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Show how Le Chatelier's principle for oxidation-reduction reactions corresponds to the Nernst equation.

Short Answer

Expert verified
Le Chatelier's principle corresponds to the Nernst equation for oxidation-reduction reactions, as both predict the system's response when there is a disturbance in the equilibrium conditions. Using a simple redox reaction as an example, an increase in the concentration of \(Cu^{2+}\) ions causes the system to shift in the forward direction according to Le Chatelier's principle. This corresponds with the Nernst equation, as the decrease in the reaction quotient (\(Q\)) caused by the increased \(Cu^{2+}\) concentration leads to an increase in cell potential (\(E\)), favoring the forward direction of the reaction.

Step by step solution

01

Understand Le Chatelier's Principle

Le Chatelier's principle states that when a system at equilibrium is subjected to a disturbance (such as a change in concentration, pressure, or temperature), the system will react to minimize the effect of that disturbance and reestablish equilibrium. Specifically, the system will shift the position of the equilibrium in the direction that counteracts the disturbance.
02

Review the Nernst Equation

The Nernst equation is used to calculate the reduction potential of a redox reaction at non-standard conditions. The Nernst equation is as follows: \(E = E^{\circ} - \frac{RT}{nF} \ln Q\) where \(E\) is the cell potential, \(E^{\circ}\) is the standard cell potential, \(R\) is the gas constant, \(T\) is the temperature in Kelvin, \(n\) is the number of moles of electrons transferred in the redox reaction, \(F\) is the Faraday constant, and \(Q\) is the reaction quotient.
03

Connect Le Chatelier's Principle and the Nernst Equation

To demonstrate how Le Chatelier's principle corresponds to the Nernst equation, let's analyze a simple redox reaction: \(Zn(s) + Cu^{2+}(aq) \rightarrow Zn^{2+}(aq) + Cu(s)\) Now, imagine that the concentration of \(Cu^{2+}\) ions is increased. According to Le Chatelier's principle, the system will react to minimize the effect of this disturbance. In this case, the reaction will proceed towards the right (forward direction), in order to consume the excess \(Cu^{2+}\) ions and reestablish equilibrium. The reaction quotient (\(Q\)) for the given redox reaction can be expressed as: \(Q = \frac{[Zn^{2+}]}{[Cu^{2+}]}\) Now, consider the Nernst equation: \(E = E^{\circ} - \frac{RT}{nF} \ln Q\) When the concentration of \(Cu^{2+}\) ions is increased, \(Q\) will decrease, since it is inversely proportional to the concentration of \(Cu^{2+}\). Using the Nernst equation, it can be observed that when \(Q\) decreases, the cell potential (\(E\)) will increase. At a higher cell potential, the reaction will proceed in the forward direction, consuming the excess \(Cu^{2+}\) ions, which is in agreement with Le Chatelier's principle. Thus, Le Chatelier's principle is shown to correspond to the Nernst equation for oxidation-reduction reactions, as both predict the system's response when there is a disturbance in the equilibrium conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nernst Equation
The Nernst equation is a powerful tool that allows us to calculate the cell potential for a redox reaction under non-standard conditions. It's particularly useful because reactions in the real world often differ from those found in textbook examples at standard conditions. The Nernst equation is given by:\[E = E^{\circ} - \frac{RT}{nF} \ln Q\]Here, \(E\) represents the actual cell potential, and \(E^{\circ}\) is the standard cell potential. Factors like the gas constant \(R\), temperature \(T\) in Kelvin, the number of moles of electrons transferred \(n\), and the Faraday constant \(F\) all play a part, as does \(Q\), the reaction quotient.
  • Understanding how the reaction quotient \(Q\) affects the equation helps in predicting reaction behavior under various conditions.
  • When conditions deviate from the standard state (such as changes in ion concentration), the effect can be calculated using the Nernst equation, showing a direct application of Le Chatelier's principle.
By using the Nernst equation, scientists can determine how changes in concentration can impact cell potential and drive reactions forward or backward.
Oxidation-Reduction Reactions
Oxidation-reduction reactions, or redox reactions, are chemical processes that involve the transfer of electrons between substances. In these reactions, one reactant gains electrons (reduction), and another loses electrons (oxidation). This complementary process keeps the electron count balanced as one substance's loss is another's gain.
  • Oxidation is the loss of electrons and can be remembered by the mnemonic "OIL" (Oxidation Is Loss).
  • Reduction, on the other hand, is the gain of electrons, often memorized as "RIG" (Reduction Is Gain).
Redox reactions are fundamental to many processes, including cellular respiration and photosynthesis. They're also vital in electrochemical cells, where electrical energy is produced through redox activities. Understanding the flow of electrons and tracking these gains and losses form the basis of utilizing the Nernst equation.
Equilibrium
In chemistry, equilibrium occurs when the forward and reverse reactions of a chemical process happen at the same rate, leading to no net change in the concentration of reactants and products. Le Chatelier's principle gives valuable insight into how systems at equilibrium respond to disturbances. When a reaction is at equilibrium and an external change like concentration, temperature, or pressure is introduced, the system will adjust itself to counter the effect of that disturbance and achieve a new equilibrium.
  • If we increase the concentration of a reactant, the system shifts to consume that reactant, progressing in the forward reaction direction.
  • Conversely, if we decrease the concentration, the reaction will shift to produce more of that reactant.
Le Chatelier's principle, in essence, ensures that systems tend to balance changes to minimize their impact. This principle parallels with the adaptive nature of the Nernst equation, as both predict changes in behavior under altered conditions.
Cell Potential
Cell potential, or electromotive force (emf), is a measure of the potential difference between two electrodes in an electrochemical cell. It indicates the ability of the cell to push electrons through a circuit, providing electrical energy derived from chemical reactions.The standard cell potential \(E^{\circ}\) is measured under standardized conditions, typically with reactants at 1 M concentration and 25 degrees Celsius. Deviations from these conditions require the use of the Nernst equation to calculate the actual cell potential.
  • A positive cell potential indicates a spontaneous reaction, meaning the reaction can do work.
  • A negative cell potential suggests the reaction is non-spontaneous, requiring input energy to proceed.
Understanding cell potential is crucial in the design and functionality of batteries, where chemical energy is converted into electrical energy. The interplay between cell potential and Nernst equation calculations ensures that systems operate efficiently despite variable conditions, adhering to principles like those of Le Chatelier.

