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When pure methanol is mixed with water, the resulting solution feels warm. Would you expect this solution to be ideal? Explain.

Short Answer

Expert verified
The methanol-water solution is not ideal because it feels warm when mixed, indicating that heat is evolved during the mixing process. This exothermic behavior implies that the solute-solvent interactions between methanol and water are stronger than the pure solute-solute and solvent-solvent interactions, resulting in a non-ideal solution.

Step by step solution

01

Understanding Ideal Solutions

An ideal solution is a solution in which the interactions between the solute and solvent particles are essentially the same as those in the pure solvents. In other words, the solute-solvent interactions are equal to the solute-solute and solvent-solvent interactions. This means that there is no change in enthalpy as a result of mixing the solute and solvent, hence, no heat is evolved or absorbed during the process.
02

Exothermic and Endothermic Solutions

In a non-ideal solution, the solute-solvent interactions are different from the interactions present before mixing. This difference in interactions results in a change in enthalpy. Depending on whether the solute-solvent interactions are stronger or weaker than the solute-solute and solvent-solvent interactions, the solution can be exothermic (heat evolves) or endothermic (heat is absorbed).
03

Methanol-Water Solution

In the given exercise, when methanol is mixed with water, the resulting solution feels warm, which indicates that heat is evolved during mixing. This means that the solute-solvent interactions, in this case between methanol and water, are stronger than the pure solute-solute and solvent-solvent interactions. Therefore, mixing methanol and water results in an exothermic process.
04

Conclusion

Based on the observation that the methanol-water solution feels warm, we can conclude that the solution is not ideal, as energy is released in the form of heat due to the difference in solute-solvent interactions compared to the pure solute and solvent. The solution is exothermic and non-ideal.

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Most popular questions from this chapter

Consider an aqueous solution containing sodium chloride that has a density of 1.01 \(\mathrm{g} / \mathrm{mL}\) . Assume the solution behaves ideally. The freezing point of this solution at 1.0 \(\mathrm{atm}\) is \(-1.28^{\circ} \mathrm{C}\) . Calculate the percent composition of this solution (by mass).

The freezing point of \(t\) -butanol is \(25.50^{\circ} \mathrm{C}\) and \(K_{\mathrm{f}}\) is \(9.1^{\circ} \mathrm{C} \cdot \mathrm{kg} / \mathrm{mol}\) Usually \(t\) -butanol absorbs water on exposure to air. If the freezing point of a 10.0 -g sample of \(t\) -butanol is \(24.59^{\circ} \mathrm{C},\) how many grams of water are present in the sample?

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A solution is prepared by dissolving 52.3 g cesium chloride in 60.0 g water. The volume of the solution is 63.3 \(\mathrm{mL}\) . Calculate the mass percent, molarity, molality, and mole fraction of the CsCl solution.

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