Question

Which of the following solutions of strong electrolytes contains the largest number of moles of chloride ions: 100.0 mL of 0.30 M $AlC{l}_3$, 50.0 mL of 0.60 M $MgC{l}_2$, or 200.0 mL of 0.40 M $NaCl$?

Short answer

100.0 mL of 0.30 M $AlC{l}_3$solution of strong electrolytes contains thelargest number of moles ofchloride ions.

Step-by-step solution

Definition

The molar mass of a material is defined as the mass of the substance contained in one mole of the substance, and it is equal to the total mass of the component atoms. It may be stated mathematically as follows:

$Molarmass=\frac{Weighting}{numberofmoles}$

Determination of number of moles of AlCl3 and MgCl2

Number of moles of $$\begin{gathered} AlC{l}_3=\left(0.30M\right)\left(100.0\times {10}^{-3}L\right) \\ =0.03moles \end{gathered}$$

$AlC{l}_3\to Al+3C{l}^{-}$

So, 1 moles of $AlC{l}_3=$3 moles of $C{l}^{-}$

1 moles of $$\begin{gathered} C{l}^{-}=3\left(0.03\right) \\ =0.09Moles \end{gathered}$$

Number of moles of role="math" localid="1650279759911" $$\begin{gathered} MgC{l}_2=\left(0.60M\right)\left(50.0\times {10}^{-3}L\right) \\ =0.03moles \end{gathered}$$

$MgC{l}_2\to M{g}^{2+}+2C{l}^{-}$

Number of moles of$$\begin{gathered} C{l}^{-}=2\left(0.03\right) \\ =0.06Moles \end{gathered}$$

Determination of number of moles of NaCl

Number of moles of $$\begin{gathered} NaCl=\left(0.40\right)\left(0.200\right) \\ =0.08moles \end{gathered}$$

$NaCl\to N{a}^{+}+C{l}^{-}$

Number of moles of $C{l}^{-}=0.08moles$

Therefore $AlC{l}_3$have more number of moles of$C{l}^{-}$ ions.