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Draw all geometrical and linkage isomers of \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right)_{2}\)

Short Answer

Expert verified
There are a total of four isomers for the complex \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right)_{2}\), considering both geometrical and linkage isomers. These include: 1. cis-isomer with both NO2- ligands attached through nitrogen. 2. cis-isomer with both NO2- ligands attached through oxygen. 3. trans-isomer with both NO2- ligands attached through nitrogen. 4. trans-isomer with both NO2- ligands attached through oxygen.

Step by step solution

01

Understand Geometrical and Linkage Isomers

Geometrical isomers are those isomers which differ in the arrangement(spatial orientation) of their ligands around the central metal atom. In the case of octahedral complexes, these isomers can arise due to the difference in the position of two ligands: - cis-isomers: the two similar ligands are adjacent to each other - trans-isomers: the two similar ligands are opposite to each other Linkage isomers are those isomers which differ in the point of attachment of their ligands to the central metal atom. They can arise if a ligand can bind to the metal center in more than one way, such as the NO2- ligand that can bind to the metal center through the nitrogen (N-NO2) or through the oxygen (O-NO2).
02

Identifying the Ligands and Possible attachments

Here, we have two types of ligands: 1. Ammonia (NH3) - it binds to the central metal atom through nitrogen. 2. Nitrite (NO2-) - it can bind to the central metal atom through nitrogen or oxygen. The complex has an octahedral configuration with 4 NH3 and 2 NO2- ligands.
03

Identifying Geometrical Isomers

For geometrical isomers, we need to determine the possible arrangements of the two NO2- ligands. There are two possibilities for this complex based on the positioning of NO2- ligands: 1. cis-isomer: The two NO2- ligands are adjacent to each other (90° angle between them) 2. trans-isomer: The two NO2- ligands are opposite to each other (180° angle between them)
04

Identifying Linkage Isomers

Since NO2- ligand can bind through nitrogen or oxygen, there are two possible linkage arrangements: 1. Both NO2- ligands bind through nitrogen (N-NO2) 2. Both NO2- ligands bind through oxygen (O-NO2)
05

Drawing All Possible Isomers

Now that we have identified all the possible geometrical and linkage configurations, we can draw all isomers: 1. cis-isomer with both NO2- ligands attached through nitrogen. 2. cis-isomer with both NO2- ligands attached through oxygen. 3. trans-isomer with both NO2- ligands attached through nitrogen. 4. trans-isomer with both NO2- ligands attached through oxygen. Considering both geometrical and linkage isomers, there are a total of four possible isomers for the complex \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right)_{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometrical Isomers
Geometrical isomers are a fascinating aspect of coordination chemistry. They arise in complexes when ligands can be arranged in different spatial orientations around a central metal atom, particularly in octahedral or square planar complexes. To understand them, think about how different arrangements can lead to molecules with the same chemical formula but different physical properties.
In the context of octahedral complexes like \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right)_{2}\), geometrical isomers occur because the ligands can be situated around the metal center in different patterns. Specifically, there are two primary ways to position two identical ligands:
  • Cis-isomer: Here, the two similar ligands (nitrite and ammonia) are adjacent, forming a 90-degree angle. This proximity can affect physical properties like boiling point and reactivity.
  • Trans-isomer: In this case, the similar ligands are opposite to each other, creating a 180-degree angle. This configuration often leads to entirely different characteristics from its cis counterpart.
Understanding these basic ideas about geometrical isomers helps in visualizing and predicting the chemical behavior of complex coordination compounds.
Linkage Isomers
Linkage isomers offer another layer of complexity in coordination chemistry. They involve the ability of a ligand to bind to a metal center in multiple ways. This type of isomerism comes into play when ligands contain atoms that can serve as donor sites to the metal.
For example, in the original exercise, we see the nitrite ion ( O_{2}^{-} ) can bind through either the nitrogen atom (N-nitro) or an oxygen atom (O-nitro). Such flexibility in binding leads to linkage isomerism.
  • N-bound isomer (N-NO2): The ligand binds to the central metal, cobalt ( Co ), through nitrogen. This affects how the compound will react chemically.
  • O-bound isomer (O-NO2): The binding occurs through oxygen instead. This minor change can lead to different chemical properties even though the rest of the structure remains unchanged.
Identifying and depicting linkage isomers broadens our understanding of the possible structures a complex ion may adopt and their properties.
Octahedral Complexes
Octahedral complexes are a cornerstone of coordination chemistry, characterized by a central metal atom surrounded symmetrically by six ligands. These ligands are usually positioned at the corners of an imaginary octahedron, offering insight into the bond formation and geometry involved.
In the case of our exercise complex, \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right)_{2}\), the coordinate structure allows for significant diversity:
  • Ligands like ammonia (NH_{3}) bind through nitrogen, providing stability and predictability in their bonding arrangement.
  • With the nitrite (NO_{2}^{-}) ligands, which bind either through nitrogen or oxygen, the options for linkage isomerism arise.
This intricate arrangement of ligands yields several possible isomers, each offering its own distinct set of chemical behaviors and properties. The octahedral configuration is critical because it dictates the potential isomers and lays the foundation for exploring both geometrical and linkage varieties in more depth.