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Most popular questions from this chapter

Given \(\mathrm{Zn} \rightarrow \mathrm{Zn}^{+2}+2 \mathrm{e}^{-}\) with \(\mathrm{E}^{\circ}=+.763\), calculate \(\mathrm{E}\) for a Zn electrode in which \(\mathrm{Zn}^{+2}=.025 \mathrm{M}\)

The standard \(\mathrm{E}^{\circ}\) for \((1 / 2) \mathrm{F}_{2}(\mathrm{~g})+\mathrm{e}^{-} \rightarrow \mathrm{F}^{-}(\mathrm{aq})\), which is \(+2.87 \mathrm{~V}\), applies when the flouride ion concentration is \(1 \mathrm{M}\). What would the corresponding \(\mathrm{E}\) be in \(1 \mathrm{M} \mathrm{H}_{3} \mathrm{O}^{+}\), i.e., for the electrode reaction \((1 / 2) \mathrm{F}_{2}(\mathrm{~g})+\mathrm{e}^{-}+\mathrm{H}_{3} \mathrm{O}^{+} \rightarrow \mathrm{HF}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O} ?\) (The \(\mathrm{K}_{\text {diss }}\) of HF is \(6.7 \times 10^{-4}\) ).

Two electrolytic cells were placed in series. One was composed of \(\mathrm{AgNO}_{3}\) and the other of \(\mathrm{CuSO}_{4}\). Electricity was passed through the cells until \(1.273 \mathrm{~g}\) of \(\mathrm{Ag}\) had been deposited. How much copper was deposited at the same time?

A voltaic cell is made up of a silver electrode in a \(1 \mathrm{M}\) silver nitrate solution and an aluminum electrode in a \(1 \mathrm{M}\) aluminum nitrate solution. The half reactions are 1) \(\mathrm{Ag}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}\) (s) \(\mathrm{E}^{\circ}=.80\) volt, and (2) \(\mathrm{Al}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Al}(\mathrm{s})\) \(E^{\circ}=-1.66\) volt, calculate the standard free energy change, \(\Delta \mathrm{G}^{\circ}\), in \(\mathrm{Kcal} /\) mole. \(1 \mathrm{cal}=4.184\) joule \(1 \mathrm{~F}=96,500\) coul, \(1 \mathrm{Kcal}=1000 \mathrm{cal}\)

Calculate the voltage (E) of a cell with \(\mathrm{E}^{\circ}=1.1\) volts, If the copper half-cell is at standard conditions but the zinc ion concentration is only \(.001\) molar. Temperature is \(25^{\circ} \mathrm{c}\). The overall reaction is \(\mathrm{Zn}+\mathrm{Cu}^{+2} \rightarrow \mathrm{Cu}+\mathrm{Zn}^{+2}\)

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