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What stabilizes a colloidal suspension? Explain why adding heat or adding an electrolyte can cause the suspended particles to settle out

Short Answer

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A colloidal suspension is stabilized by the balance of repulsive and attractive forces between the dispersed particles. Repulsive forces, mainly due to the electrical double layer and steric hindrance, prevent aggregation, while attractive forces, such as van der Waals forces, can cause aggregates or precipitates if they dominate. Adding heat increases the kinetic energy and Brownian motion of particles, making them more likely to collide and aggregate. Adding an electrolyte reduces the electrical double layer, decreasing repulsive forces and allowing attractive forces to dominate, leading to aggregation and sedimentation.

Step by step solution

01

Understand colloidal suspensions

A colloidal suspension is a mixture of insoluble particles (solid, liquid, or gas) dispersed in a continuous medium (such as a liquid). The particles have dimensions in the range of 1 to 1000 nanometers. The stability of a colloidal suspension depends on the balance of repulsive and attractive forces between the dispersed particles. The repulsive forces prevent the particles from approaching each other and aggregating, while the attractive forces can cause aggregates or precipitates if they dominate.
02

Examine repulsive forces in colloidal suspension

In many colloids, the repulsive forces are mainly due to the electrical double layer around the particles. This double layer consists of a charged surface (either positive or negative) and a region of counter ions surrounding the surface. The net effect of this double layer is that two neighboring particles will experience repulsive electrostatic forces when they approach each other. The intervening liquid also contributes to the repulsive forces through steric hindrance (i.e., the entropic penalty associated with forcing solvent molecules out of the space between particles).
03

Examine attractive forces in colloidal suspension

The primary attractive forces in colloidal suspensions are van der Waals forces, which arise due to attractive interactions between electron clouds of particles. These forces can cause aggregation or precipitation if they are not counterbalanced by repulsive forces.
04

Effect of heat on colloidal suspension

Adding heat to a colloidal suspension can cause the suspended particles to settle out due to an increase in Brownian motion. When the temperature of the suspension increases, the particles gain kinetic energy and move more rapidly. The enhanced particle motion means that the particles are more likely to collide with each other and overcome the repulsive forces, leading to aggregation or sedimentation of the particles.
05

Effect of electrolyte on colloidal suspension

Adding an electrolyte to a colloidal suspension can also cause the suspended particles to settle out due to a reduction in the electrical double layer and the consequent decrease in repulsive electrostatic forces. The added electrolyte ions will interact with the charged surfaces of the particles and compress the electrical double layer, effectively screening the surface charge. This reduces the repulsive forces between particles and allows the attractive van der Waals forces to dominate, leading to particle aggregation and sedimentation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stability of Colloids
The stability of colloidal suspensions is an intriguing balance that is mainly governed by physical forces. In essence, colloids are stabilized by the presence of repulsive forces that work to keep particles apart. These forces often arise from the interactions between charged particles and their surroundings. For instance, in a liquid medium, particles typically develop a charge due to chemical interactions with the solvent. This charge leads to the formation of an electrical double layer around each particle, which helps stabilize the colloid by preventing particles from coming too close to each other.

Moreover, the medium itself contributes to stability. The continuous medium in which the particles are dispersed can exert steric hindrance, meaning there is an energy cost if solvent molecules are displaced by particles getting too close. This protective layer plays a crucial role in maintaining colloidal stability over time, preventing aggregation that might lead to particles settling out.
Repulsive and Attractive Forces
When it comes to the forces at play in colloids, repulsive and attractive forces are constantly in a tug of war. The repulsive forces, essential for stability, often come from electrostatic interactions. Particles with like charges repel each other due to their electrical double layers, ensuring they stay dispersed.

On the flip side, attractive forces are primarily due to van der Waals interactions. These occur because of temporary shifts in charge distributions between particles, causing them to be drawn towards each other. If these attractive forces overpower the repulsive ones, the particles may start to aggregate, leading to phase separation. The balance between these forces determines whether a colloidal suspension remains stable or whether the particles start clumping together and settling.
Effect of Heat
Introducing heat to a colloidal suspension results in a change in the behavior of the particles, often causing them to settle out of the dispersion medium. The reason lies in Brownian motion: when temperature increases, particles gain kinetic energy, which makes them move faster.

