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Carbonate buffers are important in regulating the pH of blood at \(7.40 .\) If the carbonic acid concentration in a sample of blood is 0.0012 M, determine the bicarbonate ion concentration required to buffer the pH of blood at pH \(=7.40\) $$ \mathrm{H}_{2} \mathrm{CO}_{3}(a q) \rightleftharpoons \mathrm{HCO}_{3}^{-}(a q)+\mathrm{H}^{+}(a q) \quad K_{\mathrm{a}}=4.3 \times 10^{-7} $$

Short Answer

Expert verified
The bicarbonate ion concentration (HCO₃⁻) required to buffer the pH of blood at pH = 7.40 is approximately 0.0021 M, calculated using the Henderson-Hasselbalch equation and given the carbonic acid concentration and Ka value.

Step by step solution

01

Calculate pKa

To calculate the pKa, use the following equation: pKa = -log(Ka). We're given the Ka value for carbonic acid, which is 4.3 x 10⁻⁷. Therefore: pKa = -log(4.3 x 10⁻⁷) Now, calculate the pKa value: pKa ≈ 6.37
02

Use the Henderson-Hasselbalch equation

Now that we have the pKa value, we can use the Henderson-Hasselbalch equation to solve for the bicarbonate ion concentration: pH = pKa + log([A⁻]/[HA]) We are given the pH (7.40) and the concentration of carbonic acid ([HA]) which is 0.0012 M. Plug in these values into the equation: 7.40 = 6.37 + log([HCO₃⁻]/0.0012)
03

Solve for bicarbonate ion concentration [HCO₃⁻]

Now, solve for the [HCO₃⁻] concentration: 7.40 - 6.37 = log([HCO₃⁻]/0.0012) 1.03 = log([HCO₃⁻]/0.0012) To undo the logarithm, raise 10 in power of both sides: 10^1.03 = [HCO₃⁻]/0.0012 Now, simply solve for [HCO₃⁻]: [HCO₃⁻] = 0.0012 x 10^1.03 [HCO₃⁻] ≈ 0.0021 M The bicarbonate ion concentration required to buffer the pH of blood at pH = 7.40 is approximately 0.0021 M.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Henderson-Hasselbalch equation
The Henderson-Hasselbalch equation provides a way to determine the pH of a buffer solution. It is helpful in cases where you are trying to maintain the pH of a solution at a certain level. Typically, it is used to calculate the ratio of conjugate base to acid needed to achieve this desired pH.

This equation is derived from the expression for the dissociation constant of the acid, and can be written as follows:
  • \( \text{pH} = \text{pKa} + \log \left(\frac{[\text{A}^-]}{[\text{HA}]}\right) \)
Here, \([\text{A}^-]\) is the concentration of the conjugate base, \([\text{HA}]\) is the concentration of the acid, and \(\text{pKa}\) is the negative logarithm of the acid dissociation constant \(K_a\).

In the context of the carbonic acid-bicarbonate buffer system, this equation helps us find the necessary bicarbonate ion concentration required to maintain blood pH at 7.40 under given conditions.
bicarbonate ion concentration
Bicarbonate ions (\(\text{HCO}_3^-\)) play a crucial role in maintaining the pH of blood through the carbonate buffer system. They act as a buffer to neutralize acids added to the blood, thus preventing drastic changes in its pH.

From the Henderson-Hasselbalch equation, once the pKa is known (in this case, 6.37 derived from \( \text{K}_a = 4.3 \times 10^{-7} \)), you can calculate the concentration of these bicarbonate ions necessary to maintain the pH of the blood.

In the provided exercise, the calculation went as follows:
  • Given: \( [\text{HA}] = 0.0012 \text{ M} \), \( \text{pH} = 7.40 \)
  • Seek \([\text{HCO}_3^-]\) such that \( 7.40 = 6.37 + \log \left(\frac{[\text{HCO}_3^-]}{0.0012}\right) \)
  • Solve the above equation for \([\text{HCO}_3^-]\)
  • The needed bicarbonate concentration turned out to be approximately \(0.0021 \text{ M}\)
By adjusting the bicarbonate ion concentrations, our blood is able to resist significant fluctuations in pH, emphasizing the importance of these ions in biological systems.
pH regulation
pH regulation is a critical function in biological systems, especially in humans, where the proper functioning of enzymes and metabolic processes is highly dependent on a stable pH environment.

