Chapter 22: Problem 1
Methyl red, HMR is a common acid-base indicator. In solution it ionizes according to the equation: $$ \begin{array}{c} \mathrm{HMR}(\mathrm{aq}) \rightleftarrows \mathrm{H}^{+}(\mathrm{aq})+\mathrm{MR}^{-}(\mathrm{aq}) \\ \mathrm{red} \end{array} $$ If methyl red is added to distilled water, the solution turns yellow. If a drop or two of \(6 \mathrm{M}\) HCl is added to the yellow solution, it turns red. If to that solution one adds a few drops of \(6 \mathrm{M} \mathrm{NaOH}\) the color reverts to yellow. a. Why does adding \(6 \mathrm{M}\) HCl to the yellow solution of methyl red tend to cause the color to change to red? (Note that in solution HCl exists as \(\mathrm{H}^{+}\) and \(\mathrm{Cl}\) - ions.) b. Why does adding \(6\quad \mathrm{M}\quad \mathrm{NaOH}\) to the red solution tend to make it turn back to yellow? (Note that in solution NaOH exists as \(\mathrm{Na}^{+}\) and \(\mathrm{OH}^{-}\) ions. How does increasing \(\left[\mathrm{OH}^{-}\right]\) shift Reaction 3 in the discussion section? How would the resulting change in \(\left[\mathrm{H}^{+}\right]\) affect the dissociation reaction of HMR?)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.