Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Consider the following information:

i. The layer of dead skin on our bodies is sufficient to protect us from most -particle radiation.

ii. Plutonium is an α-particle producer.

iii. The chemistry Pu4+of is similar to that of Fe3+.

iv. Pu oxidizes readily toPu4+.

Why is plutonium one of the most toxic substances known?

Short Answer

Expert verified

Plutonium is oxidized by Pu4+and concentrates whereFe3+ is abundant and can cause damage.

Step by step solution

01

Plutonium.

Plutonium, with the symbol Pu and atomic number 94, is a radioactive chemical element. It's a silvery gray “actinide metal” that tarnishes in the air and forms a dull covering when oxidized.

02

Plutonium is one of the most toxic substances.

The layer of dead skin is known to protect against alpha particles. As a result, propositions (i) and (ii) imply that plutonium does not pose a hazard to the body's outer layer.

When it is swallowed or enters the body, however, it becomes harmful, because given statements (iii) and (iv), Pu4+that oxidize Pu will clump together where Fe3+is most concentrated. These alpha particles can cause harm to the human body.

03

Pu4+concentrates on areas.

Plutonium is one of the most poisonous elements.

Because plutonium is oxidized by Pu4+and concentrates whereFe3+ is abundant, it is regarded as one of the most dangerous chemicals. It can thus target regions and cause damage in the body rich in iron (III), such as the bone marrow.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Phosphorus-32 is a commonly used radioactive nuclide in

biochemical research, particularly in studies of nucleic acids. The half-life of phosphorus-32 is 14.3 days. What mass of phosphorus-32 is left from an original sample of 175mg of Na3 32 PO4 after 35.0 days? Assume that the atomic mass of 32P is 32.0 u.

A chemist wishing to do an experiment requiringCa2+47(half-life =4.5 days) needs 5.0μgof the nuclide. What mass of CaCO347must be ordered if it takes 48 h for delivery from the supplier? Assume that the atomic mass of47Ca is 47.0 u.

Using the kinetic molecular theory (Section 5.6), calculate the root mean square velocity and the average kinetic energy of H12 nuclei at a temperature of4×107K (See Exercise 43 for the appropriate mass values.)

The mass ratios oftocan also be used to date geological materials. Potassium- 40 decays by two processes:

K1940+-10e1840Ar(10.7%)t1/2=1.27×109yr1940K2040Ca+-10e(89.3%)

a. Why areAr40/40Kratios rather thanCa40/40Kratios used to date materials?

b. What assumptions must be made in using this technique?

c. A sedimentary rock has aAr40/40Kratio of 0.95. Calculate the age of the rock.

d. How will the measured age of a rock compare with the actual age if someAr40has escaped from the sample?

Much of the research on controlled fusion focuses on the problem of how to contain the reacting material. Magnetic fields appear to be the most promising mode of containment. Why is containment such a problem? Why must one resort to magnetic fields for containment?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free