
  • The placement of the OH group, which can be attached to different carbon atoms in a molecule, influencing the type of alcohol.
  • Possible branching in the carbon chain that results in structural variations without changing the overall molecular formula.
For \(\mathrm{C}_{4} \mathrm{H}_{10}\mathrm{O}\), there are 4 different alcohol isomers:
  • 1-butanol: The hydroxyl group is bonded to the first carbon atom, leading to a straight-chain alcohol.
  • 2-butanol: Here, the OH is attached to the second carbon, making it a secondary alcohol.
  • 2-methyl-1-propanol: This molecule features a branch with the hydroxyl group at the first carbon and a methyl group on the second.
  • 1-methyl-1-propanol: Similar to the previous isomer but with a different arrangement, showcasing the flexibility in structuring organic compounds.
Ether Isomers
Ethers are characterized by an oxygen atom connected to two alkyl or aryl groups. Unlike alcohols, ethers do not have a hydroxyl group; instead, they contain an ether bond \(\text{R-O-R'}\), where R and R' represent alkyl groups. This structural feature leads to a different set of isomers.

For the molecular formula \(\mathrm{C}_{4} \mathrm{H}_{10}\mathrm{O}\), the task is to mix the 4 carbons in various configurations for the ether isomers:
  • Methyl propyl ether (or propyl methyl ether): Both involve a mix of a 1-carbon group (methyl) and a 3-carbon group (propyl) attached to the oxygen atom. The name changes depending on which alkyl group is listed first in the naming convention.
  • Diethyl ether: Here, both groups on either side of the oxygen are ethyl groups, each containing two carbon atoms.
The number of ether isomers elucidates the different ways the carbon atoms can be assembled while maintaining the same basic formula. This variety showcases the diversity of organic chemistry.
Organic Chemistry Isomers
In the realm of organic chemistry, the concept of isomers is fundamental as it highlights how molecules with the same set of atoms can differ in the spatial arrangement and connectivity of those atoms. This principle is crucial for understanding the structural diversity and function of organic compounds.

There are several types of isomers, but for \(\mathrm{C}_{4} \mathrm{H}_{10}\mathrm{O}\), we focus mainly on:
  • Structural Isomers: These differ in the connectivity of the atoms. For example, alcohols and ethers both follow this category but differ due to the arrangement of the oxygen atom.
  • Functional Group Isomers: These involve major changes to the functional group in the molecule. For instance, alcohols and ethers are functional isomers of each other due to their differing functional groups (OH for alcohols, R-O-R' for ethers).
In organic chemistry education, understanding these variations helps students comprehend the nuances of molecular function and behavior. Recognizing isomers is crucial for applications ranging from pharmaceuticals to materials science. The study of isomers underlines the versatility and adaptability of organic compounds.

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Most popular questions from this chapter

In general terms, what does the tertiary structure of a protein represent? Distinguish between the secondary and tertiary structures of a protein.

Is the primary, secondary, or tertiary structure of a protein changed by denaturation?

Alcohols are very useful starting materials for the production of many different compounds. The following conversions, starting with 1-butanol, can be carried out in two or more steps. Show the steps (reactants/catalysts) you would follow to carry out the conversions, drawing the formula for the organic product in each step. For each step, a major product must be produced. (See Exercise \(68 . )\) (Hint: In the presence of \(\mathrm{H}^{+},\) an alcohol is converted into an alkene and water. This is the exact reverse of the reaction of adding water to an alkene to form an alcohol.) $$ \begin{array}{l}{\text { a. } 1 \text { -butanol } \longrightarrow \text { butane }} \\ {\text { b. } 1 \text { -butanol } \longrightarrow 2 \text { -butanone }}\end{array} $$

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