Chapter 19: Problem 50
The most stable nucleus in terms of binding energy per nucleon is \(^{56}\mathrm{Fe}\) . If the atomic mass of \(^{56}\mathrm{Fe}\) is \(55.9349 \mathrm{u},\) calculate the binding energy per nucleon for \(^{56} \mathrm{Fe} .\)
Short Answer
Expert verified
The binding energy per nucleon for \(^{56}\mathrm{Fe}\) is approximately 8.56 MeV.
Step by step solution
01
Identify the number of protons and neutrons
Since the isotope is \(^{56}\mathrm{Fe}\), it has 56 nucleons in total. Iron (Fe) has an atomic number of 26, which means it has 26 protons. To find the number of neutrons, we subtract the number of protons from the total number of nucleons: \(56 - 26 = 30\) neutrons.
02
Calculate the mass defect
The mass defect is the difference between the mass of the individual protons and neutrons and the actual mass of \(^{56}\mathrm{Fe}\). The atomic mass of a proton is approximately 1.00728 u and the atomic mass of a neutron is approximately 1.00867 u. We can calculate the mass defect using the following equation:
\[Mass\,Defect = (26 \times 1.00728\,u + 30 \times 1.00867\,u) - 55.9349\,u\]
\[Mass\,Defect = (26.18928\,u + 30.2601\,u) - 55.9349\,u\]
\[Mass\,Defect = 56.44938\,u - 55.9349\,u\]
\[Mass\,Defect = 0.51448\,u\]
03
Convert mass defect to energy
Now we will use Einstein's equation to convert the mass defect to energy. We need to multiply the mass defect by the atomic mass unit constant (\(c^2 = 931.5\,\frac{MeV}{c^2 u}\)) to convert the mass defect from atomic mass units (u) to energy in mega electron volts (MeV).
\[Total\,Binding \,Energy = 0.51448\,u \times 931.5\,\frac{MeV}{c^2 u}\]
\[Total\,Binding \,Energy = 479.17\,MeV\]
04
Calculate binding energy per nucleon
Finally, we will divide the total binding energy by the number of nucleons (56) to find the binding energy per nucleon.
\[Binding\,Energy\,Per\,Nucleon = \frac{479.17\,MeV}{56}\]
\[Binding\,Energy\,Per\,Nucleon = 8.56\,MeV\]
Thus, the binding energy per nucleon for \(^{56}\mathrm{Fe}\) is approximately 8.56 MeV.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mass Defect
In nuclear physics, the mass defect is a crucial concept. It helps explain why the mass of a nucleus is less than the sum of the masses of its constituent protons and neutrons. This difference is called the mass defect.
To find the mass defect:
For example, in the case of iron-56 ( {^{56}Fe}), the mass defect plays a pivotal role in determining its nuclear binding energy. Here, the calculated mass defect reflects the level of stability and binding energy within the atomic nucleus. This energy holds the nucleus together, preventing it from breaking apart. Eventually calculating binding energy per nucleon gives a measure of stability.
To find the mass defect:
- Calculate the expected mass by adding up the masses of all protons and neutrons in the nucleus.
- Subtract the actual mass of the nucleus from this expected mass.
For example, in the case of iron-56 ( {^{56}Fe}), the mass defect plays a pivotal role in determining its nuclear binding energy. Here, the calculated mass defect reflects the level of stability and binding energy within the atomic nucleus. This energy holds the nucleus together, preventing it from breaking apart. Eventually calculating binding energy per nucleon gives a measure of stability.
Einstein's Equation
Einstein's equation, often written as \(E=mc^2\), is a fundamental principle in physics. It shows the relationship between mass (\(m\)) and energy (\(E\)), with \(c\) representing the speed of light in a vacuum. This equation highlights that mass can be converted into energy and vice versa, a concept central to nuclear physics.
In the context of nuclear binding energy:
In the context of nuclear binding energy:
- The mass defect, which is the missing mass found when comparing the predicted and actual mass of a nucleus, is converted into energy.
- When you multiply the mass defect by the speed of light squared, you get the binding energy, showing how much energy was converted from mass to stabilize the nucleus.
Atomic Mass Unit
An atomic mass unit (amu or \(u\)) is a standard unit of mass that quantifies mass on an atomic or molecular scale. By definition, one atomic mass unit is one-twelfth of the mass of a carbon-12 atom. Nearly all atoms are measured in atomic mass units, making it a convenient way to express atomic and molecular masses.
In nuclear processes:
In nuclear processes:
- Mass defect calculations use atomic mass units to express the minute changes in mass that occur during nuclear reactions.
- This unit helps in conversions, particularly when changing the mass defect into energy using Einstein's equation, as these reactions are dealing with extremely small mass amounts.
Iron-56
Iron-56 (
{^{56}Fe}) is a significant isotope in studies of nuclear stability. It is considered to be one of the most stable isotopes owing to its high binding energy per nucleon. This stability is due to its balanced forces and efficiently bound nucleons within its nucleus.
Key points about iron-56:
Key points about iron-56:
- It has 26 protons and 30 neutrons.
- Iron-56 is located at the peak of the nuclear binding energy curve, meaning it has the highest binding energy per nucleon compared to other elements.