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Most popular questions from this chapter

For the process $$\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}^{2+}(a q)+\mathrm{Cl}^{-}(a q) \longrightarrow \mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}^{+}(a q)+\mathrm{NH}_{3}(a q)$$ what would be the expected ratio of cis to trans isomers in the product?

Ethylenediaminetetraacetate (EDTA \(^{4-} )\) is used as a complexing agent in chemical analysis with the structure shown in Fig. \(21.7 .\) Solutions of EDTA \(^{4-}\) are used to treat heavy metal poisoning by removing the heavy metal in the form of a soluble complex ion. The complex ion virtually prevents the heavy metal ions from reacting with biochemical systems. The reaction of EDTA \(^{4-}\) with \(\mathrm{Pb}^{2+}\) is $$\mathrm{Pb}^{2+}(a q)+\mathrm{EDTA}^{4-(a q)} \rightleftharpoons \mathrm{PbEDTA}^{2-}(a q) \\\ \quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad K=1.1 \times 10^{18}$$ Consider a solution with 0.010 mol of \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\) added to 1.0 \(\mathrm{L}\) of an aqueous solution buffered at \(\mathrm{pH}=13.00\) and containing 0.050\(M \mathrm{Na}_{4} \mathrm{EDTA} .\) Does \(\mathrm{Pb}(\mathrm{OH})_{2}\) precipitate from this solution? \(\left[K_{\mathrm{sp}} \text { for } \mathrm{Pb}(\mathrm{OH})_{2}=1.2 \times 10^{-15}\right]\)

Until the discoveries of Alfred Werner, it was thought that carbon had to be present in a compound for it to be optically active. Werner prepared the following compound containing \(\mathrm{OH}^{-}\) ions as bridging groups and separated the optical isomers. a. Draw structures of the two optically active isomers of this compound. b. What are the oxidation states of the cobalt ions? c. How many unpaired electrons are present if the complex is the low-spin case?

Carbon monoxide is toxic because it binds more strongly to iron in hemoglobin \((\mathrm{Hb})\) than does \(\mathrm{O}_{2} .\) Consider the following reactions and approximate standard free energy changes: $$\begin{aligned} \mathrm{Hb}+\mathrm{O}_{2} \longrightarrow \mathrm{HbO}_{2} & \Delta G^{\circ}=-70 \mathrm{kJ} \\ \mathrm{Hb}+\mathrm{CO} \longrightarrow \mathrm{HbCO} & \Delta G^{\circ}=-80 \mathrm{kJ} \end{aligned}$$ Using these data, estimate the equilibrium constant value at \(25^{\circ} \mathrm{C}\) for the following reaction: $$\mathrm{HbO}_{2}(a q)+\mathrm{CO}(g) \rightleftharpoons \mathrm{HbCO}(a q)+\mathrm{O}_{2}(g)$$

Why are \(\mathrm{CN}^{-}\) and \(\mathrm{CO}\) toxic to humans?

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