Question

Assign oxidation states to all atoms in each compound.

$\begin{array}{l}\mathbf{a}\mathbf{.}{\mathbf{KMnO}}_4\\ \mathbf{b}\mathbf{.}{\mathbf{NiO}}_2\\ \mathbf{c}\mathbf{.}{\mathbf{K}}_4\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]\left(\mathrm{Fe}\mathrm{only}\right)\\ \mathbf{d}\mathbf{.}{\left({\mathrm{NH}}_4\right)}_2{\mathbf{HPO}}_4\\ \mathbf{e}\mathbf{.}{\mathbf{P}}_4{\mathbf{O}}_6\\ \mathbf{f}\mathbf{.}{\mathbf{Fe}}_3{\mathbf{O}}_4\\ \mathbf{g}\mathbf{.}{\mathbf{XeOF}}_4\\ \mathbf{h}\mathbf{.}{\mathbf{SF}}_4\\ \mathbf{i}\mathbf{.}\mathbf{CO}\\ \mathbf{j}\mathbf{.}{\mathbf{C}}_6{\mathbf{H}}_{12}{\mathbf{O}}_6\end{array}$

Short answer

Oxidation state to each atom in the given molecules is assigned.

Step-by-step solution

Introduction

The oxidation state of an atom indicates the charge attained by the atom during the formation of the associated compound.

Subpart a)

The oxidation state of each atom in the given compound is as shown below:

$\begin{array}{l}KMn{O}_4\\ \begin{array}{ccc}K& Mn& O\\ +1& +7& -1\end{array}\end{array}$

Subpart b)

The oxidation state of each atom in the given compound is as shown below:

$\begin{array}{l}Ni{O}_2\\ NiO\\ +4-4\end{array}$

Subpart c)

The oxidation state of each atom in the given compound is as shown below:

$\begin{array}{l}{K}_4\left[Fe{\left(CN\right)}_6\right]\\ Fe:+2\end{array}$

Subpart d)

The oxidation state of each atom in the given compound is as shown below:

$\begin{array}{l}{\left(N{H}_4\right)}_{2}HP{O}_4\\ NHPO\\ -3+1+5-2\end{array}$

Subpart e)

The oxidation state of each atom in the given compound is as shown below:

$\begin{array}{l}{P}_4{O}_6\\ PO\\ +3-2\end{array}$

Subpart f)

The oxidation state of each atom in the given compound is as shown below:

$\begin{array}{l}F{e}_3{O}_4\\ FeO\\ +2,+3-2\end{array}$

Subpart g)

The oxidation state of each atom in the given compound is as shown below:

$\begin{array}{l}XeO{F}_4\\ XeOF\\ +6-2-1\end{array}$

Subpart h)

The oxidation state of each atom in the given compound is as shown below:

$\begin{array}{l}S{F}_4\\ SF\\ +4-1\end{array}$

Subpart i)

The oxidation state of each atom in the given compound is as shown below:

$\begin{array}{l}CO\\ CO\\ +2-2\end{array}$

Subpart j)

The oxidation state of each atom in the given compound is as shown below:

$\begin{array}{l}{C}_6{H}_{12}{O}_6\\ CHO\\ 0+1-2\end{array}$