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Would it be better to use octahedral \(\mathrm{Ni}^{2+}\) complexes or octahe- dral \(\mathrm{Cr}^{2+}\) complexes to determine whether a given ligand is a strong-field or weak-field ligand by measuring the number of unpaired electrons? How else could the relative ligand field strengths be determined?

Short Answer

Expert verified
The \(\mathrm{Ni}^{2+}\) complex is better suited for determining if a ligand is strong-field or weak-field by measuring the number of unpaired electrons, as its electron configurations will show a difference in the number of unpaired electrons depending on the ligand type. This is not the case for the \(\mathrm{Cr}^{2+}\) complex. Alternative methods to determine ligand field strengths include comparing ligand-to-metal charge-transfer (LMCT) bands in UV-Visible spectroscopy, measuring the magnetic susceptibility of the complex, analyzing crystal field stabilization energies (CFSE), and comparing the stability constants of the complexes.

Step by step solution

01

Determine the electron configurations of \(\mathrm{Ni}^{2+}\) and \(\mathrm{Cr}^{2+}\)

To determine the electron configurations of these complexes, we first need to know their atomic number in the periodic table. Nickel (Ni) has an atomic number of 28 and chromium (Cr) has an atomic number of 24. When losing two electrons to form a 2+ ion, their electron configurations become: - For \(\mathrm{Ni}^{2+}\): \([Ar] 3d^8\) - For \(\mathrm{Cr}^{2+}\): \([Ar] 3d^4\) where [Ar] denotes the electron configuration of the Argon core. ##Step 2: Analyze the distribution of electrons in the respective complexes##
02

Compare the number of unpaired electrons in the \(\mathrm{Ni}^{2+}\) and \(\mathrm{Cr}^{2+}\) complexes

Now let's consider the complexes' electron distribution in an octahedral ligand field. In an octahedral field, we have 5 d-orbitals splitting into two energy levels: 3 lower energy \(t_{2g}\) orbitals and 2 higher energy \(e_g\) orbitals. - For the \(\mathrm{Ni}^{2+}\) complex: \([Ar] 3d^8\) will have 2 electrons in the \(e_g\) orbitals and 6 in the \(t_{2g}\) orbitals. In a strong-field ligand, all the \(t_{2g}\) orbitals will be filled (no unpaired electrons), while in a weak-field ligand, there will be 2 unpaired electrons in the \(t_{2g}\) orbitals. - For the \(\mathrm{Cr}^{2+}\) complex: \([Ar] 3d^4\) will have all the 4 electrons in the \(t_{2g}\) orbitals. In a strong-field ligand, all the \(t_{2g}\) orbitals will be filled (no unpaired electrons). However, in a weak-field ligand, there will also be no unpaired electrons, as the electrons will preferentially fill the \(t_{2g}\) orbitals before entering the higher-energy \(e_g\) orbitals, following Hund's rule. ##Step 3: Choose the best complex for determining ligand field strength##
03

Determine the best complex for identifying strong-field or weak-field ligands

Based on the above analysis, we see that the electron configurations of \(\mathrm{Ni}^{2+}\) complexes will exhibit a difference in the number of unpaired electrons depending on whether the ligand is strong-field or weak-field. In contrast, the electron configurations of \(\mathrm{Cr}^{2+}\) complexes will not show a difference in the number of unpaired electrons under either ligand condition. As a result, the best complex for determining whether a ligand is strong-field or weak-field would be the \(\mathrm{Ni}^{2+}\) complex. ##Step 4: Alternative methods to determine ligand field strengths##
04

