Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Cobra venom helps the snake secure food by binding to acetylcholine receptors on the diaphragm of a bite victim, leading to the loss of function of the diaphragm muscle tissue and eventually death. In order to develop more potent antivenins, scientists have studied what happens to the toxin once it has bound the acetylcholine receptors. They have found that the toxin is released from the receptor in a process that can be described by the rate law $$ \text {Rate} =k[\text { acetylcholine receptor-toxin complex }] $$ If the activation energy of this reaction at \(37.0^{\circ} \mathrm{C}\) is 26.2 \(\mathrm{kJ} /\) mol and \(A=0.850 \mathrm{s}^{-1},\) what is the rate of reaction if you have \(\mathrm{a} 0.200-\mathrm{M}\) solution of receptor-toxin complex at \(37.0^{\circ} \mathrm{C} ?\)

Short Answer

Expert verified
The rate of the reaction for a 0.200 M solution of receptor-toxin complex at 37.0°C is approximately 2.74 × 10^-5 M/s.

Step by step solution

01

Convert the activation energy and temperature to the proper units

The activation energy (Ea) needs to be in Joules per mol (J/mol) and the temperature (T) should be in Kelvins (K). Ea = 26.2 kJ/mol × (1000 J / 1 kJ) = 26200 J/mol T = 37.0 °C + 273.15 = 310.15 K
02

Use the Arrhenius equation to find the rate constant (k)

The Arrhenius equation is: \(k = Ae^{\frac{-Ea}{RT}}\) where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant (8.314 J/mol·K), and T is the temperature. Plugging in the given values: k = 0.850 s^-1 × exp(-26200 J/mol ÷ (8.314 J/mol·K × 310.15 K)) Calculate the value for k: k ≈ 1.37 × 10^-4 s^-1
03

Use the rate law equation to find the rate of reaction

Now that we have the rate constant (k), we can use the rate law equation to find the rate of the reaction: Rate = k[acetylcholine receptor-toxin complex] Plug in the values: Rate = (1.37 × 10^-4 s^-1) × 0.200 M Calculate the rate: Rate ≈ 2.74 × 10^-5 M/s So, the rate of the reaction is approximately 2.74 × 10^-5 M/s at 37.0°C for a 0.200 M solution of receptor-toxin complex.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Activation Energy
Activation energy is a crucial concept in understanding chemical reactions. It is the minimum energy required to initiate a reaction. Think of it as a barrier that reactants must overcome to transform into products. Activation energy is typically expressed in Joules per mole (J/mol) or kilojoules per mole (kJ/mol).

In a chemical reaction, the reactants need enough kinetic energy for their atoms to rearrange. Activation energy acts as this initial push. Without sufficient energy, even if reactants are present, the reaction does not proceed.

For instance, in the reaction concerning acetylcholine receptor-toxin complex, the activation energy is given as 26.2 kJ/mol, which helps determine the rate constant using another important tool: the Arrhenius equation.
Arrhenius Equation
The Arrhenius equation is a formula used to calculate the rate constant (k) of a reaction. It shows how the rate of a chemical reaction increases with temperature. This is expressed as:

\[k = A e^{-\frac{E_a}{RT}}\] where:
  • \(k\) is the rate constant, which indicates the speed of a reaction.
  • \(A\) is the pre-exponential factor or frequency factor, representing the likelihood of a collision between reactant molecules.
  • \(E_a\) is the activation energy.
  • \(R\) is the gas constant (8.314 J/mol·K).
  • \(T\) is the temperature in Kelvin.
The Arrhenius equation shows that the higher the temperature, the lower the exponential function outcome, making the rate constant larger.

For our exercise, by calculating using the given activation energy, pre-exponential factor, and temperature, we find that the rate constant \(k\) is approximately \(1.37 \times 10^{-4} \text{s}^{-1}\) at \(37.0^{\circ} \text{C}\).
Acetylcholine Receptor
Acetylcholine receptors play an essential role in communication between nerve cells and muscles. They are proteins located on cell membranes, primarily on muscle tissues and nerves. When acetylcholine, a neurotransmitter, binds to these receptors, it triggers muscle contraction.

But, in the case of cobra venom, toxins mimic or interfere with acetylcholine. The venom binds to the acetylcholine receptors and blocks their normal function, causing paralysis and potentially leading to death if untreated.

Understanding this interaction helps researchers develop antidotes and treatments. By determining how toxins bind and release from these receptors, scientists can tailor antivenoms to better outcompete the toxins or reverse their effects.

In this context, knowing the rate at which the toxin releases from the receptor is key to figuring out how quickly an antidote might need to work to save someone's life.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the Haber process for the production of ammonia, $$ \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g) $$ what is the relationship between the rate of production of ammonia and the rate of consumption of hydrogen?

The reaction $$ \left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}+\mathrm{OH}^{-} \longrightarrow\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}+\mathrm{Br}^{-} $$ in a certain solvent is first order with respect to \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}\) and zero order with respect to \(\mathrm{OH}^{-} .\) In several experiments, the rate constant \(k\) was determined at different temperatures. A plot of \(\ln (k)\) versus 1\(/ T\) was constructed resulting in a straight line with a slope value of \(-1.10 \times 10^{4} \mathrm{K}\) and \(y\) -intercept of 33.5 . Assume \(k\) has units of \(\mathrm{s}^{-1}\) a. Determine the activation energy for this reaction. b. Determine the value of the frequency factor \(A\) . c. Calculate the value of \(k\) at \(25^{\circ} \mathrm{C}\) .

Sulfuryl chloride undergoes first-order decomposition at \(320 .^{\circ} \mathrm{C}\) with a half-life of 8.75 \(\mathrm{h}\) . $$ \mathrm{SO}_{2} \mathrm{Cl}_{2}(g) \longrightarrow \mathrm{SO}_{2}(g)+\mathrm{Cl}_{2}(g) $$ What is the value of the rate constant, \(k,\) in \(\mathrm{s}^{-1}\) ? If the initial pressure of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) is 791 torr and the decomposition occurs in a \(1.25-\mathrm{L}\) container, how many molecules of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) remain after 12.5 \(\mathrm{h}\) ?

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 \(\mathrm{kJ} / \mathrm{mol} .\) In the presence of a catalyst at \(37^{\circ} \mathrm{C}\) the rate constant for the reaction increases by a factor of \(2.50 \times 10^{3}\) as compared with the uncatalyzed reaction. Assuming the frequency factor \(A\) is the same for both the catalyzed and uncatalyzed reactions, calculate the activation energy for the catalyzed reaction.

Individuals who suffer from lactose intolerance do not produce enough of the enzyme lactase. Explain why this is an issue.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free