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The value of the equilibrium constant \(K\) depends on which of the following (more than one answer may be correct)? a. the initial concentrations of the reactants b. the initial concentrations of the products c. the temperature of the system d. the nature of the reactants and products Explain.

Short Answer

Expert verified
The value of the equilibrium constant (K) depends on the temperature of the system (option 'c') and the nature of the reactants and products (option 'd'). It is independent of the initial concentrations of reactants and products (options 'a' and 'b'). Changes in temperature can affect the balance between forward and reverse reaction rates, while the specific chemical properties of reactants and products determine the unique equilibrium constant value for each reaction.

Step by step solution

01

Option a: The initial concentrations of the reactants

The value of the equilibrium constant (K) is independent of the initial concentrations of the reactants. Equilibrium conditions depend on a fixed ratio of the concentrations of reactants and products, irrespective of their initial concentrations. Hence, option 'a' is incorrect.
02

Option b: The initial concentrations of the products

Similar to option 'a', the value of the equilibrium constant (K) is independent of the initial concentrations of the products. The equilibrium concentrations are determined by the fixed ratio between the concentrations of reactants and products, which does not depend on their initial concentrations. So, option 'b' is also incorrect.
03

Option c: The temperature of the system

The value of the equilibrium constant (K) is dependent on the temperature of the system for a given reaction. A change in temperature affects the equilibrium constant because it influences the balance between the forward and reverse reaction rates. If a reaction is endothermic, an increase in temperature will shift the equilibrium to favor the products, increasing the value of K. Conversely, if a reaction is exothermic, an increase in temperature will shift the equilibrium to favor the reactants, decreasing the value of K. Therefore, option 'c' is correct.
04

Option d: The nature of the reactants and products

The value of the equilibrium constant (K) depends on the nature of the reactants and products involved in the reaction. The equilibrium constant represents the balance between the forward and reverse reactions, which in turn depends on the specific chemical properties of the reactants and products. Each reaction has a unique equilibrium constant value that is specific to the reactants and products involved. So, option 'd' is correct. In conclusion, the value of the equilibrium constant (K) depends on the temperature of the system (option 'c') and the nature of the reactants and products (option 'd').

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Most popular questions from this chapter

Write expressions for \(K_{\mathrm{p}}\) for the following reactions. a. \(2 \mathrm{Fe}(s)+\frac{3}{2} \mathrm{O}_{2}(g) \rightleftharpoons \mathrm{Fe}_{2} \mathrm{O}_{3}(s)\) b. \(\mathrm{CO}_{2}(g)+\mathrm{MgO}(s) \rightleftharpoons \mathrm{MgCO}_{3}(s)\) c. \(\mathrm{C}(s)+\mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons \mathrm{CO}(g)+\mathrm{H}_{2}(g)\) d. \(4 \mathrm{KO}_{2}(s)+2 \mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons 4 \mathrm{KOH}(s)+3 \mathrm{O}_{2}(g)\)

Suppose the reaction system $$\mathrm{UO}_{2}(s)+4 \mathrm{HF}(g) \rightleftharpoons \mathrm{UF}_{4}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)$$ has already reached equilibrium. Predict the effect that each of the following changes will have on the equilibrium position. Tell whether the equilibrium will shift to the right, will shift to the left, or will not be affected. a. Additional \(\mathrm{UO}_{2}(s)\) is added to the system. b. The reaction is performed in a glass reaction vessel; HF \((g)\) attacks and reacts with glass. c. Water vapor is removed.

For the reaction $$\mathrm{PCl}_{5}(g) \rightleftharpoons \mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g)$$ at \(600 . \mathrm{K}\) , the equilibrium constant, \(K_{\mathrm{p}},\) is \(11.5 .\) Suppose that 2.450 \(\mathrm{g} \mathrm{PCl}_{5}\) is placed in an evacuated 500 -mL bulb, which is then heated to \(600 . \mathrm{K}\) . a. What would be the pressure of \(\mathrm{PCl}_{5}\) if it did not dissociate? b. What is the partial pressure of \(\mathrm{PCl}_{5}\) at equilibrium? c. What is the total pressure in the bulb at equilibrium? d. What is the percent dissociation of PCl_ at equilibrium?

Consider the reaction $$\mathrm{Fe}^{3+}(a q)+\mathrm{SCN}^{-}(a q) \rightleftharpoons \mathrm{FeSCN}^{2+}(a q)$$ How will the equilibrium position shift if a. water is added, doubling the volume? b. \(\operatorname{AgNO}_{3}(a q)\) is added? (AgSCN is insoluble.) c. \(\mathrm{NaOH}(a q)\) is added? [Fe(OH) \(_{3}\) is insoluble. \(]\) d. Fe(NO \(_{3} )_{3}(a q)\) is added?

At a particular temperature, 8.1 moles of \(\mathrm{NO}_{2}\) gas are placed in a 3.0 -L container. Over time the \(\mathrm{NO}_{2}\) decomposes to \(\mathrm{NO}\) and \(\mathrm{O}_{2} :\) $$2 \mathrm{NO}_{2}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g)$$ At equilibrium the concentration of \(\mathrm{NO}(g)\) was found to be 1.4 \(\mathrm{mol} / \mathrm{L}\) . Calculate the value of \(K\) for this reaction.

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