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Suppose a reaction has the equilibrium constant \(K=1.3 \times 10^{8} .\) What does the magnitude of this constant tell you about the relative concentrations of products and reactants that will be present once equilibrium is reached? Is this reaction likely to be a good source of the products?

Short Answer

Expert verified
The given equilibrium constant, \(K = 1.3 \times 10^8\), is significantly greater than 1, indicating that the reaction is product-favored. At equilibrium, the concentration of products will be much greater than that of reactants. Therefore, this reaction is likely to be a good source of the products.

Step by step solution

01

Understand the meaning of the equilibrium constant

The equilibrium constant (K) is a dimensionless value that helps us determine the extent of a reaction at equilibrium, i.e., the relative concentrations of products and reactants. A reaction can be written in the form: \(aA + bB \rightleftharpoons cC + dD\) At equilibrium, the constant K is defined as: \[K = \frac{[C]^c \cdot [D]^d}{[A]^a \cdot [B]^b}\] Where [A], [B], [C], and [D] are the molar concentrations of the reactants (A and B) and products (C and D) at equilibrium. If K >> 1, the reaction is product-favored, meaning the concentration of products is much greater than that of reactants at equilibrium. If K << 1, the reaction is more reactant-favored.
02

Interpret the given equilibrium constant

In this exercise, we are given the equilibrium constant as \(K = 1.3 \times 10^8\). This value is significantly greater than 1, meaning the reaction is product-favored. Once equilibrium is reached, the concentration of products will be much greater than that of reactants.
03

Determine the suitability of the reaction as a product source

Since K >> 1, the reaction is product-favored, and the concentration of products at equilibrium will be much greater than that of reactants. This indicates the system would likely be a good source of the products. The large value of K suggests that the products are largely favored, so if the reactants were introduced into the system, the equilibrium would shift to produce more products.

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Most popular questions from this chapter

An initial mixture of nitrogen gas and hydrogen gas is reacted in a rigid container at a certain temperature by the reaction $$3 \mathrm{H}_{2}(g)+\mathrm{N}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g)$$ At equilibrium, the concentrations are \(\left[\mathrm{H}_{2}\right]=5.0 M,\left[\mathrm{N}_{2}\right]=\) \(8.0 M,\) and \(\left[\mathrm{NH}_{3}\right]=4.0 \mathrm{M} .\) What were the concentrations of nitrogen gas and hydrogen gas that were reacted initially?

The reaction $$2 \mathrm{NO}(g)+\mathrm{Br}_{2}(g) \rightleftharpoons 2 \mathrm{NOBr}(g)$$ has \(K_{\mathrm{p}}=109\) at \(25^{\circ} \mathrm{C}\) . If the equilibrium partial pressure of \(\mathrm{Br}_{2}\) is 0.0159 atm and the equilibrium partial pressure of NOBr is 0.0768 atm, calculate the partial pressure of \(\mathrm{NO}\) at equilibrium.

For the reaction \(\mathrm{H}_{2}(g)+\mathrm{I}_{2}(g) \rightleftharpoons 2 \mathrm{HI}(g),\) consider two possibilities: (a) you mix 0.5 mole of each reactant, allow the system to come to equilibrium, and then add another mole of \(\mathrm{H}_{2}\) and allow the system to reach equilibrium again, or \((b)\) you \(\operatorname{mix} 1.5\) moles of \(\mathrm{H}_{2}\) and 0.5 mole of \(\mathrm{I}_{2}\) and allow the system to reach equilibrium. Will the final equilibrium mixture be different for the two procedures? Explain.

An important reaction in the commercial production of hydrogen is $$\mathrm{CO}(g)+\mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons \mathrm{H}_{2}(g)+\mathrm{CO}_{2}(g)$$ How will this system at equilibrium shift in each of the five following cases? a. Gaseous carbon dioxide is removed. b. Water vapor is added. c. In a rigid reaction container, the pressure is increased by adding helium gas. d. The temperature is increased (the reaction is exothermic). e. The pressure is increased by decreasing the volume of the reaction container.

A sample of gaseous nitrosyl bromide (NOBr) was placed in a container fitted with a frictionless, massless piston, where it decomposed at \(25^{\circ} \mathrm{C}\) according to the following equation: $$2 \mathrm{NOBr}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{Br}_{2}(g)$$ The initial density of the system was recorded as 4.495 \(\mathrm{g} / \mathrm{L}\) . After equilibrium was reached, the density was noted to be 4.086 \(\mathrm{g} / \mathrm{L}\) . a. Determine the value of the equilibrium constant \(K\) for the reaction. b. If \(\operatorname{Ar}(g)\) is added to the system at equilibrium at constant temperature, what will happen to the equilibrium position? What happens to the value of \(K ?\) Explain each answer.

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