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One of the classic methods for the determination of the manganese content in steel involves converting all the manganese to the deeply colored permanganate ion and then measuring the absorption of light. The steel is first dissolved in nitric acid, producing the manganese(II) ion and nitrogen dioxide gas. This solution is then reacted with an acidic solution containing periodate ion; the products are the permanganate and iodate ions. Write balanced chemical equations for both of these steps.

Short Answer

Expert verified
The balanced chemical equations for determining the manganese content in steel are: 1. Mn(s)+2 HNO3(aq)Mn2+(aq)+2 NO2(g)+2 H+(aq) 2. 5 Mn2+(aq)+12 IO4(aq)+16 H+(aq)5 MnO4(aq)+12 IO3(aq)+8 H2O(l)

Step by step solution

01

Identify the chemical formulas

First, let us determine the chemical formulas for all the species involved in both reactions: 1. Steel: Primarily composed of Iron (Fe) and Manganese (Mn). 2. Nitric acid: HNO3 3. Manganese(II) ion: Mn^(2+) 4. Nitrogen dioxide gas: NO2 5. Periodate ion: IO4^(-) 6. Acidic solution: H+ ions are present, usually from a strong acid like H2SO4 or HCl. 7. Permanganate ion: MnO4^(-) 8. Iodate ion: IO3^(-) Now that we have the chemical formulas, we can write the unbalanced equations.
02

Write the unbalanced chemical equations

For the first reaction, Manganese in steel + Nitric acid -> Manganese(II) ion + Nitrogen dioxide gas Mn(s) + HNO3(aq) -> Mn^(2+)(aq) + NO2(g) For the second reaction, Manganese(II) ion + Periodate ion + Acidic solution -> Permanganate ion + Iodate ion Mn^(2+)(aq) + IO4^(-)(aq) + H+(aq) -> MnO4^(-)(aq) + IO3^(-)(aq)
03

Balance the chemical equations

Balance the first chemical equation: Mn(s)+2 HNO3(aq)Mn2+(aq)+2 NO2(g)+2 H+(aq) Balance the second chemical equation: 5 Mn2+(aq)+12 IO4(aq)+16 H+(aq)5 MnO4(aq)+12 IO3(aq)+8 H2O(l) Now we have the balanced chemical equations for determining the manganese content of steel: 1. Mn(s)+2 HNO3(aq)Mn2+(aq)+2 NO2(g)+2 H+(aq) 2. 5 Mn2+(aq)+12 IO4(aq)+16 H+(aq)5 MnO4(aq)+12 IO3(aq)+8 H2O(l)

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Most popular questions from this chapter

The equilibrium constant Ka for the reaction Co(H2O)63+(aq)+H2O(l) Co(H2O)5(OH)2+(aq)+H3O+(aq) is 1.0×105 a. Calculate the pH of a 0.10M solution of [Co(H2O)6]Cl3 b. Will a 1.0M solution of cobalt(Il) nitrate have a higher or lower pH than a 1.0M solution of cobalt (III) nitrate? Explain. c. Co3+ complex ions are generally low-spin cases, whereas Co2+ complex ions are generally high-spin cases. Explain. If this is the situation, how many unpaired electrons are present in Co(H2O)63+ and Co(H2O)62+?

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A metal ion in a high-spin octahedral complex has two more unpaired electrons than the same ion does in a low-spin octahedral complex. Name some possible metal ions for which this would be true.

The compound Ni(H2O)6Cl2 is green, whereas Ni(NH3)6Cl2 is violet. Predict the predominant color of light absorbed by each compound. Which compound absorbs light with the shorter wavelength? Predict in which compound Δ is greater and whether H2O or NH3 is the stronger field ligand. Do your conclusions agree with the spectrochemical series?

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