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Consider the following reduction potentials: $$\begin{array}{ll}{\mathrm{Co}^{3+}+3 \mathrm{e}^{-} \longrightarrow \mathrm{Co}} & {\mathscr{E}^{\circ}=1.26 \mathrm{V}} \\ {\mathrm{Co}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Co}} & {\mathscr{E}^{\circ}=-0.28 \mathrm{V}}\end{array}$$ a. When cobalt metal dissolves in 1.0\(M\) nitric acid, will \(\mathrm{Co}^{3+}\) or \(\mathrm{Co}^{2+}\) be the primary product (assuming standard conditions)? b. Is it possible to change the concentration of \(\mathrm{HNO}_{3}\) to get a different result in part a? Concentrated \(\mathrm{HNO}_{3}\) is about 16 \(M\) .

Short Answer

Expert verified
When cobalt metal dissolves in 1.0 M nitric acid under standard conditions, Co³⁺ will be the primary product. It is not possible to change this result by increasing the concentration of HNO₃, as even with concentrated HNO₃ (16 M), Co³⁺ will still be the primary product.

Step by step solution

01

Write the redox reaction with nitric acid

First, let's write the redox reaction that occurs when cobalt metal dissolves in nitric acid: \[2\mathrm{Co} + 6\mathrm{H}^+ + 6\mathrm{NO}_3^- \longrightarrow 2\mathrm{Co}^n+ + 6\mathrm{NO}_2 + 3\mathrm{H}_2\mathrm{O}\] Here, n is either 2 or 3, so we'll have to find out which cobalt ion, Co²⁺ or Co³⁺, will be the primary product.
02

Calculate E₀cell for both Co²⁺ and Co³⁺

Now we'll calculate the E₀cell for both possible reactions: For the Co³⁺/Co reaction: \[E^\circ_{cell} = E^\circ_{Co^{3+}/Co} = 1.26\ \mathrm{V}\] For the Co²⁺/Co reaction: \[E^\circ_{cell} = E^\circ_{Co^{2+}/Co} = -0.28\ \mathrm{V}\]
03

Use the Nernst equation to calculate the reduction potential for both reactions at 1.0 M HNO₃

The Nernst equation is given by: \[E = E^\circ - \frac{RT}{nF} \ln Q\] Let's plug in the reduction potentials, concentrations, and constants for both reactions: For Co³⁺/Co: \[E_{Co^{3+}/Co} = 1.26\ \mathrm{V} - \frac{8.314 \times 298\ \mathrm{K}}{3 \times 96485\ \mathrm{C/mol}} \ln\frac{[Co^{3+}]}{[Co]} = 1.26\ \mathrm{V}\] For Co²⁺/Co: \[E_{Co^{2+}/Co} = -0.28\ \mathrm{V} - \frac{8.314 \times 298\ \mathrm{K}}{2 \times 96485\ \mathrm{C/mol}} \ln\frac{[Co^{2+}]}{[Co]} = -0.28\ \mathrm{V}\] Since the concentration of Co remains constant in both reactions, we can compare them directly. The larger potential is for the Co³⁺/Co reaction, so Co³⁺ is the primary product under standard conditions.
04

Answer to part (a)

When cobalt metal dissolves in 1.0 M nitric acid under standard conditions, Co³⁺ will be the primary product.
05

Repeat the Nernst equation calculations for 16 M HNO₃

Now let's see if the result would change using concentrated HNO₃ (16 M). For Co³⁺/Co, keep its E unchanged: \[E_{Co^{3+}/Co} = 1.26\ \mathrm{V}\] For Co²⁺/Co, use the Nernst equation with 16 M HNO₃: \[E_{Co^{2+}/Co} = -0.28\ \mathrm{V} - \frac{8.314 \times 298\ \mathrm{K}}{2 \times 96485\ \mathrm{C/mol}} \ln\frac{[Co^{2+}]}{[Co]}\] The change in concentration of nitric acid does not affect the Nernst equation for Co²⁺/Co because it doesn't appear in the equation. Therefore, the calculated potential remains -0.28 V.
06

Answer to part (b)

It is not possible to change the result in part (a) by changing the concentration of HNO₃. Even with concentrated HNO₃ (16 M), Co³⁺ will still be the primary product when cobalt metal dissolves in nitric acid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reduction Potentials
Reduction potentials are essential in electrochemistry, helping to predict the direction of redox reactions. In simple terms, a reduction potential, denoted as \(E^\circ\), measures the tendency of a chemical species to be reduced. It is often given in volts (V).

A positive standard reduction potential indicates a greater tendency to gain electrons, thus being reduced. Conversely, a negative value suggests a preference to lose electrons, or oxidize. Hence, in our cobalt example,
  • The reaction \(\text{Co}^{3+} + 3\text{e}^- \rightarrow \text{Co}\) has a reduction potential of \(1.26\,\text{V}\).
  • The reaction \(\text{Co}^{2+} + 2\text{e}^- \rightarrow \text{Co}\) has a reduction potential of \(-0.28\,\text{V}\).
This means that \(\text{Co}^{3+}\) has a stronger tendency to be reduced to cobalt metal than \(\text{Co}^{2+}\) does. As a result, when cobalt metal interacts with nitric acid, \(\text{Co}^{3+}\) forms more readily.

