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Cytochrome \(\mathrm{C}\) is a molecule with an iron-porphyrin head connected to a protein tail. Analysis shows the molecule is \(0.45\) percent iron by weight. Calculate the molecular weight of cytochrome \(\mathrm{C}\).

Short Answer

Expert verified
The molecular weight of cytochrome C is approximately 12410 g/mol.

Step by step solution

01

Convert the percentage of iron to a decimal value

To convert the percentage to a decimal value, simply divide the percentage value by 100. So, we have: 0.45% = 0.45/100 = 0.0045 This means that there is 0.0045 parts of iron by weight in cytochrome C.
02

Find the molar mass of iron

The molar mass of iron, denoted as Fe, can be found on the periodic table. The molar mass of iron is approximately M(Fe) = 55.845 g/mol
03

Set up an equation relating the weight of iron to the total molecular weight

Let the molecular weight of cytochrome C be denoted as M(CytC). The equation relating the weight of iron to the total molecular weight is: 0.0045 * M(CytC) = M(Fe)
04

Solve the equation for the molecular weight of cytochrome C

Plugging in the molar mass of iron found in step 2: 0.0045 * M(CytC) = 55.845 g/mol Now, we can solve for the molecular weight of cytochrome C: M(CytC) = M(Fe) / 0.0045 M(CytC) = 55.845 g/mol / 0.0045 M(CytC) ≈ 12410 g/mol The molecular weight of cytochrome C is approximately 12410 g/mol.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Cytochrome C
Cytochrome C is an essential molecule found in the mitochondria of cells. It plays a crucial role in the electron transport chain, which is a series of chemical reactions that help generate energy in the form of ATP. This molecule has two primary components: an iron-porphyrin head and a protein tail. The iron-porphyrin complex is responsible for the electron transfer process, while the protein tail aids in attaching the molecule within the mitochondrial membrane.
Cytochrome C's function in cellular respiration makes it vital for energy production, underpinning many metabolic processes. This molecule is also interesting for its role in apoptosis, or programmed cell death, thus making it a focal point in studies related to diseases such as cancer.
Iron Percentage in Molecular Structure
The iron percentage in a molecule like cytochrome C is a measure of how much of the molecule's mass is made up of iron. This is typically expressed as a percentage by weight. In the given problem, cytochrome C is said to be 0.45% iron by weight.
When you hear '0.45% iron,' it means that out of every 100 grams of cytochrome C, 0.45 grams is iron.
Understanding the iron content is crucial because iron's presence and amount can significantly impact the molecule's properties and functionality, particularly in its role in electron transport.
Calculating Molar Mass
Molar mass is essentially the weight of one mole of a given substance, usually measured in grams per mole (g/mol). It is calculated by summing the atomic masses of all atoms in a molecule.
For elemental iron, the molar mass is approximately 55.845 g/mol, as stated in the periodic table. Molar masses are essential for converting moles to grams or vice versa, particularly in chemical reactions and stoichiometry.
  • To find the molecular weight of a compound, multiply the molar mass of its component parts by their frequency in a single molecule, summing the total.
  • For cytochrome C, we use the equation derived in the original solution to apply these principles.
Importance of Chemical Analysis
Chemical analysis involves determining the constituents or composition of a substance.
In the context of cytochrome C, chemical analysis helps determine not only the percentage of iron but also its molecular weight and other crucial parameters. Methods like spectrometry can precisely measure the proportions of various compounds in a sample.
For students learning about chemical analysis, it's important to understand that these procedures help scientists and researchers to delve deeper into the properties and functions of various molecules.
  • It provides insights into the elements a molecule is comprised of and in what ratios.
  • It aids in understanding how these molecular characteristics influence overall chemical behavior.
By exploring the molecular composition, chemical analysis can solve mysteries about complex biological processes and assist in the design of pharmaceuticals and new materials.

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Most popular questions from this chapter

At \(\mathrm{pH}\) values of 4 to 9 , natural amino acids exist as polar or zwitter ions: \(\mathrm{H}_{2} \mathrm{~N}^{+} \mathrm{CHZCO}^{-}{ }_{2}\). At a pH of 12 , what would be the predominant ionic type? What would it be at a \(\mathrm{pH}\) of 2? Can the uncharged molecular form, \(\mathrm{H}_{2} \mathrm{NCHZCO}_{2} \mathrm{H}\) ever predominate at any \(\mathrm{pH}\) ?

A chemist has an \(\mathrm{E}\). coli bacterium cell of cylindrical shape. It is \(2 \mu\) (microns) long and ly in diameter and weighs \(2 \times 10^{-12} \mathrm{~g}\). (a) How many lipid molecules are present, assuming their average molecular weight to be 700 and lipid content to be \(2 \%\) ? (b) If the cell contains 15,000 ribosomes, what percent of the volume do they occupy? You may assume them to be spherical with a diameter of \(180 \AA\); also \(10_{4} \AA=1\) micron.

Paper electrophoresis at \(\mathrm{pH} 6.0\) was carried out on a mixture of glycine, alanine, glutamic acid, lysine, arginine and serine, (a) Which compound moved toward the anode? (b) Which moved toward the cathode? (c) Which remained at the origin?

A student wanted to produce a sample of lactic acid. He carried out the following synthesis: \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{H} \rightarrow\) \(\mathrm{CH}_{3} \mathrm{CHCICO}_{2} \mathrm{H} \rightarrow \mathrm{CH}_{3} \mathrm{CHOHCO}_{2} \mathrm{H}\). He obtained a product that appeared to be lactic acid, and yet, it was optically inactive. Does this mean the product was not truly lactic acid?

A sample of polymer contains \(0.50\) mole fraction with molecular weight 100,000 and \(0.50\) mole fraction with molecular weight 200,000 . Calculate (a) the number average molecular weight, \(\mathrm{M}_{\mathrm{n}}\) and (b) the weight average molecular weight, \(\mathrm{M}_{\mathrm{w}}\).

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