Question

Write the formula for each of the following compounds: a. diboron trioxide b. arsenic pentafluoride c. dinitrogen monoxide d. sulfur hexachloride

Short answer

a. \(B_2O_3\) b. \(AsF_5\) c. \(N_2O\) d. \(S_6Cl\)

Step-by-step solution

The compound is made up of two elements, boron (B) and oxygen (O). The prefixes indicate that there are 2 boron atoms (di) and 3 oxygen atoms (tri). #Step 2: Write the chemical formula#

Based on the number of atoms for each element, we can write the chemical formula as \(B_2O_3\). #b. arsenic pentafluoride# #Step 1: Identify elements and number of atoms#

The compound is made up of two elements, arsenic (As) and fluorine (F). The prefixes indicate that there is 1 arsenic atom and 5 fluorine atoms (penta). #Step 2: Write the chemical formula#

Based on the number of atoms for each element, we can write the chemical formula as \(AsF_5\). #c. dinitrogen monoxide# #Step 1: Identify elements and number of atoms#

The compound is made up of two elements, nitrogen (N) and oxygen (O). The prefixes indicate that there are 2 nitrogen atoms (di) and 1 oxygen atom (mono). #Step 2: Write the chemical formula#

Based on the number of atoms for each element, we can write the chemical formula as \(N_2O\). #d. sulfur hexachloride# #Step 1: Identify elements and number of atoms#

The compound is made up of two elements, sulfur (S) and chlorine (Cl). The prefixes indicate that there is 1 sulfur atom and 6 chlorine atoms (hexa). #Step 2: Write the chemical formula#

Based on the number of atoms for each element, we can write the chemical formula as \(S_6Cl\).