In the blood, the pH is tightly regulated around 7.40 through various mechanisms, one of the most important being the bicarbonate buffer system. This system works by adjusting the levels of carbonic acid (H₂CO₃) and bicarbonate ions (HCO₃⁻), balancing the shift in hydrogen ion (H⁺) concentration, which in turn stabilizes the pH.

  • Increased H⁺ concentration results in a lower pH (more acidic). The bicarbonate ions can neutralize these excess H⁺ ions.
  • Conversely, a decrease in H⁺ concentration (higher pH) means carbonic acid will dissociate, releasing H⁺ ions to bring the pH back to a neutral level.


In situations where pH regulation fails, serious health conditions can arise, such as acidosis or alkalosis, which can have severe biological implications. Thus, the bicarbonate buffering mechanism is essential for healthcare professionals to understand when dealing with such issues. Through the use of buffer systems, organisms are able to maintain a relatively constant internal environment which is crucial for survival.

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Most popular questions from this chapter

Consider the titration of 100.0 \(\mathrm{mL}\) of 0.100 \(\mathrm{M} \mathrm{HCN}\) by 0.100 \(\mathrm{M} \mathrm{KOH}\) at \(25^{\circ} \mathrm{C} .\left(K_{\mathrm{a}} \text { for } \mathrm{HCN}=6.2 \times 10^{-10} .\right)\) a. Calculate the pH after 0.0 \(\mathrm{mL}\) of KOH has been added. b. Calculate the pH after 50.0 \(\mathrm{mL}\) of KOH has been added. c. Calculate the pH after 75.0 \(\mathrm{mL}\) of KOH has been added. d. Calculate the pH at the equivalence point. e. Calculate the pH after 125 \(\mathrm{mL}\) of KOH has been added.

Consider 1.0 \(\mathrm{L}\) of a solution that is 0.85 \(\mathrm{M} \mathrm{HOC}_{6} \mathrm{H}_{5}\) and 0.80 \(\mathrm{M} \mathrm{NaOC}_{6} \mathrm{H}_{5} .\left(K_{\mathrm{a}} \text { for } \mathrm{HOC}_{6} \mathrm{H}_{5}=1.6 \times 10^{-10} .\right)\) a. Calculate the pH of this solution. b. Calculate the pH after 0.10 mole of \(\mathrm{HCl}\) has been added to the original solution. Assume no volume change on addition of HCl. c. Calculate the pH after 0.20 mole of NaOH has been added to the original buffer solution. Assume no volume change on addition of NaOH.

You have a solution of the weak acid HA and add some HCl to it. What are the major species in the solution? What do you need to know to calculate the pH of the solution, and how would you use this information? How does the pH of the solution of just the HA compare with that of the final mixture? Explain

A buffer solution is prepared by mixing 75.0 \(\mathrm{mL}\) of 0.275 \(\mathrm{M}\) fluorobenzoic acid \(\left(\mathrm{C}_{7} \mathrm{H}_{5} \mathrm{O}_{2} \mathrm{F}\right)\) with 55.0 \(\mathrm{mL}\) of 0.472 \(\mathrm{M}\) sodium fluorobenzoate. The \(\mathrm{pK}_{\mathrm{a}}\) of this weak acid is \(2.90 .\) What is the pH of the buffer solution?

One method for determining the purity of aspirin \(\left(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}\right)\) is to hydrolyze it with NaOH solution and then to titrate the remaining NaOH. The reaction of aspirin with NaOH is as follows: \(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}(s)+2 \mathrm{OH}^{-}(a q)\) $$ \mathrm{C}_{7} \mathrm{H}_{3} \mathrm{O}_{3}^{-}(a q)+\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) $$ A sample of aspirin with a mass of 1.427 g was boiled in 50.00 \(\mathrm{mL}\) of 0.500\(M \mathrm{NaOH}\) . After the solution was cooled, it took 31.92 \(\mathrm{mL}\) of 0.289 \(\mathrm{M} \mathrm{HCl}\) to titrate the excess NaOH. Calculate the purity of the aspirin. What indicator should be used for this titration? Why?

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