Suggest other methods to determine ligand field strengths

Apart from measuring the number of unpaired electrons, other possible methods to determine the relative ligand field strengths include: 1. Comparing the ligand-to-metal charge-transfer (LMCT) bands in UV-Visible spectroscopy - strong-field ligands generally have more intense LMCT bands. 2. Measuring the magnetic susceptibility of the complex - complexes with more unpaired electrons will exhibit higher magnetic susceptibilities. 3. Comparing crystal field stabilization energies (CFSE) - complexes with strong-field ligands will generally have larger crystal field stabilization energies. 4. Analyzing the stability constants of the complexes - complexes with strong-field ligands will tend to have larger stability constants.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Octahedral Complexes
In the fantastic world of chemistry, octahedral complexes play a vital role. An octahedral complex is a type of coordination compound where a central metal atom is surrounded by six ligands. These ligands arrange themselves around the metal ion at the corners of an octahedron. This particular geometry is significant because it affects the way electron orbitals are split.
  • These complexes have a 3D geometric arrangement.
  • They are very common, especially for transition metals.
  • The octahedral shape influences the chemical properties and behaviors of the complex.
In an octahedral field, a metal's d-orbitals are split into two different energy levels due to the approach of the ligands. Understanding this split is key to predicting how the complex behaves, especially how electrons distribute in the available orbitals.
Electron Configuration
Electron configuration is the distribution of electrons of an atom or a molecule in atomic or molecular orbitals. For transition metals like Nickel (\(\mathrm{Ni}^{2+}\)), the electron configuration is crucial to understanding their chemical properties.
  • For \(\mathrm{Ni}^{2+}\): \([Ar] 3d^8\)
  • For \(\mathrm{Cr}^{2+}\): \([Ar] 3d^4\)
When the transition metals lose electrons to become cations (\(2+\) ions in this case), their electron configuration changes. This new configuration affects how they interact with ligands in complex formation.In octahedral complexes, the d-orbitals of these electrons get split into two levels: lower energy \(t_{2g}\) and higher energy \(e_g\). The specific electron configuration determines which orbitals the electrons will fill first. These configurations help to understand the number of unpaired electrons in a metal ion within a complex.
Strong-Field and Weak-Field Ligands
Ligands can dramatically alter the energy landscape of a metal complex. Depending on the electron-donating or withdrawing nature, ligands are classified as strong-field or weak-field. This classification significantly impacts the electron configuration and properties of the complex.
  • **Strong-Field Ligands:** Cause larger splitting of d-orbitals, pushing electrons to pair up in lower energy orbitals, resulting in fewer unpaired electrons.
  • **Weak-Field Ligands:** Lead to smaller splitting, allowing electrons to remain unpaired in various orbitals.
The ability of ligands to enhance or weaken the splitting of d-orbitals is crucial. A complex with strong-field ligands, for example, a \( \mathrm{Ni}^{2+}\) complex, will show fewer unpaired electrons because these ligands make electrons fill lower energy levels first. In contrast, weak-field ligands do not reduce the number of unpaired electrons significantly.
Unpaired Electrons
The concept of unpaired electrons is essential for understanding the magnetic properties of a compound. Unpaired electrons occur when there are electrons in an atom or ion that are not paired with another electron of opposite spin in the same orbital, leading to paramagnetism.
  • Unpaired electrons create a net magnetic moment.
  • Can be measured to determine the strength of the ligand field in a complex.
For octahedral complexes, the number of unpaired electrons can help determine whether a ligand is a strong-field or weak-field. For instance, in \( \mathrm{Ni}^{2+}\) complexes, the difference in unpaired electrons between strong-field and weak-field ligands is notable. Strong-field ligands tend to pair up electrons, resulting in lesser unpaired electrons, while weak-field ligands allow more unpaired electrons. This attribute is an important indicator when assessing the properties and behavior of complexes.

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Most popular questions from this chapter

\(\mathrm{CoCl}_{4}^{2-}\) forms a tetrahedral complex ion and \(\mathrm{Co}(\mathrm{CN})_{6}^{3-}\) forms an octahedral complex ion. What is wrong about the following statements concerning each complex ion and the \(d\) orbital splitting diagrams? a. \(\mathrm{CoCl}_{4}^{2-}\) is an example of a strong-field case having two unpaired electrons. b. Because \(\mathrm{CN}^{-}\) is a weak-field ligand, \(\mathrm{Co}(\mathrm{CN})_{6}^{3-}\) will be a low-spin case having four unpaired electrons.

Name the following complex ions. a. \(\operatorname{Ru}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}^{2+}\) b. \(\mathrm{Fe}(\mathrm{CN})_{6}^{4-}\) c. \(\mathrm{Mn}\left(\mathrm{NH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\right)_{3}^{2+}\) d. \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{55} \mathrm{NO}_{2}^{2+}\) e. \(\mathrm{Ni}(\mathrm{CN})_{4}^{2-}\) f. \(\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}^{+}\) g. \(\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}^{3-}\) h. \(\mathrm{Co}(\mathrm{SCN})_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}^{+}\)

Which of the following crystal field diagram(s) is(are) correct for the complex given? a. \(\mathrm{Zn}\left(\mathrm{NH}_{3}\right)_{4}^{2+}\) (tetrahedral) b. \(\operatorname{Mn}(\mathrm{CN})_{6}^{3-}\) (strong field) c. \(\mathrm{Ni}(\mathrm{CN})_{4}^{2-}\) (square planar, diamagnetic)

Compounds of \(\mathrm{Sc}^{3+}\) are not colored, but those of \(\mathrm{Ti}^{3+}\) and \(\mathrm{V}^{3+}\) are. Why?

When aqueous KI is added gradually to mercury(II) nitrate, an orange precipitate forms. Continued addition of KI causes the precipitate to dissolve. Write balanced equations to explain these observations. \(\left(\text {Hint} : \mathrm{Hg}^{2+} \text { reacts with } \mathrm{I}^{-} \text { to form } \mathrm{HgI}_{4}^{2-} .\right)\) Would you expect \(\mathrm{Hg} \mathrm{I}_{4}^{2-}\) to form colored solutions? Explain.

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