Question

If 10.g of $AgN{O}_3$ is available, what volume of 0.25 M$AgN{O}_3$ solution can be prepared?

Short answer

The volume of 0.25 M$AgN{O}_3$solution can be prepared is $0.24L$.

Step-by-step solution

Definition

A solution's molarity is a concept that refers to the amount of solute contained in one litre of the solution. It may be stated mathematically as follows:

$Molarity=\frac{molesofsolute}{volumeofsolutioninliter}$

Determination of volume of the solution

From the given,

The mass of $AgN{O}_3=10.0g$

Moles of role="math" localid="1650278713300" $$\begin{gathered} AgN{O}_3=\frac{10.00g}{167.87{\displaystyle \raisebox{1ex}{$g$}\!\left/ \!\raisebox{-1ex}{$mol$}\right.}} \\ =0.059mol \end{gathered}$$

Let us find the volume of solution,

$$\begin{gathered} V=\frac{0.059mol}{0.25M} \\ V=0.24L \end{gathered}$$

Therefore thevolume of the solution is $0.24L$.