Question

Consider element $\mathbf{113}$. What is the expected electron configuration for element$\mathbf{113}$? What oxidation states would be exhibited by element$\mathbf{113}$in its compounds?

Short answer

The expected electron configuration for element$113$ is $\left[Rn\right]5f^{14}6d^{10}7s^{2}7p^1$.

The oxidation states would be exhibited by element$113$ in its compound is$+1$ and $+3$.

Step-by-step solution

Definition of oxidation

The loss of electrons or a rise in the oxidation state of an elementis referred to as oxidation.

Find the expected electron configuration for element 113 and oxidation states

• Nihonium is an atomic number element. It belongs to period$7$ and group $3A$. (boron group).
• Electron configuration of nihonium is $\left[\text{Rn}\right]5f^{14}6d^{10}\mathbf{7}{\mathbf{s}}^2\mathbf{7}{\mathbf{p}}^1$.
• The electron configuration of nihonium can be used to forecast the oxidation states that it will display in its compounds.
• Because of its electron configuration, nihonium may take on the$+1$ and$+3$ oxidation states in its compounds.
• The former occurs when only one p electron is involved in bonding, whereas the later occurs when all three valence electrons are involved, two in the s-subshell and one in the p-subshell.
• Although some predictions imply that nihonium can take on the oxidation states$-1$ and $+5$, the most prevalent oxidation states are$+1$ and $+3$.