Question

Give an example of how each of the following insoluble ionic compounds could be produced using a precipitation reaction. Write the balanced molecular equation.

$$\begin{gathered} a.F_e{\left(OH\right)}_{3\left(S\right)} \\ b.{H_g}_{2}C{1}_{2\left(S\right)} \\ c.PbS{O}_{4\left(S\right)} \\ d.BaCr{O}_{4\left(S\right)} \end{gathered}$$

Short answer

Answer:

$$\begin{gathered} a.3NaOH\left(aq\right)+Fe{\left(N{O}_3\right)}_3\left(aq\right)\to 3NaN{O}_3\left(aq\right)+Fe{\left(OH\right)}_3\downarrow \\ b.2HgN{O}_3\left(a2q\right)+2KC1\left(aq\right)\to H{g}_{2}C{1}_2\left(aq\right)+2KN{O}_3\left(aq\right) \\ c.N{a}_{2}S{O}_4\left(aq\right)+Pb{\left(N{O}_3\right)}_2\left(aq\right)\to 2NaN{O}_3\left(aq\right)+PbS{O}_4\left(s\right)\downarrow \\ d.K_{2}Cr{O}_4\left(aq\right)+Ba{\left(N{O}_3\right)}_2\left(aq\right)\to 2KN{O}_3\left(aq\right)+BaCr{O}_4\left(s\right)\downarrow \end{gathered}$$

Step-by-step solution

Definition of balanced equation

An equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products is defined as balanced equation

Molecular equation

a. Molecular equation for $F_e{\left(OH\right)}_{3\left(S\right)}$ precipitate

$3NaOH\left(aq\right)+Fe{\left(N{O}_3\right)}_3\left(aq\right)\to 3NaN{O}_3\left(aq\right)+Fe{\left(OH\right)}_3\downarrow$

b. Molecular equation for ${H_g}_{2}C{1}_{2\left(S\right)}$ precipitate

$2HgN{O}_3\left(a2q\right)+2KC1\left(aq\right)\to H{g}_{2}C{1}_2\left(aq\right)+2KN{O}_3\left(aq\right)$

c. Molecular equation for $PbS{O}_{4\left(S\right)}$ precipitate

$N{a}_{2}S{O}_4\left(aq\right)+Pb{\left(N{O}_3\right)}_2\left(aq\right)\to 2NaN{O}_3\left(aq\right)+PbS{O}_4\left(s\right)\downarrow$

d. Molecular equation for $BaCr{O}_{4\left(S\right)}$precipitate

$K_{2}Cr{O}_4\left(aq\right)+Ba{\left(N{O}_3\right)}_2\left(aq\right)\to 2KN{O}_3\left(aq\right)+BaCr{O}_4\left(s\right)\downarrow$