Chapter 10: Problem 384
A saturated solution of the strong electrolyte \(\mathrm{Ca}(\mathrm{OH})_{2}\) is prepared by adding sufficient water to \(5.0 \times 10^{-4}\) mole of \(\mathrm{Ca}(\mathrm{OH})_{2}\) to form \(100 \mathrm{ml}\) of solution. What is the \(\mathrm{pH}\) of this solution?
Short Answer
Expert verified
The pH of the saturated Ca(OH)₂ solution is approximately 12.
Step by step solution
01
Calculate the initial concentration of Ca(OH)₂ in the solution.
We are given the amount (mole) of Ca(OH)₂ in the solution, which is 5.0 x 10⁻⁴ mole. The volume of the solution is 100 ml. First, we convert the volume to liters:
\(100 \mathrm{ml} \times \frac{1\ \mathrm{L}}{1000\ \mathrm{ml}} = 0.1\ \mathrm{L}\)
Now, we can calculate the initial concentration of Ca(OH)₂ in the solution:
\[\frac{5.0 \times 10^{-4}\ \text{mole}}{0.1\ \mathrm{L}} = 0.005\ \text{M}\]
02
Determine the hydroxide ion concentration from the dissociation of Ca(OH)₂.
Ca(OH)₂ is a strong electrolyte, and it dissociates completely when it dissolves in water:
\(\mathrm{Ca(OH)_2\ \to\ Ca^{2+} + 2\ OH^{-}}\)
Each mole of Ca(OH)₂ dissociates into 2 moles of hydroxide ions. Therefore, the hydroxide ion concentration in the solution is double the initial concentration of Ca(OH)₂:
\(0.005\ \mathrm{M} \times 2= 0.01\ \mathrm{M}\)
03
Calculate the pOH of the solution from the hydroxide ion concentration.
We can now calculate the pOH of the solution using the relationship:
\[\mathrm{pOH} = - \log_{10}[OH^{-}]\]
We plug in the hydroxide ion concentration we found in step 2:
\(\mathrm{pOH} = - \log_{10}(0.01\ \mathrm{M})\)
By calculating:
\(\mathrm{pOH} \approx 2\)
04
Calculate the pH of the solution using the relationship between pH and pOH.
We can find the pH of the solution using the relationship:
\(\mathrm{pH} + \mathrm{pOH} = 14\)
From step 3, we know that the pOH is approximately 2. Therefore, we can find the pH of the solution:
\(\mathrm{pH} = 14 - \mathrm{pOH}\)
\(\mathrm{pH} = 14 - 2\)
\(\mathrm{pH} = 12\)
#Conclusion#
The pH of the saturated Ca(OH)₂ solution is approximately 12.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Saturated Solution
A saturated solution is one in which the maximum amount of a solute has been dissolved in a solvent at a given temperature and pressure. Once a solution reaches saturation, any additional solute will not dissolve. Instead, it will remain as another phase, typically as a solid.
For calcium hydroxide, Ca(OH)₂, this means that the solution contains the maximum concentration of Ca(OH)₂ that can dissolve. If more Ca(OH)₂ is added beyond this point, it will remain undissolved.
For calcium hydroxide, Ca(OH)₂, this means that the solution contains the maximum concentration of Ca(OH)₂ that can dissolve. If more Ca(OH)₂ is added beyond this point, it will remain undissolved.
- Saturation depends on temperature - more solute can usually dissolve at higher temperatures.
- The concept of saturation is crucial for calculating solute concentrations in solutions.
Strong Electrolyte
Strong electrolytes are substances that completely dissociate into ions when dissolved in water. This means that they split into their constituent ions, which are then free to move in the solution.
In the case of Ca(OH)₂, it fully dissociates into Ca²⁺ and OH⁻ ions. This complete dissociation is what makes it a strong electrolyte. Complete dissociation ensures that no intact Ca(OH)₂ molecules remain in the solution.
In the case of Ca(OH)₂, it fully dissociates into Ca²⁺ and OH⁻ ions. This complete dissociation is what makes it a strong electrolyte. Complete dissociation ensures that no intact Ca(OH)₂ molecules remain in the solution.
- Strong acids, strong bases, and most salts are strong electrolytes.
- The presence of free ions makes these solutions excellent conductors of electricity.
Hydroxide Ion Concentration
The hydroxide ion concentration is a critical factor in determining the basicity of a solution. For basic solutions, hydroxide ions (
OH⁻
) are present in higher concentrations.
For example, in our calculation, Ca(OH)₂ dissociates completely, producing two OH⁻ ions for every formula unit dissolved. As a result, the hydroxide ion concentration is twice the initial molarity of Ca(OH)₂.
For example, in our calculation, Ca(OH)₂ dissociates completely, producing two OH⁻ ions for every formula unit dissolved. As a result, the hydroxide ion concentration is twice the initial molarity of Ca(OH)₂.
- The concentration of hydroxide ions determines the solution's pOH, a direct measure of basicity.
- It is important to understand the role of dissociation in calculating ion concentration.
Dissociation
Dissociation is the process by which compounds split into their ions in solution. This is especially crucial for understanding reactions in aqueous environments and the behavior of strong electrolytes.
For strong electrolytes like Ca(OH)₂, this process is complete, meaning the solute completely dissociates into its Ca²⁺ and OH⁻ components. This full breakdown is pivotal in calculations of ion concentrations.
For strong electrolytes like Ca(OH)₂, this process is complete, meaning the solute completely dissociates into its Ca²⁺ and OH⁻ components. This full breakdown is pivotal in calculations of ion concentrations.
- Dissociation allows the calculation of individual ion concentrations.
- The extent of dissociation can be different depending on whether the compound is a strong or weak electrolyte.
pOH
The pOH of a solution offers a measure of its basicity, much like pH measures acidity. It's calculated using the concentration of hydroxide ions present in the solution.
Given a strong base like Ca(OH)₂, once you know the hydroxide ion concentration (in our case, 0.01 M), you can find the pOH using the formula: \[\text{pOH} = -\log_{10}[OH^-]\]This value provides insight into how the solution compares to neutral solutions (which have a pOH of about 7).
Given a strong base like Ca(OH)₂, once you know the hydroxide ion concentration (in our case, 0.01 M), you can find the pOH using the formula: \[\text{pOH} = -\log_{10}[OH^-]\]This value provides insight into how the solution compares to neutral solutions (which have a pOH of about 7).
- pOH is inversely related to pH, where \(\text{pH + pOH} = 14\).
- Knowing the pOH is essential for creating a comprehensive understanding of a solution's properties.