Question

For the process $\mathbf{Co}\mathbf{(}{\mathbf{NH}}_{\mathbf{3}}{\mathbf{)}}_{\mathbf{5}}{\mathbf{Cl}}^{\mathbf{2}\mathbf{+}}\mathbf{+}{\mathbf{Cl}}^{\mathbf{-}}\mathbf{\to }\mathbf{Co}\mathbf{(}{\mathbf{NH}}_{\mathbf{3}}{\mathbf{)}}_{\mathbf{4}}\mathbf{C}{{\mathbf{l}}_{\mathbf{2}}}^{\mathbf{+}}\mathbf{+}{\mathbf{NH}}_{\mathbf{3}}$. What would be the expected ratio of cis to trans isomers in the product?

Short answer

Depends on the possible geometrical isomers of the product.$\mathrm{Cis}:\mathrm{Trans}=4:1$

Step-by-step solution

Description

Octahedral displacement reaction takes place in which ammonia is departed by attacking nucleophile chloride ion.

 Possible geometrical isomers

All Cis (4 isomers)

Trans isomer