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A 2.00 -g sample of a large biomolecule was dissolved in 15.0 g carbon tetrachloride. The boiling point of this solution was determined to be 77.85C . Calculate the molar mass of the biomolecule. For carbon tetrachloride, the boiling-point constant is 5.03Ckg/mol, and the boiling point of pure carbon tetrachloride is 76.50C.

Short Answer

Expert verified
The molar mass of the biomolecule is approximately 497 g/mol.

Step by step solution

01

Understand the Boiling-Point Elevation formula

Boiling-point elevation is the phenomenon that occurs when a non-volatile solute is dissolved in a solvent, resulting in an increase in the boiling point of the solvent. The relationship is described by the following formula: ΔT = Kₘ ⋅ molality where ΔT is the boiling point elevation, Kₘ is the boiling-point constant for the solvent, and the molality is the concentration of the solute in the solution.
02

Calculate the boiling point elevation

First, let's calculate the boiling point elevation (ΔT). We are given the boiling point of the pure solvent (carbon tetrachloride) and the boiling point of the solution: ΔT = Boiling point of the solution - Boiling point of pure solvent ΔT = 77.85C 76.50C ΔT = 1.35 °C
03

Rearrange the formula to calculate molality

Now we can rearrange the boiling-point elevation formula to solve for the molality of the biomolecule in the solution: molality = ΔT / Kₘ
04

Calculate the molality of the biomolecule

The boiling-point constant for carbon tetrachloride K=5.03Ckg/mol and ΔT = 1.35 °C. So, let's plug the values: molality = (1.35 °C) / 5.03Ckg/mol molality = 0.2684 mol / kg
05

Calculate the amount of moles of the biomolecule

Molality is defined as the number of moles of solute per kilogram of solvent. We know the mass of the solvent and the molality of the biomolecule. Using this information, we can calculate the number of moles of the biomolecule present in the solution: moles = molality × mass of solvent in kg moles = (0.2684 mol / kg) × (15.0 g CCl₄ × (1 kg / 1000 g)) moles = 0.004026 mol
06

Calculate the molar mass of the biomolecule

We are given the mass of the biomolecule (2.00 g) and we have calculated the number of moles present in the solution. We can now calculate the molar mass of the biomolecule: molar mass = mass of biomolecule / moles of biomolecule molar mass = (2.00 g) / (0.004026 mol) molar mass ≈ 497 g/mol The molar mass of the biomolecule is approximately 497 g/mol.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
Calculating the molar mass of a substance is an essential skill in chemistry. Molar mass allows chemists to relate mass in grams to the amount of substance in moles. To find molar mass, remember this simple formula:
  • Molar Mass (g/mol) = Mass of the Substance (g) / Moles of the Substance (mol)
Steps to Calculate:
- First, you need the mass of the substance, which in our example is the biomolecule weighing 2.00 g.
- Next, determine the amount in moles, which requires understanding the solute’s concentration in the solvent, often done through colligative properties.
By dividing, you’ll arrive at the molar mass, which here is approximately 497 g/mol.
Molar mass is a fundamental concept because it bridges the gap between atomic-level interactions and measurable quantities, allowing scientists to predict and balance chemical reactions.
Colligative Properties
Colligative properties depend on the number of solute particles in a solvent rather than the identity of the solute. These properties are crucial for understanding how solutions behave. Among them are boiling-point elevation, freezing-point depression, vapor pressure lowering, and osmotic pressure.

In the context of boiling-point elevation:
  • When a non-volatile solute, like our biomolecule, is added to a solvent such as carbon tetrachloride, it causes the boiling point to increase.
  • This increase is quantified by the formula: ΔT = Kₘ ⋅ molality, where ΔT represents the boiling point elevation and Kₘ is the boiling-point elevation constant.
  • Molality, a measure of solute concentration, changes the physical properties of the solvent.
Colligative properties are powerful tools to determine molar mass and understand solution compositions. When dealing with solutions, these properties illustrate how solute particles, regardless of type, influence overall behavior.
Solution Chemistry
Solution chemistry is the study of how substances dissolve and interact within a medium, usually a liquid solvent. A solution is composed of a solute — the substance being dissolved — and a solvent — the substance doing the dissolving.

Key principles include:
  • Solubility: The amount of solute that can be dissolved in a solvent at a given temperature.
  • Concentration: Represents the quantity of solute present in a certain amount of solution, expressed commonly in molarity or molality.
  • Interactions: When a solute dissolves, it may dissociate into ions or stay as molecules, affecting how properties manifest.
Understanding these components is vital to predicting the properties of mixtures. Solution chemistry is foundational to the study of thermodynamics and kinetics in reactions. It helps chemists control conditions to optimize reaction outcomes and duplicate results reliably.

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Most popular questions from this chapter

A 1.60 -g sample of a mixture of naphthalene (C10H8) and anthracene (C14H10) is dissolved in 20.0 g benzene (C6H6) The freezing point of the solution is 2.81C. What is the composition as mass percent of the sample mixture? The freezing point of benzene is 5.51C and Kf is 5.12Ckg/mol.

Rationalize the trend in water solubility for the following simple alcohols:

You have read that adding a solute to a solvent can both increase the boiling point and decrease the freezing point. A friend of yours explains it to you like this: “The solute and solvent can be like salt in water. The salt gets in the way of freezing in that it blocks the water molecules from joining together. The salt acts like a strong bond holding the water molecules together so that it is harder to boil.” What do you say to your friend?

Patients undergoing an upper gastrointestinal tract laboratory test are typically given an X-ray contrast agent that aids with the radiologic imaging of the anatomy. One such contrast agent is sodium diatrizoate, a nonvolatile water-soluble compound. A 0.378 -m solution is prepared by dissolving 38.4 g sodium diatrizoate (NaDTZ) in 1.60×102mL water at 31.2C (the density of water at 31.2C is 0.995 g/cm3). What is the molar mass of sodium diatrizoate? What is the vapor pressure of this solution if the vapor pressure of pure water at 31.2C is 34.1 torr?

An aqueous solution containing 0.250 mole of Q, a strong electrolyte, in 5.00×102g water freezes at 2.79C. What is the van't Hoff factor for Q? The molal freezing-point depression constant for water is 1.86Ckg/mol . What is the formula of Q if it is 38.68% chlorine by mass and there are twice as many anions as cations in one formula unit of Q?

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