This increased movement heightens the likelihood of collisions between particles. When they collide, they may be prompted to overcome the stabilizing repulsive forces. As a result, the particles can aggregate more easily, leading to the separation of the colloidal phase as particles settle. Thus, maintaining a cooler environment is key to preserving the integrity of colloidal suspensions.
Effect of Electrolyte
Electrolytes can significantly influence the stability of colloidal suspensions. When an electrolyte is introduced, it interacts with the charged surfaces of the colloidal particles. The ions from the electrolyte compress the electrical double layers surrounding the particles, which diminishes the electrostatic repulsion between them.

This compression is known as "screening" of the surface charge. With reduced repulsive forces, the attractive van der Waals forces can dominate, causing the particles to stick together more easily, leading to aggregation and settling out of the suspension. Therefore, careful management of electrolyte concentrations is crucial to maintaining the stability of colloidal systems.

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Most popular questions from this chapter

Which solvent, water or hexane \(\left(\mathrm{C}_{6} \mathrm{H}_{14}\right),\) would you choose to dissolve each of the following? a. \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\) b. \(\mathrm{CS}_{2}\) c. \(\mathrm{CH}_{3} \mathrm{OH}\) d. \(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{16} \mathrm{CH}_{2} \mathrm{OH}\) e. \(\mathrm{HCl}\) f. \(\mathrm{C}_{6} \mathrm{H}_{6}\)

In a coffee-cup calorimeter, 1.60 \(\mathrm{g} \mathrm{NH}_{4} \mathrm{NO}_{3}\) was mixed with 75.0 \(\mathrm{g}\) water at an initial temperature \(25.00^{\circ} \mathrm{C}\) . After dissolution of the salt, the final temperature of the calorimeter contents was \(23.34^{\circ} \mathrm{C}\) . a. Assuming the solution has a heat capacity of 4.18 \(\mathrm{J} / \mathrm{g}\) \(^{\circ} \mathrm{C},\) and assuming no heat loss to the calorimeter, calculate the enthalpy of solution \(\left(\Delta H_{\mathrm{soln}}\right)\) for the dissolution of \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) in units of \(\mathrm{kJ} / \mathrm{mol} .\) b. If the enthalpy of hydration for \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) is \(-630 . \mathrm{kJ} / \mathrm{mol}\) calculate the lattice energy of \(\mathrm{NH}_{4} \mathrm{NO}_{3} .\)

A 1.60 -g sample of a mixture of naphthalene \(\left(\mathrm{C}_{10} \mathrm{H}_{8}\right)\) and anthracene \(\left(\mathrm{C}_{14} \mathrm{H}_{10}\right)\) is dissolved in 20.0 \(\mathrm{g}\) benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) The freezing point of the solution is \(2.81^{\circ} \mathrm{C} .\) What is the composition as mass percent of the sample mixture? The freezing point of benzene is \(5.51^{\circ} \mathrm{C}\) and \(K_{\mathrm{f}}\) is \(5.12^{\circ} \mathrm{C} \cdot \mathrm{kg} / \mathrm{mol} .\)

The freezing point of \(t\) -butanol is \(25.50^{\circ} \mathrm{C}\) and \(K_{\mathrm{f}}\) is \(9.1^{\circ} \mathrm{C} \cdot \mathrm{kg} / \mathrm{mol}\) Usually \(t\) -butanol absorbs water on exposure to air. If the freezing point of a 10.0 -g sample of \(t\) -butanol is \(24.59^{\circ} \mathrm{C},\) how many grams of water are present in the sample?

A forensic chemist is given a white solid that is suspected of being pure cocaine \(\left(\mathrm{C}_{17} \mathrm{H}_{21} \mathrm{NO}_{4}, \text { molar mass }=303.35 \mathrm{g} / \mathrm{mol}\right)\) She dissolves \(1.22 \pm 0.01 \mathrm{g}\) of the solid in \(15.60 \pm 0.01 \mathrm{g}\) benzene. The freezing point is lowered by \(1.32 \pm 0.04^{\circ} \mathrm{C}\) a. What is the molar mass of the substance? Assuming that the percent uncertainty in the calculated molar mass is the same as the percent uncertainty in the temperature change, calculate the uncertainty in the molar mass. b. Could the chemist unequivocally state that the substance is cocaine? For example, is the uncertainty small enough to distinguish cocaine from codeine \(\left(\mathrm{C}_{18} \mathrm{H}_{21} \mathrm{NO}_{3}, \text { molar }\right.\) mass \(=299.36 \mathrm{g} / \mathrm{mol}\) )? c. Assuming that the absolute uncertainties in the measurements of temperature and mass remain unchanged, how could the chemist improve the precision of her results?

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