Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The type of rate law for a reaction, either the differential rate law or the integrated rate law, is usually determined by which data is easiest to collect. Explain.

Short Answer

Expert verified
The choice between using a differential or integrated rate law depends on the ease of data collection during experiments. Differential rate laws are more suitable when there is a direct method to measure the reactant concentrations over time, such as spectrophotometry or conductivity measurements. Integrated rate laws are convenient when data points of concentration change over time can be easily obtained for a known reaction order. The practical aspects of data collection determine which rate law is most efficient and useful for a given reaction.

Step by step solution

01

Introduction to Differential and Integrated Rate Laws

Differential rate laws show the relationship between the rate of a reaction and the concentrations of reactants. Integrated rate laws relate the concentration of a reactant at the initial time (t=0) to the concentrations at any time (t) during the reaction. Both differential and integrated rate laws can be used to describe the reaction rates. However, the choice of the rate law depends on the ease of collecting data during experiments.
02

Differential Rate Laws and Data Collection

Differential rate laws are expressed as a rate equation, such as: Rate \(= k[A]^m[B]^n\) Where Rate is the rate of the reaction, k is the rate constant, [A] and [B] are the concentrations of reactants A and B, and m and n are the order of the reaction with respect to each reactant. To determine the values of m and n, experimental data is required, which usually involves monitoring the change in the concentrations of reactants over time. Collecting this data can be easier if there are direct methods to measure the concentrations, such as spectrophotometry for colored solutions or conductivity measurements for ionic species.
03

Integrated Rate Laws and Data Collection

Integrated rate laws are derived from the differential rate equations by integrating them with respect to time. They can be represented as: For zero-order reactions: \([A]_t = [A]_0 - kt\) For first-order reactions: ln\([A]_t = ln[A]_0 - kt\) For second-order reactions: \(\frac{1}{[A]_t} = \frac{1}{[A]_0} + kt\) Where \([A]_t\) is the concentration of reactant A at time t, \([A]_0\) is the initial concentration of reactant A, and k is the rate constant. To analyze data using integrated rate laws, it is usually more convenient to collect data points of concentration or concentration change over time. The method depends on the reaction order, which should be determined through experimental observation.
04

Conclusion

In summary, the choice of using a differential or integrated rate law mainly depends on the practical aspects of data collection during experiments. Differential rate laws are more suitable when there is a direct method to measure the reactant concentrations over time, while integrated rate laws are convenient when data points of concentration change over time can be easily obtained for a known reaction order.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Table 12.2 illustrates how the average rate of a reaction decreases with time. Why does the average rate of a reaction generally decrease with time? How does the instantaneous rate of a reaction depend on time? Why are initial rates of a reaction primarily used by convention?

A popular chemical demonstration is the "magic genie" procedure, in which hydrogen peroxide decomposes to water and oxygen gas with the aid of a catalyst. The activation energy of this (uncatalyzed) reaction is 70.0 \(\mathrm{kJ} / \mathrm{mol}\) . When the catalyst is added, the activation energy (at \(20 .^{\circ} \mathrm{C} )\) is 42.0 \(\mathrm{kJ} / \mathrm{mol}\) . Theoretically, to what temperature ( \((\mathrm{C})\) would one have to heat the hydrogen peroxide solution so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction at \(20 .^{\circ} \mathrm{C} ?\) Assume the frequency factor \(A\) is constant, and assume the initial concentrations are the same.

The reaction $$ 0^{\circ} \mathrm{C}, $$ These relationships hold only if there is a very small amount of \(\mathrm{I}_{3}^{-}\) present. What is the rate law and the value of the rate constant? (Assume that rate \(=-\frac{\Delta\left[\mathrm{H}_{2} \mathrm{SeO}_{3}\right]}{\Delta t} )\)

Each of the statements given below is false. Explain why. a. The activation energy of a reaction depends on the overall energy change \((\Delta E)\) for the reaction. b. The rate law for a reaction can be deduced from examination of the overall balanced equation for the reaction. c. Most reactions occur by one-step mechanisms.

A first-order reaction has rate constants of \(4.6 \times 10^{-2} \mathrm{s}^{-1}\) and \(8.1 \times 10^{-2} \mathrm{s}^{-1}\) at \(0^{\circ} \mathrm{C}\) and \(20 .^{\circ} \mathrm{C},\) respectively. What is the value of the activation energy?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free