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For lighter, stable isotopes, the ratio of the mass number to the atomic number is close to a certain value. What is the value? What happens to the value of the mass number to atomic number ratio as stable isotopes become heavier?

Short Answer

Expert verified
For lighter, stable isotopes, the ratio of the mass number to the atomic number (\(R = \frac{A}{Z}\)) is close to 2. As stable isotopes become heavier, the ratio increases at a slower pace due to the higher number of neutrons required to maintain the stability of the nucleus, balancing the repulsive forces between protons.

Step by step solution

01

Define Terms

The first thing we need to do is define our terms. The mass number, represented as \(A\), is the total number of protons and neutrons in the nucleus of an isotope. The atomic number, represented as \(Z\), is the number of protons in the nucleus of an isotope. The ratio we are interested in is given by: \[R = \frac{A}{Z}\]
02

Determine the Ratio for Lighter Stable Isotopes

The most common lighter, stable isotopes include hydrogen (\(^1_1H\)), helium (\(^4_2He\)), lithium (\(^7_3Li\)), and beryllium (\(^9_4Be\)). Let's calculate the ratio, R, for each of these isotopes: For hydrogen: \[R_H = \frac{1}{1} = 1\] For helium: \[R_{He} = \frac{4}{2} = 2\] For lithium: \[R_{Li} = \frac{7}{3} \approx 2.33\] For beryllium: \[R_{Be} = \frac{9}{4} \approx 2.25\] It appears that the ratio for lighter, stable isotopes is close to 2.
03

Discuss the Trend as Isotopes Become Heavier

As the isotopes become heavier, the ratio R is expected to deviate from the previously determined value of 2. This is mainly due to the increase in the number of neutrons relative to protons in the nucleus. The presence of more neutrons provides a balance to the repulsive forces between protons, thereby making heavier nuclei more stable. As we progress through the periodic table, the necessity to maintain greater neutron counts to maintain stability increases. Therefore, the ratio R also increases, but at a slower pace. This reflects the need for a higher number of neutrons relative to protons in the nucleus of isotopes with a larger atomic number.

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Most popular questions from this chapter

a. Classify the following elements as metals or nonmetals: $$\begin{array}{lll}\mathrm{Mg} & \mathrm{Si} & \mathrm{Rn} \\ \mathrm{Ti} & \mathrm{Ge} & \mathrm{Eu} \\ \mathrm{Au} & \mathrm{B} & \mathrm{Am} \\\ \mathrm{Bi} & \mathrm{At} & \mathrm{Br}\end{array}$$ b. The distinction between metals and nonmetals is really not a clear one. Some elements, called metalloids, are intermediate in their properties. Which of these elements would you reclassify as metalloids? What other elements in the periodic table would you expect to be metalloids?

Which of the following statements is(are) true? For the false statements, correct them. a. All particles in the nucleus of an atom are charged. b. The atom is best described as a uniform sphere of matter in which electrons are embedded. c. The mass of the nucleus is only a very small fraction of the mass of the entire atom. d. The volume of the nucleus is only a very small fraction of the total volume of the atom. e. The number of neutrons in a neutral atom must equal the number of electrons.

Write the formula for each of the following compounds: a. sodium oxide b. sodium peroxide c. potassium cyanide d. copper(II) nitrate e. selenium tetrabromide f. iodous acid g. lead(IV) sulfide h. copper(I) chloride i. gallium arsenide j. cadmium selenide k. zinc sulfide l. nitrous acid m. diphosphorus pentoxide

The designations 1A through 8A used for certain families of the periodic table are helpful for predicting the charges on ions in binary ionic compounds. In these compounds, the metals generally take on a positive charge equal to the family number, while the nonmetals take on a negative charge equal to the family number minus eight. Thus the compound between sodium and chlorine contains \(\mathrm{Na}^{+}\) ions and \(\mathrm{Cl}^{-}\) ions and has the formula NaCl. Predict the formula and the name of the binary compound formed from the following pairs of elements. a. Ca and N b. \(\mathrm{K}\) and \(\mathrm{O}\) c. \(\mathrm{Rb}\) and \(\mathrm{F}\) d. Mg and S e. Ba and I f. Al and Se g. \(\mathrm{Cs}\) and \(\mathrm{P}\) h. In and Br

Explain the law of conservation of mass, the law of definite proportion, and the law of multiple proportions.

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