Question

Write balanced equations that describe the following reactions. a. the dissociation of perchloric acid in water b. the dissociation of propanoic acid \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{H}\right)\) in water c. the dissociation of ammonium ion in water

Short answer

a. \( \mathrm{HClO}_{4}(aq) \rightarrow \mathrm{H}^{+}(aq) + \mathrm{ClO}_{4}^{-}(aq) \) b. \( \mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CO}_{2}\mathrm{H}(aq) \rightarrow \mathrm{H}^{+}(aq) + \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CO}_{2}^{-}(aq) \) c. \( \mathrm{NH}_{4}^{+}(aq) \rightarrow \mathrm{H}^{+}(aq) + \mathrm{NH}_{3}(aq) \)

Step-by-step solution

Identify reactants and products

Perchloric acid (HClO4) dissociates in water to produce hydrogen ions (H+) and perchlorate ions (ClO4-). The water molecule will act as a solvent but does not participate directly in the reaction. Reactants: HClO4 Products: H+ ions and ClO4- ions Step 2: Write the balanced equation

Write the balanced equation

\( \mathrm{HClO}_{4}(aq) \rightarrow \mathrm{H}^{+}(aq) + \mathrm{ClO}_{4}^{-}(aq) \) The above equation is already balanced. #b. Dissociation of propanoic acid (CH3CH2CO2H) in water#

Identify reactants and products

Propanoic acid (CH3CH2CO2H) dissociates in water to produce hydrogen ions (H+) and propanoate ions (CH3CH2CO2-). The water molecule will act as a solvent but does not participate directly in the reaction. Reactants: CH3CH2CO2H Products: H+ ions and CH3CH2CO2- ions

Write the balanced equation

\( \mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CO}_{2}\mathrm{H}(aq) \rightarrow \mathrm{H}^{+}(aq) + \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CO}_{2}^{-}(aq) \) The above equation is already balanced. #c. Dissociation of ammonium ion in water#

Identify reactants and products

Ammonium ion (NH4+) dissociates in water to produce hydrogen ions (H+) and ammonia molecules (NH3). The water molecule will act as a solvent but does not participate directly in the reaction. Reactants: NH4+ ions Products: H+ ions and NH3 molecules

Write the balanced equation

\( \mathrm{NH}_{4}^{+}(aq) \rightarrow \mathrm{H}^{+}(aq) + \mathrm{NH}_{3}(aq) \) The above equation is already balanced.