Chapter 22: Problem 800
In the Citric Acid Cycle (also known as the Krebs Cycle), citrate is converted to isocitrate. From the algebraic sign of \(\Delta \mathrm{G}^{\circ}\) for the isomerization, what is the favored or spontaneous direction of the reaction? Calculate \(\Delta \mathrm{G}^{\circ}\) for the following reaction and explain what bearing this reaction will have on the isomerization of citrate and the operation of the Krebs Cycle: Isocitrate \(^{3-}+(1 / 2) \mathrm{O}_{2}(\mathrm{~g})+\mathrm{H}^{\mathrm{f}} \rightleftarrows\) a ketoglutarate \(^{2-}+\mathrm{H}_{2} \mathrm{O}(\ell)+\) (g) \(\Delta \mathrm{G}_{\mathrm{f}}\) in \((\mathrm{Kcal} / \mathrm{mole})\) are for citrate \({ }^{3-}=-279.24\); \(\mathrm{CO}_{2}(\mathrm{~g}\) isocitrate \(^{3-}=-277.65 ; \mathrm{H}^{\mathrm{f}}=0, \mathrm{O}_{2}=0\) \(\alpha\) -ketoglutarate \(^{2-}=-190.62 ; \mathrm{H}_{2} \mathrm{O}(\ell)=-56.69\) \(\mathrm{CO}_{2}(\mathrm{~g})=-94.26\)
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