Two isomers (A and B) of a given compound dimerize as follows:
$$
\begin{array}{l}{2 \mathrm{A} \stackrel{k_{1}}{\longrightarrow} A_{2}} \\ {2
\mathrm{B} \stackrel{k_{2}}{\longrightarrow} \mathrm{B}_{2}}\end{array}
$$
Both processes are known to be second order in reactant, and \(k_{1}\) is known
to be 0.250 \(\mathrm{L} / \mathrm{mol} \cdot \mathrm{s}\) at \(25^{\circ}
\mathrm{C}\) . In a particular experiment \(\mathrm{A}\) and \(\mathrm{B}\) were
placed in separate containers at \(25^{\circ} \mathrm{C},\) where
\([\mathrm{A}]_{0}=1.00 \times 10^{-2} M\) and \([\mathrm{B}]_{0}=2.50 \times
10^{-2} M\) It was found that after each reaction had progressed for \(3.00
\mathrm{min},[\mathrm{A}]=3.00[\mathrm{B}]\) . In this case the rate laws are
defined as
$$
\begin{array}{l}{\text { Rate }=-\frac{\Delta[\mathrm{A}]}{\Delta
t}=k_{1}[\mathrm{A}]^{2}} \\ {\text { Rate
}=-\frac{\Delta[\mathrm{B}]}{\Delta t}=k_{2}[\mathrm{B}]^{2}}\end{array}
$$
a. Calculate the concentration of \(\mathrm{A}_{2}\) after 3.00 \(\mathrm{min}\) .
b. Calculate the value of \(k_{2}\) .
c. Calculate the half-life for the experiment involving A.