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Which of the following ions is(are) expected to form colored

octahedral aqueous complex ions?

a. Zn2+

b. Cu2+

c. Mn3+

d. Ti4+

Short Answer

Expert verified
  1. No color
  2. Colored
  3. Colored
  4. No Color.

Step by step solution

01

Determine whether Zn2+ will form colored octahedral aqueous complex ions.

The electron configuration of Zn2+will be [Ar] 3d10. We can see that the d orbital is completely filled. Hence, Zn2+will form colored octahedral aqueous complex ions.

02

Determine whether Cu2+ will form colored octahedral aqueous complex ions.

The electron configuration of Cu2+will be [Ar] 3d9. We can see that the d orbital is not completely filled. Hence, Cu2+will not form colored octahedral aqueous complex ions.

03

Determine whether Mn3+ will form colored octahedral aqueous complex ions.

The electron configuration of Mn3+will be [Ar] 3d4. We can see that the d orbital is not completely filled. Hence, Mn3+will not form colored octahedral aqueous complex ions.

04

Determine whether Ti4+ will form colored octahedral aqueous complex ions.

The electron configuration of Ti4+will be [Ar] 3d0. We can see that the d orbital does not have any electrons. Hence, Ti4+will not form colored octahedral aqueous complex ions

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