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How does temperature affect k, the rate constant? Explain.

Short Answer

Expert verified
The rate constant (k) is affected by temperature through the Arrhenius Equation: \(k = A \times e^{-\frac{Ea}{RT}}\). As temperature increases, the exponential factor (\(e^{-\frac{Ea}{RT}}\)) increases, leading to an increase in the rate constant and a faster reaction. The activation energy (Ea) determines how sensitive the rate constant is to temperature changes, with higher activation energy making the reaction more sensitive to temperature changes.

Step by step solution

01

Understanding the Arrhenius Equation

The connection between temperature and the rate constant (k) is given by the Arrhenius Equation: \[k = A \times e^{-\frac{Ea}{RT}}\] where: - k is the rate constant - A is the pre-exponential factor (a constant) - Ea is the activation energy (energy needed for a reaction to occur) - R is the ideal gas constant (8.314 J/mol K) - T is the temperature in Kelvin
02

Effect of temperature on k

In the Arrhenius equation, the rate constant k depends on the temperature through the exponential factor: \[e^{-\frac{Ea}{RT}}\] This factor is a dimensionless number between 0 and 1, which decreases as the activation energy (Ea) increases and/or the temperature (T) decreases. Conversely, this factor increases as the temperature (T) increases.
03

Evaluating the exponential factor

When the temperature is low, the exponential factor becomes closer to 0. This means that the rate constant (k) is also lower, leading to a slower reaction. As the temperature increases, the exponential factor becomes closer to 1, increasing the rate constant (k) and making the reaction faster. This is why temperature plays a significant role in determining the rate of a reaction.
04

Activation energy and temperature sensitivity

The activation energy (Ea) determines how sensitive a reaction's rate constant (k) is to temperature changes. Reactions with high activation energy are more sensitive to temperature changes, meaning that small changes in temperature result in significant changes in the rate constant. Reactions with low activation energy are less sensitive to temperature changes, meaning that changes in temperature have a smaller effect on the rate constant. In summary, the rate constant (k) is affected by temperature through the Arrhenius Equation. As temperature increases, the exponential factor in the Arrhenius Equation increases, leading to an increase in the rate constant and a faster reaction. The activation energy of the reaction determines how sensitive the rate constant is to temperature changes.

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Most popular questions from this chapter

Enzymes are kinetically important for many of the complex reactions necessary for plant and animal life to exist. However, only a tiny amount of any particular enzyme is required for these complex reactions to occur. Explain.

Two isomers (A and B) of a given compound dimerize as follows: $$ \begin{array}{l}{2 \mathrm{A} \stackrel{k_{1}}{\longrightarrow} A_{2}} \\ {2 \mathrm{B} \stackrel{k_{2}}{\longrightarrow} \mathrm{B}_{2}}\end{array} $$ Both processes are known to be second order in reactant, and \(k_{1}\) is known to be 0.250 \(\mathrm{L} / \mathrm{mol} \cdot \mathrm{s}\) at \(25^{\circ} \mathrm{C}\) . In a particular experiment \(\mathrm{A}\) and \(\mathrm{B}\) were placed in separate containers at \(25^{\circ} \mathrm{C},\) where \([\mathrm{A}]_{0}=1.00 \times 10^{-2} M\) and \([\mathrm{B}]_{0}=2.50 \times 10^{-2} M\) It was found that after each reaction had progressed for \(3.00 \mathrm{min},[\mathrm{A}]=3.00[\mathrm{B}]\) . In this case the rate laws are defined as $$ \begin{array}{l}{\text { Rate }=-\frac{\Delta[\mathrm{A}]}{\Delta t}=k_{1}[\mathrm{A}]^{2}} \\ {\text { Rate }=-\frac{\Delta[\mathrm{B}]}{\Delta t}=k_{2}[\mathrm{B}]^{2}}\end{array} $$ a. Calculate the concentration of \(\mathrm{A}_{2}\) after 3.00 \(\mathrm{min}\) . b. Calculate the value of \(k_{2}\) . c. Calculate the half-life for the experiment involving A.

The reaction $$ \left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}+\mathrm{OH}^{-} \longrightarrow\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}+\mathrm{Br}^{-} $$ in a certain solvent is first order with respect to \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}\) and zero order with respect to \(\mathrm{OH}^{-} .\) In several experiments, the rate constant \(k\) was determined at different temperatures. A plot of \(\ln (k)\) versus 1\(/ T\) was constructed resulting in a straight line with a slope value of \(-1.10 \times 10^{4} \mathrm{K}\) and \(y\) -intercept of 33.5 . Assume \(k\) has units of \(\mathrm{s}^{-1}\) a. Determine the activation energy for this reaction. b. Determine the value of the frequency factor \(A\) . c. Calculate the value of \(k\) at \(25^{\circ} \mathrm{C}\) .

The reaction $$ 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g) $$ exhibits the rate law $$ \text {Rate} =k[\mathrm{NO}]^{2}\left[\mathrm{O}_{2}\right] $$ Which of the following mechanisms is consistent with this rate law? $$ \begin{array}{l}{\text { a. } \mathrm{NO}+\mathrm{O}_{2} \longrightarrow \mathrm{NO}_{2}+\mathrm{O}} \\ {\mathrm{O}+\mathrm{NO} \longrightarrow \mathrm{NO}_{2}} \\ {\text { b. } \mathrm{NO}+\mathrm{O}_{2} \rightleftharpoons \mathrm{NO}_{3}} \\ {\mathrm{NO}_{3}+\mathrm{NO} \longrightarrow 2 \mathrm{NO}_{2}}\end{array} $$ $$ \begin{array}{l}{\text { c. } 2 \mathrm{NO} \longrightarrow \mathrm{N}_{2} \mathrm{O}_{2}} \\ {\mathrm{N}_{2} \mathrm{O}_{2}+\mathrm{O}_{2} \longrightarrow \mathrm{N}_{2} \mathrm{O}_{4}} \\ {\mathrm{N}_{2} \mathrm{O}_{4} \longrightarrow 2 \mathrm{NO}_{2}} \\ {\text { d. } 2 \mathrm{NO} \rightleftharpoons \mathrm{N}_{2} \mathrm{O}_{2}} \\\ {\mathrm{N}_{2} \mathrm{O}_{2} \longrightarrow \mathrm{NO}_{2}+\mathrm{O}} \\\ {\mathrm{O}+\mathrm{NO} \longrightarrow \mathrm{NO}_{2}}\end{array} $$

The rate constant \((k)\) depends on which of the following (there may be more than one answer)? a. the concentration of the reactants b. the nature of the reactants c. the temperature d. the order of the reaction Explain.

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