Knowing reduction potentials allows us to predict which species will behave as oxidizing agents (accepting electrons) and which will behave as reducing agents (donating electrons).
Nernst Equation
The Nernst equation is a powerful tool in electrochemistry used to calculate the cell potential under non-standard conditions. It accounts for the effect of concentration on cell potentials. The equation is expressed as:\[ E = E^\circ - \frac{RT}{nF} \ln Q \] where:
  • \(E\) is the cell potential under non-standard conditions.
  • \(E^\circ\) is the standard cell potential.
  • \(R\) is the universal gas constant (8.314 J/mol K).
  • \(T\) is the temperature in Kelvin.
  • \(n\) is the number of moles of electrons exchanged.
  • \(F\) is the Faraday constant (96485 C/mol).
  • \(Q\) is the reaction quotient, representing the ratio of product concentrations to reactant concentrations.

In the given problem, the Nernst equation demonstrates that changing the concentration of \(\text{HNO}_3\) doesn’t affect the potential for the \(\text{Co}^{2+}/\text{Co}\) couple because it doesn’t appear in the reaction quotient for this reaction. Consequently, even with the increased concentration of \(\text{HNO}_3\), the potential for \(\text{Co}^{2+}/\text{Co}\) remains constant, confirming \(\text{Co}^{3+}\) as the dominant product.
Redox Reactions
Redox reactions, short for reduction-oxidation reactions, are chemical processes where electrons are transferred between substances. They play a crucial role in energy production and resource cycling in nature and technology.Key aspects of redox reactions include:
  • Reduction: The gain of electrons by a molecule, atom, or ion.
  • Oxidation: The loss of electrons.
  • Oxidizing agent: A substance that gains electrons (is reduced itself).
  • Reducing agent: A substance that loses electrons (is oxidized itself).

In the context of the cobalt and nitric acid reaction, cobalt metal acts as a reducing agent. When it dissolves in nitric acid, cobalt ions (\(\text{Co}^{3+}\) and \(\text{Co}^{2+}\)) are generated. The net transfer of electrons determines which cobalt species predominates.Identifying and balancing redox reactions require understanding the electron flow, which is depicted through oxidation states and half-equations. This aids in predicting reaction spontaneity and product formation.

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Most popular questions from this chapter

It takes 15 kWh (kilowatt-hours) of electrical energy to produce 1.0 kg aluminum metal from aluminum oxide by the Hall-Heroult process. Compare this to the amount of energy necessary to melt 1.0 kg aluminum metal. Why is it economically feasible to recycle aluminum cans? [The enthalpy of fusion for aluminum metal is 10.7 \(\mathrm{kJ} / \mathrm{mol}(1 \text { watt }=1 \mathrm{J} / \mathrm{s}) . ]\)

Combine the equations $$\Delta G^{\circ}=-n F \mathscr{E}^{\circ} \text { and } \Delta G^{\circ}=\Delta H^{\circ}-T \Delta S^{\circ}$$ to derive an expression for \(\mathscr{E}^{\circ}\) as a function of temperature. Describe how one can graphically determine \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) from measurements of \(\mathscr{E}^{\circ}\) at different temperatures, assuming that \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) do not depend on temperature. What property would you look for in designing a reference half-cell that would produce a potential relatively stable with respect to temperature?

A disproportionation reaction involves a substance that acts as both an oxidizing and a reducing agent, producing higher and lower oxidation states of the same element in the products. Which of the following disproportionation reactions are spontaneous under standard conditions? Calculate \(\Delta G^{\circ}\) and \(K\) at \(25^{\circ} \mathrm{C}\) for those reactions that are spontaneous under standard conditions. a. \(2 \mathrm{Cu}^{+}(a q) \longrightarrow \mathrm{Cu}^{2+}(a q)+\mathrm{Cu}(s)\) b. \(3 \mathrm{Fe}^{2+}(a q) \longrightarrow 2 \mathrm{Fe}^{3+}(a q)+\mathrm{Fe}(s)\) c. \(\mathrm{HClO}_{2}(a q) \longrightarrow \mathrm{ClO}_{3}^{-}(a q)+\mathrm{HClO}(a q) \quad\) (unbalanced) Use the half-reactions: \(\mathrm{ClO}_{3}^{-}+3 \mathrm{H}^{+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{HClO}_{2}+\mathrm{H}_{2} \mathrm{O} \quad \mathscr{E}^{\circ}=1.21 \mathrm{V}\) \(\mathrm{HClO}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{HClO}+\mathrm{H}_{2} \mathrm{O} \quad \mathscr{E}^{\circ}=1.65 \mathrm{V}\)

A galvanic cell consists of a standard hydrogen electrode and a copper electrode immersed in a Cu(NO \(_{3} )_{2}(a q)\) solution. If you wish to construct a calibration curve to show how the cell potential varies with \(\left[\mathrm{Cu}^{2+}\right],\) what should you plot to obtain a straight line? What will be the slope of this line?

Which of the following statements concerning corrosion is(are) true? For the false statements, correct them. a. Corrosion is an example of an electrolytic process. b. Corrosion of steel involves the reduction of iron coupled with the oxidation of oxygen. c. Steel rusts more easily in the dry (arid) Southwest states than in the humid Midwest states. d. Salting roads in the winter has the added benefit of hindering the corrosion of steel. e. The key to cathodic protection is to connect via a wire a metal more easily oxidized than iron to the steel surface to be protected.

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